如何在 JavaScript 中以递增顺序在对象中添加属性

how to add property in object in increasing order in javascript?

本文关键字:对象 顺序 添加 属性 JavaScript      更新时间:2023-09-26

>我有对象数组。在对象中,有些具有shortkeys属性,有些没有shortkeys属性。我想shortkeys属性添加到所有对象。重要的是我需要为所有对象提供独特的shortkeys

那些没有shortkeys的对象将遵循这些条件

  • 如果对象没有shortkeys则分配从 1-9 开始shortkeys,例如"Alt+1"、"Alt+2"..."Alt+9"。
  • 9之后,我需要0属性分配给对象。
  • 然后我需要分配像"alt+a","alt+b"这样的a-z
  • 重要的是我需要跳过已经定义的示例"alt+m"的所有shortkeys,以便每个对象都具有唯一的属性。

这是我的代码https://jsfiddle.net/krzz9zmf/

var arr=[
  {name:"abc",shortkeys:"alt+m"},
  {name:"c_1"},
  {name:"abc",shortkeys:"alt+t"},
  {name:"abc",shortkeys:"alt+c"},
  {name:"wes_2"},
  {name:"ncv_3"},
  {name:"sghb_4"},
  {name:"ijo_5"},
  {name:"nhio_6"},
  {name:"jion_7"},
  {name:"chudoi_8"},
  {name:"bdmki_9"},
  {name:"dssd_0"},
  {name:"sdfs_a"},
  {name:"abc",shortkeys:"alt+y"},
  {name:"abc",shortkeys:"alt+e"},
  {name:"sghb_b"},
  {name:"ijo_d"},
  {name:"gsha_e"},
  {name:"asdas_f"},
  {name:"bbb_g"},
  {name:"mko_h"},
  {name:"kioh_i"},
  {name:"qwee_j"},
  {name:"qwee_k"},
  {name:"qwee_l"},
  {name:"qwee_n"},
]
var j =1;
for(var i=0;i<arr.length;i++){
  var obj =arr[i];
  if (!'shortkeys' in myObj){
    //add shorkeys start from 1-9 then 0 and then a-z.In other words need to assign shortcut key like that 'alt+1','alt+2'....'alt+0'''alt+a','alt+b'...'alt+z';
    //some of the objects already define shortkeys example 'alt+m' .so I need to skip these shortcut key .so that each item have unique shortcut.
    myObj.shortkeys= 'alt+'+j;
    j++;
    if(j==10){
      j=0
    }
    if(j==1){
      myObj.shortkeys='alt+a';
    }
  }
}

预期输出

[
{name:"abc",shortkeys:"alt+m"},
{name:"c_1",,shortkeys:"alt+1"},
{name:"abc",shortkeys:"alt+t"},
{name:"abc",shortkeys:"alt+c"},
{name:"wes_2",shortkeys:"alt+2"},
{name:"ncv_3",,shortkeys:"alt+3"},
{name:"sghb_4",shortkeys:"alt+4"},
{name:"ijo_5",shortkeys:"alt+5"},
{name:"nhio_6",shortkeys:"alt+6"},
{name:"jion_7",shortkeys:"alt+7"},
{name:"chudoi_8",shortkeys:"alt+8"},
{name:"bdmki_9",shortkeys:"alt+9"},
{name:"dssd_0",shortkeys:"alt+0"},
{name:"sdfs_a",shortkeys:"alt+a"},
{name:"abc",shortkeys:"alt+y"},
{name:"abc",shortkeys:"alt+e"},
{name:"sghb_b",shortkeys:"alt+b"},
{name:"ijo_d",shortkeys:"alt+d"},
{name:"gsha_e",shortkeys:"alt+e"},
{name:"asdas_f",shortkeys:"alt+f"},
{name:"bbb_g",shortkeys:"alt+g"},
{name:"mko_h",shortkeys:"alt+h"},
{name:"kioh_i",shortkeys:"alt+i"},
{name:"qwee_j",shortkeys:"alt+j"},
{name:"qwee_k",shortkeys:"alt+k"},
{name:"qwee_l",shortkeys:"alt+l"},
{name:"qwee_n",shortkeys:"alt+n"},
]

您可以浏览并删除作为键存在的字符,然后返回并添加剩余的内容

https://jsfiddle.net/stevenkaspar/krzz9zmf/8/

var alpha_num_array = [
'1','2','3','4',
'5','6','7','8','9',
'0',
'a','b','c','d','e',
'f','g','h','i','j',
'k','l','m','n','o',
'p','q','r','s','t',
'u','v','w','x','y',
'z'];
key_arr.map(function(k){
  if(!k.shortkeys) return;
  var key = k.shortkeys.split('+')[1];
  var key_index = alpha_num_array.indexOf(key);
  alpha_num_array.splice(key_index, 1);
})
key_arr = key_arr.map(function(k){
  if(k.shortkeys) return k;
  k.shortkeys = 'alt+'+alpha_num_array[0];
  alpha_num_array.shift();
  return k;
})
console.log(key_arr);

