Asp.net MVC使用Ajax从PartialView的actionlink加载父视图不起作用

Asp.net MVC Loading Parent View from the actionlink of PartialView using Ajax not working

本文关键字:加载 actionlink 视图 不起作用 PartialView MVC net 使用 Ajax Asp      更新时间:2023-09-26

我有一种情况,需要从ParentView的局部视图调用它。就像我在Partial视图中有ToDos列表一样,Ajax操作链接用于通过传递id来编辑父级中的数据。在不使用Ajax的情况下,它也可以通过放入querystring来操作url。但我们希望与Ajax进行内部通话,Ajax不会开火。

我们使用的代码如下:

<li>@Ajax.ActionLink(@item.ToDoTitle, "Index", new { tdid = @item.ToDoId }, new AjaxOptions { UpdateTargetId = "saved", InsertionMode = InsertionMode.Replace, HttpMethod="POST" })</li>

控制器是这样的:

public ActionResult Index(int tdid =0)
    {
        if (tdid !=0)
        {
            ToDo t = new ToDo();
            t.ToDoTitle = "Ramlal";
            t.ToDoDesc = "Shyamlal";
            t.ToDoId = tdid;
            return Json(t);
        }
        else
        {
            return View();
        }
    }

我们也尝试过返回视图,但没有发生任何事情,所以我们尝试使用Json作为它的返回模型。

如果我错了,请纠正我?

仅供参考,这是父视图:

@model myTask.Models.ToDo
@{
    ViewBag.Title = "My Task";
}
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script src="~/Scripts/jquery.unobtrusive-ajax.min.js"></script>
@using (Ajax.BeginForm("Save", new AjaxOptions() { InsertionMode = InsertionMode.Replace, UpdateTargetId = "MyTaskList" }))
{
    @Html.AntiForgeryToken()
    <div class="MyTask">
        @Html.HiddenFor(t => t.ToDoId)
        <div class="row">
            <div class="col-lg-12">
                @Html.LabelFor(t => t.ToDoTitle)<br />
                @Html.TextBoxFor(t => t.ToDoTitle)
            </div>
            <div class="col-lg-12">
                @Html.LabelFor(t => t.ToDoDesc)<br />
                @Html.TextAreaFor(t => t.ToDoDesc)
            </div>
        </div>
        <script>
            $( "#ToDoTitle" ).blur( function() {
                $.ajax({
                    url: "Save",
                    type: "POST",
                data: $("#form0").serialize(),
                dataType: "json"
                }).done(function (model) {
                $("#ToDoId").val(model.ToDoId);
                $("#ToDoTitle").val(model.ToDoTitle);
                $("#ToDoDesc").val(model.ToDoDesc);
            });
            });
            $("#ToDoDesc").blur(function () {
                if ($("#ToDoId").val() > 0) {
                    $.ajax({
                        url: "Save",
                        type: "POST",
                        data: $("#form0").serialize(),
                        dataType: "json"
                    }).done(function (model) {
                        $("#ToDoId").val(model.ToDoId);
                        $("#ToDoTitle").val(model.ToDoTitle);
                        $("#ToDoDesc").val(model.ToDoDesc);
                    });
                }});
        </script>
    </div>
    <div class="ObjectList" id="MyTaskList">
        @Html.Action("TodoList")
    </div>
    <div class="clearfix"></div>
}

这是使用@Html.Action("TodoList")调用的部分视图

@using System.Linq
@model myTask.Models.ToDoList
@{
    ViewBag.Title = "Index";
}
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script src="~/Scripts/jquery.unobtrusive-ajax.min.js"></script>
<div class="row">
    @if (Model.ToDos.Count > 0)
    {
        <ul>
            @foreach (var item in Model.ToDos)
            {
                @*<li>@Html.ActionLink(@item.ToDoTitle, "Index", new { tdid = @item.ToDoId })</li>*@
                <li>@Ajax.ActionLink(@item.ToDoTitle, "/Index", new { tdid = @item.ToDoId }, new AjaxOptions { UpdateTargetId = "MyTask", InsertionMode = InsertionMode.Replace, HttpMethod = "POST" })</li>
            }
        </ul>
    }
</div>

