如何从经纬度点获取城市名称
How can I get city name from a latitude and longitude point?
有没有一种方法可以使用javascript的谷歌地图api从纬度和经度点获取城市名称？
如果是的话，我可以看看一个例子吗？
这被称为反向地理编码
-
谷歌文档：
http://code.google.com/apis/maps/documentation/geocoding/#ReverseGeocoding.
-
谷歌地理编码Web服务示例调用：
http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224，-73.96452&传感器=真&key=YOUR_key
这是一个完整的示例：
<!DOCTYPE html>
<html>
<head>
<title>Geolocation API with Google Maps API</title>
<meta charset="UTF-8" />
</head>
<body>
<script>
function displayLocation(latitude,longitude){
var request = new XMLHttpRequest();
var method = 'GET';
var url = 'http://maps.googleapis.com/maps/api/geocode/json?latlng='+latitude+','+longitude+'&sensor=true';
var async = true;
request.open(method, url, async);
request.onreadystatechange = function(){
if(request.readyState == 4 && request.status == 200){
var data = JSON.parse(request.responseText);
var address = data.results[0];
document.write(address.formatted_address);
}
};
request.send();
};
var successCallback = function(position){
var x = position.coords.latitude;
var y = position.coords.longitude;
displayLocation(x,y);
};
var errorCallback = function(error){
var errorMessage = 'Unknown error';
switch(error.code) {
case 1:
errorMessage = 'Permission denied';
break;
case 2:
errorMessage = 'Position unavailable';
break;
case 3:
errorMessage = 'Timeout';
break;
}
document.write(errorMessage);
};
var options = {
enableHighAccuracy: true,
timeout: 1000,
maximumAge: 0
};
navigator.geolocation.getCurrentPosition(successCallback,errorCallback,options);
</script>
</body>
</html>
在node.js中，我们可以使用节点地理编码npm模块从lat、lng、。，
geo.js
var NodeGeocoder = require('node-geocoder');
var options = {
provider: 'google',
httpAdapter: 'https', // Default
apiKey: ' ', // for Mapquest, OpenCage, Google Premier
formatter: 'json' // 'gpx', 'string', ...
};
var geocoder = NodeGeocoder(options);
geocoder.reverse({lat:28.5967439, lon:77.3285038}, function(err, res) {
console.log(res);
});
输出：
节点geo.js
[ { formattedAddress: 'C-85B, C Block, Sector 8, Noida, Uttar Pradesh 201301, India',
latitude: 28.5967439,
longitude: 77.3285038,
extra:
{ googlePlaceId: 'ChIJkTdx9vzkDDkRx6LVvtz1Rhk',
confidence: 1,
premise: 'C-85B',
subpremise: null,
neighborhood: 'C Block',
establishment: null },
administrativeLevels:
{ level2long: 'Gautam Buddh Nagar',
level2short: 'Gautam Buddh Nagar',
level1long: 'Uttar Pradesh',
level1short: 'UP' },
city: 'Noida',
country: 'India',
countryCode: 'IN',
zipcode: '201301',
provider: 'google' } ]
以下是Google地理编码Web服务的最新示例
https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224，-73.96452&密钥=YOUR_API_key
只需将YOUR_API_KEY更改为从Google Geocoding API 获得的API密钥
p/S：地理编码API位于地点非地图下；(
以下代码可以很好地获取城市名称(使用Google Map Geo API(：
HTML
<p><button onclick="getLocation()">Get My Location</button></p>
<p id="demo"></p>
<script src="http://maps.google.com/maps/api/js?key=YOUR_API_KEY"></script>
脚本
var x=document.getElementById("demo");
function getLocation(){
if (navigator.geolocation){
navigator.geolocation.getCurrentPosition(showPosition,showError);
}
else{
x.innerHTML="Geolocation is not supported by this browser.";
}
}
function showPosition(position){
lat=position.coords.latitude;
lon=position.coords.longitude;
displayLocation(lat,lon);
}
function showError(error){
switch(error.code){
case error.PERMISSION_DENIED:
x.innerHTML="User denied the request for Geolocation."
