JavaScript代码未正确检查ajax请求

JavaScript code not checking ajax request properly

本文关键字:检查 ajax 请求 代码 JavaScript      更新时间:2023-09-26

我有一个星期四的案例,我想知道为什么这不起作用。

问题:即使页面成功返回,我也无法从AJAX请求返回数组的值。

所以,这是我的AJAX请求:

    $.ajax({
    type: "GET",
    url: "get-sendgrid-info.php?username=" + emailToCheck,
        success: function(dataSG) {
            console.log("Length: " + dataSG.length + " Username: " + dataSG[0].username);
            if (dataSG[0].username) {
                console.log('CURRENTLY IN SEND GRID!');
                $(".sgstatus").html("<div style='font-weight:bold;color:green;'>CURRENTLY IN SENDGRID</div>");
            }else{
                console.log('NOT IN SEND GRID!');
                $(".sgstatus").html("<div style='font-weight:bold;color:red;'>NOT IN SENDGRID</div>");
            }
        },
        error: function(XMLHttpRequest, textStatus, errorThrown) {
            console.log(XMLHttpRequest);
            console.log(errorThrown);
        }
    });

并且CCD_ 1将调用该CCD_ 2页面:

    if ($email) echo json_encode($data);
}
$stmt->close();
$mysqli->close();

它会输出这样的东西:

Array
(
    [0] => stdClass Object
        (
            [username] => sample@email.net
            [email] => sample@email.net
            [active] => true
            [first_name] => John
            [last_name] => Doe
            [address] => 123 Fake Street
            [address2] => Suite117
            [city] => Denver
            [state] => CO
            [zip] => 12345
            [country] => US
            [phone] => 555-555-5555
            [website] => http://website.com
            [website_access] => true
        )
)
1

(是的,即使是1)。

所以,当我在AJAX请求之后尝试这个时

        if (dataSG[0].username) {
            console.log('CURRENTLY IN SEND GRID!');
            $(".sgstatus").html("<div style='font-weight:bold;color:green;'>CURRENTLY IN SENDGRID</div>");
        }else{
            console.log('NOT IN SEND GRID!');
            $(".sgstatus").html("<div style='font-weight:bold;color:red;'>NOT IN SENDGRID</div>");
        }

我总是得到NOT IN SENDGRID,即使响应中显示了一个包含用户名的数组

请帮忙?

edit:我应该添加我在IIS服务器上。

编辑:响应控制台显示:

Object {readyState: 4, getResponseHeader: function, getAllResponseHeaders: function, setRequestHeader: function, overrideMimeType: function…}abort: 
...
Object
create-email.php:2629 SyntaxError: Unexpected token A {stack: (...), message: "Unexpected token A"}message: "Unexpected token A"stack: (...)get stack: function () { [native code] }set stack: function () { [native code] }__proto__: Error

我认为原因是您的pho脚本正在回显以"Array"开头的字符串。get方法对返回对象进行了明智的猜测。当它从php接收到一个字符串时,它无法将其转换为Jason或xml,因此它认为dataSG只是字符串。Json_encode未成功执行此操作。您必须将php输出格式化为类似"[‘a’,‘b’]"的格式,然后Ajax才能成功地将其转换为JavaScript数组。

试试这个:

...
success: function(dataSG) {
    dataSG = JSON.parse(dataSG);
...