Alasql:UNION(或UNION ALL)仅给出表1的结果

Alasql: UNION (or UNION ALL) only gives results from table1

本文关键字:UNION 结果 ALL Alasql      更新时间:2023-09-26

当使用 alasql (https://github.com/agershun/alasql) 在 GROUP BY 查询中使用 UNION 或 UNION ALL 时,仅检索表 1 中的结果。

改为运行单独的查询会输出正确的结果。

看到这个 jfiddle http://jsfiddle.net/L8471bnk/116/

var data= [
{"label":"transport - car","value":800},
{"label":"airplane","value":234},
{"label":"train","value":500},
{"label":"glider","value":123},
{"label":"transport - motorbike","value":50},
{"label":"transport - bike","value":150}
];

var query1 = alasql('' +
        'SELECT ''transport'' AS label, SUM(CAST([value] AS INT)) AS [value] ' +
        'FROM ? ' +
        'WHERE label LIKE ''%transport%'' ' +
        'GROUP BY ''transport'' ' +
        '',
[data]);
 var query2 = alasql('' +
        'SELECT label, SUM(CAST([value] AS INT)) AS [value] ' +
        'FROM ? ' +
        'WHERE label NOT LIKE ''%transport%'' ' +
        'GROUP BY label' +
        '',
[data]);
var queryUnion = alasql('' +
        'SELECT ''transport'' AS label, SUM(CAST([value] AS INT)) AS [value] ' +
        'FROM ? ' +
        'WHERE label LIKE ''%transport%'' ' +
        'GROUP BY ''transport'' ' +
        'UNION ALL ' + //or UNION, same result!
        'SELECT label, SUM(CAST([value] AS INT)) AS [value] ' +
        'FROM ? ' +
        'WHERE label NOT LIKE ''%transport%'' ' +
        'GROUP BY label' +
        '',
[data, data]);

$("#res").html("<br/>UNION IS WRONG (length is correct, but query2 results are missing!!!)!<br/>" + JSON.stringify(queryUnion) + " LENGTH: " + queryUnion.length);
$("#info").html("<br/>Query1 is correct:<br/>" 
+ JSON.stringify(query1) 
+ " LENGTH: " + query1.length
+ "<br/><br/>Query2 is correct<br/>" + JSON.stringify(query2) 
+ " LENGTH: " + query2.length);

刚刚发现:好像是错误?

见 https://github.com/agershun/alasql/issues/485

:(((