break;
case error.POSITION_UNAVAILABLE:
x.innerHTML="Location information is unavailable."
break;
case error.TIMEOUT:
x.innerHTML="The request to get user location timed out."
break;
case error.UNKNOWN_ERROR:
x.innerHTML="An unknown error occurred."
break;
}
}
function displayLocation(latitude,longitude){
var geocoder;
geocoder = new google.maps.Geocoder();
var latlng = new google.maps.LatLng(latitude, longitude);
geocoder.geocode(
{'latLng': latlng},
function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[0]) {
var add= results[0].formatted_address ;
var value=add.split(",");
count=value.length;
country=value[count-1];
state=value[count-2];
city=value[count-3];
x.innerHTML = "city name is: " + city;
}
else {
x.innerHTML = "address not found";
}
}
else {
x.innerHTML = "Geocoder failed due to: " + status;
}
}
);
}
BigDataCloud也有一个很好的API，也适用于nodejs用户。
他们有免费的API。但也适用于后端，使用API_KEY(根据配额免费(。
他们的GitHub页面。
代码看起来像：
const client = require('@bigdatacloudapi/client')(API_KEY);
async foo() {
...
const location: string = await client.getReverseGeocode({
latitude:'32.101786566878445',
longitude: '34.858965073072056'
});
}
如果您不想使用google地理编码API，那么您可以参考其他几个免费API进行开发。例如，我使用[mapquest]API来获取位置名称。
通过实现以下功能，您可以轻松地获取位置名称
const fetchLocationName = async (lat,lng) => {
await fetch(
'https://www.mapquestapi.com/geocoding/v1/reverse?key=API-Key&location='+lat+'%2C'+lng+'&outFormat=json&thumbMaps=false',
)
.then((response) => response.json())
.then((responseJson) => {
console.log(
'ADDRESS GEOCODE is BACK!! => ' + JSON.stringify(responseJson),
);
});
};下面是一个使用promise的现代解决方案：
function getAddress (latitude, longitude) {
return new Promise(function (resolve, reject) {
var request = new XMLHttpRequest();
var method = 'GET';
var url = 'http://maps.googleapis.com/maps/api/geocode/json?latlng=' + latitude + ',' + longitude + '&sensor=true';
var async = true;
request.open(method, url, async);
request.onreadystatechange = function () {
if (request.readyState == 4) {
if (request.status == 200) {
var data = JSON.parse(request.responseText);
var address = data.results[0];
resolve(address);
}
else {
reject(request.status);
}
}
};
request.send();
});
};
这样称呼它：
getAddress(lat, lon).then(console.log).catch(console.error);
promise返回'then'中的地址对象或'catch'中的错误状态代码
与@Sanchit Gupta相同。
在这个部分
if (results[0]) {
var add= results[0].formatted_address ;
var value=add.split(",");
count=value.length;
country=value[count-1];
state=value[count-2];
city=value[count-3];
x.innerHTML = "city name is: " + city;
}
只需控制台结果数组
if (results[0]) {
console.log(results[0]);
// choose from console whatever you need.
