正在从谷歌地图请求解析城市/州

Parsing city/state from Google Maps request

本文关键字:城市 请求 谷歌地图      更新时间:2023-09-26
var geocoder = new google.maps.Geocoder();
            geocoder.geocode({'latLng': foundLoc}, function(results, status) {
                if (status == google.maps.GeocoderStatus.OK) {
                    if (results[1]) {
                        var loc = getCityState(results);
                    }
                }
            }); 
function getCityState(results)
        {
            var citystateArray = results[1].formatted_address.split(",",2);
            var city = citystateArray[0];
            var state = citystateArray[1].substring(1, 3);
            return (city + ', ' + state)
        }

这就是我现在使用的,大约90%的时间都是这样。有时,formatted_address包含一个城镇和一个城市以及州,有时只是城镇和城市,有时是你能梦想的一切。

我还没有找到一种始终从谷歌地图API结果中获取城市/州的一致方法。你们有人有吗?谢谢

谷歌在其页面上使用的一个响应示例:

{
  "status": "OK",
  "results": [ {
    "types": [ "street_address" ],
    "formatted_address": "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
    "address_components": [ {
      "long_name": "1600",
      "short_name": "1600",
      "types": [ "street_number" ]
    }, {
      "long_name": "Amphitheatre Pkwy",
      "short_name": "Amphitheatre Pkwy",
      "types": [ "route" ]
    }, {
      "long_name": "Mountain View",
      "short_name": "Mountain View",
      "types": [ "locality", "political" ]
    }, {
      "long_name": "California",
      "short_name": "CA",
      "types": [ "administrative_area_level_1", "political" ]
    }, {
      "long_name": "United States",
      "short_name": "US",
      "types": [ "country", "political" ]
    }, {
      "long_name": "94043",
      "short_name": "94043",
      "types": [ "postal_code" ]
    } ],
    "geometry": {
      "location": {
        "lat": 37.4219720,
        "lng": -122.0841430
      },
      "location_type": "ROOFTOP",
      "viewport": {
        "southwest": {
          "lat": 37.4188244,
          "lng": -122.0872906
        },
        "northeast": {
          "lat": 37.4251196,
          "lng": -122.0809954
        }
      }
    }
  } ]
}

有时这些字段没有值,有时有值。

为什么解析formatted_address

有address_components,您可以浏览它们并查找具有的

"types": [ "administrative_area_level_1", "political" ]// the state
"types" : [ "locality", "political" ]//the city

以下是一个示例:http://jsfiddle.net/doktormolle/QWPCL/

到目前为止,这似乎对我有效。。。

  readCityAndStateFromResult: (data) ->
    displayName = []
    for component in data[0].address_components
      if component.types and component.types.length
        switch true
          when 'locality' in component.types
            displayName.push component.long_name
          when 'administrative_area_level_1' in component.types or 'administrative_area_level_2' in component.types
            displayName.push component.short_name
    return displayName.join ', ' if displayName.length
    return null