var arr=[
  {name:"abc",shortkeys:"alt+m"},
  {name:"c_1"},
  {name:"abc",shortkeys:"alt+t"},
  {name:"abc",shortkeys:"alt+c"},
  {name:"wes_2"},
  {name:"ncv_3"},
  {name:"sghb_4"},
  {name:"ijo_5"},
  {name:"nhio_6"},
  {name:"jion_7"},
  {name:"chudoi_8"},
  {name:"bdmki_9"},
  {name:"dssd_0"},
  {name:"sdfs_a"},
  {name:"abc",shortkeys:"alt+4"},
  {name:"abc",shortkeys:"alt+e"},
  {name:"sghb_b"},
  {name:"ijo_d"},
  {name:"gsha_e"},
  {name:"asdas_f"},
  {name:"bbb_g"},
  {name:"mko_h"},
  {name:"kioh_i"},
  {name:"qwee_j"},
  {name:"qwee_k"},
  {name:"qwee_l"},
  {name:"qwee_n"},
];
//possible shortkeys reversed so we can pop them off
var keys = [
  '1','2','3','4','5','6','7','8','9','0'
  ,'a','b','c','d','e','f','g','h','i','j'
  ,'k','l','m','n','o','p','q','r','s','t'
  ,'u','v','w','x','y','z'].reverse();
//elements without a shortkeys
var tagsWithoutShortcuts = arr.filter(function(element){ return typeof element.shortkeys === 'undefined'; });
console.log(keys);
console.log(tagsWithoutShortcuts);
tagsWithoutShortcuts.forEach(function(tag){
  var key = keys.pop();
  //while key is already used, get another
  while (arr.filter(function(element){ return element.shortkeys === 'alt+'+ key; }).length) key = keys.pop();
  //put the shortkeys on the tag
  tag.shortkeys = 'alt+'+ key;
});
console.log(arr);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

您现有尝试的错误(除了没有得到您想要的字母(是......

  • 您在声明var objmyObj使用了错误的变量名
  • 你有if (!'shortkeys' in myObj){而不是if (!('shortkeys' in myObj)){
  • 在分配现有shortkeys之前,您未能查找现有

在此代码中,我...

  • 添加了一个跟踪所有已使用的快捷键(包括当前存在的快捷键(的对象
  • 添加了一个循环,该循环会不断寻找唯一的快捷键,直到找到一个
  • 添加了用于获取a-z字符的alpha变量
  • 在主for循环中添加了一个OUTER标签,以便我们可以在超过字母z时中断循环。标签是必需的,因为我们正在打破内部do-while循环。

var arr=[
  {name:"abc",shortkeys:"alt+m"}, {name:"c_1"}, {name:"abc",shortkeys:"alt+t"}, {name:"abc",shortkeys:"alt+c"},
  {name:"wes_2"}, {name:"ncv_3"}, {name:"sghb_4"}, {name:"ijo_5"}, {name:"nhio_6"}, {name:"jion_7"},
  {name:"chudoi_8"}, {name:"bdmki_9"}, {name:"dssd_0"}, {name:"sdfs_a"}, {name:"abc",shortkeys:"alt+y"},
  {name:"abc",shortkeys:"alt+e"}, {name:"sghb_b"}, {name:"ijo_d"}, {name:"gsha_e"}, {name:"asdas_f"},
  {name:"bbb_g"}, {name:"mko_h"}, {name:"kioh_i"}, {name:"qwee_j"}, {name:"qwee_k"}, {name:"qwee_l"}, {name:"qwee_n"}
]
var j = 1;
var alpha = 'a'.charCodeAt(0); // Number for the 'a-z' chars
var z = 'z'.charCodeAt(0); // Number for the 'z' character
var shorts = {}; // Holds all shortkeys to avoid duplicates
var short = "";
// First gather all the existing shortkeys
for (var i = 0; i < arr.length; i++) {
  if (arr[i].shortkeys) {
    shorts[arr[i].shortkeys] = arr[i].shortkeys
  }
}
OUTER:
for (var i = 0; i < arr.length; i++) {
  var myObj = arr[i];
  
  if (!('shortkeys' in myObj)) {
    // We want to make sure that our "short" is not yet used.
    do {
      if (j < 10) {
        short = 'alt+' + j
        j++;
        
      } else if (j == 10) {
        short = 'alt+0'
        j++;
        
      } else if (alpha <= z) {
        short = 'alt+' + String.fromCharCode(alpha);
        alpha++;
        
      } else {
      	break OUTER; // We've moved beyond 'z', so just quit.
      }
    } while(short in shorts)
    
    // Track the new shortkey, and assign it
    shorts[short] = short
    myObj.shortkeys = short
  }
}
document.querySelector("pre").textContent = JSON.stringify(arr, null, 4)
<pre></pre>

注意。。。

  • 你的预期输出有一个错误;它有两次alt+e
  • 无需手动创建值数组,因为字符映射到数字