var city = results[0].address_components[3].short_name;
x.innerHTML = "city name is: " + city;
}
以下代码对我来说很好城市状态国邮政编码(使用谷歌地图地理API(：
var url = "https://maps.googleapis.com/maps/api/geocode/json?latlng="+lat+","+long+"&key=KEY_HERE&sensor=false";
$.get(url, function(data) {
var results = data.results;
if (data.status === 'OK')
{
//console.log(JSON.stringify(results));
if (results[0])
{
var city = "";
var state = "";
var country = "";
var zipcode = "";
var address_components = results[0].address_components;
for (var i = 0; i < address_components.length; i++)
{
if (address_components[i].types[0] === "administrative_area_level_1" && address_components[i].types[1] === "political") {
state = address_components[i].long_name;
}
if (address_components[i].types[0] === "locality" && address_components[i].types[1] === "political" ) {
city = address_components[i].long_name;
}
if (address_components[i].types[0] === "postal_code" && zipcode == "") {
zipcode = address_components[i].long_name;
}
if (address_components[i].types[0] === "country") {
country = address_components[i].long_name;
}
}
var address = {
"city": city,
"state": state,
"country": country,
"zipcode": zipcode,
};
console.log(address);
}
else
{
window.alert('No results found');
}
}
else
{
window.alert('Geocoder failed due to: ' + status);
}
});
有很多可用的工具
- 谷歌地图API就像所有人写的一样
- 使用此数据"https://simplemaps.com/data/world-cities"下载免费版本，并使用一些在线转换器将excel转换为JSON，如"http://beautifytools.com/excel-to-json-converter.php">
- 使用IP地址这不好，因为使用某人的IP地址可能不好用户认为你可以破解他们
其他免费和付费工具也可用
公共函数retornaCidade($lat，$lng(
{
$key = "SUA CHAVE";
$url = 'https://maps.googleapis.com/maps/api/geocode/json?latlng=' . $lat . ',' . $lng . '&key=' . $key;
$geoFull = json_decode ( file_get_contents ( $url ), true );
if ( $geoFull[ 'results' ] )
{
//console.log(JSON.stringify(results));
if ( $geoFull[ 'results' ][ 0 ] )
{
$cidade = "";
$estado = "";
$pais = "";
$cep = "";
$address_components = $geoFull[ 'results' ][ 0 ][ 'address_components' ];
for ( $i = 0; $i < count ( $address_components ); $i++ )
{
if ( ($address_components[ $i ][ 'types' ][ 0 ] == "administrative_area_level_1") && ($address_components[ $i ][ 'types' ][ 1 ] == "political" ))
{
$estado = str_replace('State of ', '',$address_components[ $i ][ 'long_name' ]);];
}
if ( ($address_components[ $i ][ 'types' ][ 0 ] == "administrative_area_level_2") && ($address_components[ $i ][ 'types' ][ 1 ] == "political" ))
{
$cidade = $address_components[ $i ][ 'long_name' ];
}
if ( $address_components[ $i ][ 'types' ][ 0 ] == "postal_code" && $cep == "" )
{
$cep = $address_components[ $i ][ 'long_name' ];
}
if ($address_components[ $i ][ 'types' ][ 0 ] == "country" )
{
$pais = $address_components[ $i ][ 'long_name' ];
}
}
$endereco = [
"cidade" => $cidade,
"estado" => $estado,
"pais" => $pais,
"cep" => $cep,
];
return $endereco;
}
else
{
return false;
}
}
else
{
return false;
}
}
您可以在基于Node的API中使用此库来进行反向地理编码：
https://github.com/rapomon/geojson-places
您可以使用纯php和谷歌地理编码api
/*
*
* @param latlong (String) is Latitude and Longitude with , as separator for example "21.3724002,39.8016229"
**/
function getCityNameByLatitudeLongitude($latlong)
{
$APIKEY = "AIzaXXXXXXXXXXXXXXXXXXXXXXXXXXX"; // Replace this with your google maps api key
$googleMapsUrl = "https://maps.googleapis.com/maps/api/geocode/json?latlng=" . $latlong . "&language=ar&key=" . $APIKEY;
$response = file_get_contents($googleMapsUrl);
$response = json_decode($response, true);
$results = $response["results"];
$addressComponents = $results[0]["address_components"];
$cityName = "";
foreach ($addressComponents as $component) {
// echo $component;
$types = $component["types"];
if (in_array("locality", $types) && in_array("political", $types)) {
$cityName = $component["long_name"];
}
}
if ($cityName == "") {
echo "Failed to get CityName";
} else {
echo $cityName;
}
}
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