如何通过邮政编码确定美国县

How can I determine US County by zip-code?

本文关键字：美国县 邮政编码 何通过      更新时间：2023-09-26

是否可以在javascript中在客户端实现一个函数来像这样使用它：

var county = get_county(zip_code);

我的意思是可以通过脚本在线完成吗？或者我必须挖掘一些数据库？还是我必须买它？

任何帮助不胜感激！


附言在Dyrandz Famador的帮助下，我为GAS做了这个功能：

function get_county(zip) {
 var county, response, result, adresses, i, j, n, type;
 response = Maps.newGeocoder().geocode(zip);
 for (i = 0; i < response.results.length; i++) {
   result = response.results[i];
   adresses = result.address_components;
   n = adresses.length;
   for (j=0;j<n;j++) {
     type = adresses[j].types[0];
     if (type == 'locality') county = (adresses[j].long_name);
     if (type == 'administrative_area_level_2')   {county =(adresses[j].long_name);}
   }
 }
 return (county);
}

您可以使用谷歌地图API从邮政编码中获取位置

Google提供了许多API，其中包括Maps API。在此示例中 我们将显示使用邮政编码访问Google所需的所有代码 以城市，州和国家/地区的形式获取位置。

首先要做的是引用 Google 的 Map API：

<script language="javascript" src="https://maps.google.com/maps/api/js?sensor=false"></script>

接下来是用于输入邮政编码的小表格：

<form>
zip: <input type="text" name="zip" value="46032"> <a href="#" onclick="getLocation()">Get Address</a>
</form>

你可以看到我有一个链接，它触发了一个名为“getLocation()”的函数——下面你会发现该函数和相关代码：

...
<script language="javascript">
function getLocation(){
  getAddressInfoByZip(document.forms[0].zip.value);
}
function response(obj){
  console.log(obj);
}
function getAddressInfoByZip(zip){
  if(zip.length >= 5 && typeof google != 'undefined'){
    var addr = {};
    var geocoder = new google.maps.Geocoder();
    geocoder.geocode({ 'address': zip }, function(results, status){
      if (status == google.maps.GeocoderStatus.OK){
        if (results.length >= 1) {
      for (var ii = 0; ii < results[0].address_components.length; ii++){
        var street_number = route = street = city = state = zipcode = country = formatted_address = '';
        var types = results[0].address_components[ii].types.join(",");
        if (types == "street_number"){
          addr.street_number = results[0].address_components[ii].long_name;
        }
        if (types == "route" || types == "point_of_interest,establishment"){
          addr.route = results[0].address_components[ii].long_name;
        }
        if (types == "sublocality,political" || types == "locality,political" || types == "neighborhood,political" || types == "administrative_area_level_3,political"){
          addr.city = (city == '' || types == "locality,political") ? results[0].address_components[ii].long_name : city;
        }
        if (types == "administrative_area_level_1,political"){
          addr.state = results[0].address_components[ii].short_name;
        }
        if (types == "postal_code" || types == "postal_code_prefix,postal_code"){
          addr.zipcode = results[0].address_components[ii].long_name;
        }
        if (types == "country,political"){
          addr.country = results[0].address_components[ii].long_name;
        }
      }
      addr.success = true;
      for (name in addr){
          console.log('### google maps api ### ' + name + ': ' + addr[name] );
      }
      response(addr);
        } else {
          response({success:false});
        }
      } else {
        response({success:false});
      }
    });
  } else {
    response({success:false});
  }
}
</script>
...

就是这样 - 在Chrome中打开控制台，并在您输入不同的邮政编码时注意输出。

从这里获取：http://rickluna.com/wp/2012/09/using-the-google-maps-api-to-get-locations-from-zip-codes/

你需要知道zip_code和国家/地区的映射，

我为此找到了一个 github 项目：

https://github.com/jgoodall/us-maps

通过指令获得 JSON 映射后，即可实现所需的函数。

这是美国政府的一个很好的地理数据库API：
https://www.sba.gov/about-sba/sba-performance/sba-data-store/web-service-api/us-city-and-county-web-data-api#county-state

该 API 生成所有县和州信息，但似乎不包含邮政编码。使用谷歌地理编码API可能更容易。

这是

您可以从几乎任何位置输入（例如Santa Monica, CA或90405）中获取地址，城市，州和/或邮政编码的一种方法。请记住，除非您的请求非常具体，否则您不能总是返回所有这些变量。 

function getLocationInfo(){
    var location = $('#location').val();
    var geocoder = new google.maps.Geocoder();
    geocoder.geocode({ 'address': location }, function (result, status) {
    var address = '';
    var streetNumber = '';
    var streetName = '';
    var cityName = '';
    var stateName = '';
    var zipCode = '';
    var addressComponent = result[0]['address_components'];
    // find street number
    var streetNumberQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('street_number', x.types) != -1;
    });
    if (streetNumberQueryable.length) {
        streetNumber = streetNumberQueryable[0]['long_name'];
    }
    // find street name
    var streetNameQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('route', x.types) != -1;
    });
    if (streetNameQueryable.length) {
        streetName = streetNameQueryable[0]['long_name'];
    }
    // find city data
    var cityQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('locality', x.types) != -1;
    });
    if (cityQueryable.length) {
        cityName = cityQueryable[0]['long_name'];
    }
    // find state data
    var stateQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('administrative_area_level_1', x.types) != -1;
    });
    if (stateQueryable.length) {
        stateName = stateQueryable[0]['long_name'];
    }
    // find zip data
    var zipQueryable = $.grep(addressComponent, function (x) {
        return $.inArray('postal_code', x.types) != -1;
    });
    if (zipQueryable.length) {
        zipCode = zipQueryable[0]['long_name'];
    }
    address = streetNumber + ' ' + streetName;
    console.log(address);
    console.log(cityName);
    console.log(stateName);
    console.log(zipCode);
    });
}
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