无法读取属性“父节点”

Cannot read property 'parentNode'

本文关键字:父节点 属性 读取      更新时间:2023-09-26

我开始学习javascript,我一辈子都想不通,为什么这个"无法读取属性'parentNode'"被扔到控制台中;为什么for循环在第三个链接之后调用an。

我正在学习有关javascript翻转的课程,翻转有效,但是为什么会抛出错误?

<style type="text/css" media="screen">
  #caption, #content {
    width: 30%;
    float: left;
    padding: 10%;
    line-height: 1.675em;
  }
</style>
<script type="text/javascript" charset="utf-8">
  window.onload = initRollover;
  function initRollover() {
    for (var i = 0; i < document.links.length; i++) {  
      console.log(i);  
      if(document.images[i].parentNode.tagName == "A") {
        setupRollover(document.images[i]);
      } 
      document.links[i].setAttribute('class', 'test');
    }
  }
  function setupRollover(thisImage){
    thisImage.outImage = new Image();
    thisImage.outImage.src = thisImage.src;
    thisImage.onmouseout = function() {
      this.src = this.outImage.src;
    }
    thisImage.overImage = new Image();
    thisImage.overImage.src = "images/" + "silver" + ".jpg";
    thisImage.onmouseover = function(){
      this.src = this.overImage.src;
    }
  }
</script>
<div id="content" style="background: lightgreen;">
  <img src="images/silver.jpg" width="240" alt="Silver" id="photoA">
  <br><br>
  <a href="boom.html">
    <img src="images/gold.jpg" width="240" alt="Gold" id="photoB">
  </a>
</div>
<div id="caption">
  <a href="foo.html">Lorem ipsum dolor sit amet,</a> consectetur adipisicing elit, sed do eiusmod
  tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam,
  quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo
  consequat. <a href="bar.html">Duis aute irure dolor </a>in reprehenderit in voluptate velit esse
  cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non
  proident, sunt in <a href="car.html">culpa qui officia deserunt</a> mollit anim id est laborum.
</div>
<div style="clear:both"></div>

谢谢

我不完全确定您要实现的目标。但我看到的问题就在这里

function initRollover() {
for (var i = 0; i < document.links.length; i++) {  
  console.log(i);  
  if(document.images[i].parentNode.tagName == "A") {
    setupRollover(document.images[i]);
  } 
  document.links[i].setAttribute('class', 'test');
}
}

在您的 html 代码中,有 3 个带有标签的链接,但只有 2 个带有标签的图像。所以当i = 2时,没有document.images[2]。因此,父节点为空。这会导致您的错误。

希望有帮助。