控制器:

using myTask.Models;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading.Tasks;
using System.Web;
using System.Web.Mvc;
namespace myTask.Controllers
{
    public class TasktdController : Controller
    {
        // GET: Tasktd
        public ActionResult Index(int tdid =0)
        {
            if (tdid !=0)
            {
                ToDo t = new ToDo();
                t.ToDoTitle = "Ramlal";
                t.ToDoDesc = "Shyamlal";
                t.ToDoId = tdid;
                return PartialView(t);
            }
            else
            {
                return View();
            }
        }
        [HttpPost]
        [ValidateAntiForgeryToken]
        public async Task<ActionResult> Save(ToDo td)
        {
            var errors = ModelState.Values.SelectMany(v => v.Errors);
            ModelState.Remove("ToDoId");
            if (ModelState.IsValid)
            {
                var t = await td.Save(td);
                return Json(td);
            }
            return Json("Oops! Error Occured");
        }
        [ChildActionOnly]
        public PartialViewResult TodoList()
        {
            ToDoList tdl = new ToDoList();
            List <ToDo> tds= new List<ToDo>();
            ToDo t = new ToDo();
            t.ToDoId = 1;
            t.ToDoTitle = "XXX";
            tds.Add(t);
            tdl.ToDos = tds;
            return PartialView(tdl);
        }
    }
}

您的代码有很多问题。首先,您使用.ajax()提交表单,但表单甚至没有提交按钮!更换

@using (Ajax.BeginForm("Save", new AjaxOptions() { ... })
{
  ....
}

带有

<form id="form">
  .... // add controls for properties
  <button id="save" type="button">Save</button>
</form>

删除$( "#ToDoTitle" ).blur()$("#ToDoDesc").blur()的脚本并替换为

<script>
  var form = $('#form');
  var saveUrl = '@Url.Action("Save")';
  $.post(saveUrl, form.serialize(), function(data) {
    if(data) {
      // save successful - give the user some feedback
    }
  }).fail(function (result) {
    // Oops and error occurred - give the user some feedback
  });
  .... // add script for editing here (see below0
</script>

您当前的脚本会导致性能不佳,并且是糟糕的UI设计的结果。用户应该决定何时保存(即单击按钮),而不是您。考虑一下,如果用户编辑了描述的标题和选项卡,然后意识到所有内容都是正确的,根本不需要更改任何内容(您的代码已经更改了数据库中的数据,用户甚至不知道)

请注意,脚本应该紧跟在关闭</body>标记之前(不是内联)。如果成功保存了对象,则Save()方法应返回Json(true)

要处理点击"链接",请将部分更改为(注意不需要@if块)

<ul>
  @foreach (var item in Model.ToDos)
  {
    <li>
      <span>@item.ToDoTitle</span>
      <button class="edit" type="button" data-id="@item.@item.ToDoId">Edit</button>
    </li>
  }
</ul>

如果你想让按钮看起来像一个链接,那么使用css将其设置为

然后在主视图中添加另一个脚本

var editUrl = '@Url.Action("Get")';
$('.edit').click(function() {
  var id = $(this).data('id');
  var title = $(this).prev('span').text();
  $.getJSON(editUrl, { id: id, function(data) {
    // Populate form fields
    $('#ToDoId').val(id);
    $('#ToDoTitle').val(title);
    $('#ToDoDesc').val(data);
  });
});

控制器的方法是

public JsonResult Get(int id)
{
  // Look up the Description based on the id, for example
  string description = db.ToDo.Where(x => x.ToDoId == id).Select(x => x.ToDoDesc);
  return Json(description, JsonRequestBehavior.AllowGet);
}

请注意,视图中已经有ID和Title属性,因此只需要返回Description(我建议您按照此处的建议更改属性名称,即IDTitleDescription