这是将JSON解析为var的正确方法吗?

Is this the correct way for parsing JSON into var?

本文关键字：方法 var JSON      更新时间：2023-09-26

我有这个carData JSON:这是正确的解析JSON数据吗?

var carData = '[{"ConditionNotes":{},"Photos":{},"RealChassisNo":"BJ5W-315859","Age":0,"Miles":0,"ImprovementCost":0,"AirBagType":0,"M3":0,"Category":0,"IsMiles":false,"IsInnerCargo":false,"IsPreSold":false,"IsNoNZ":false,"InnerCargoNote":null,"DateStock":"'/Date(-62135596800000)'/","IsSold":false,"PriceSales":0,"PriceConfirmation":0,"PriceExport":0,"PriceATSales":0,"ScaledMargin":0,"PriceDynamic":0,"FobFees":332000.0000,"OFSFees":1440.0000,"CIFFees":0,"FreightRate":0,"PriceBase":0,"MarketTerm":null,"IsIncludeOPC":false,"CustomerTerm":null,"LandedCost":0,"NZNote":null,"NZStructuralNote":null,"NZStructuralCost":0,"IDIBCInfo":null,"TransportStatus":null,"DateDeparture":"'/Date(1281801600000)'/","DateArrive":"'/Date(1283788800000)'/","ShipName":"Saracen Star(KB)","TypeOfSale":"","BuyTripCustomer":"","IsSplitCurrency":false,"Currency":"JPY","CountryID":75,"IsFollowing":false,"FrieghtAndInsuranceTerm":null,"FrieghtAndInsuranceFees":0,"PriceBaseForATNZ":0,"IDVehicle":"232960","Price":0,"MaskChassisNo":null,"Make":"MAZDA","Model":"FAMILIA","Year":2002,"Month":0,"Type":null,"Location":null,"Grade":"S-F","Transmission":null,"KMS":0,"EngineDisplacement":null,"Fuel":null,"Doors":null,"ConditionGrade":null,"Color":null,"IsPowerSteering":false,"IsPowerWindow":false,"IsAirConditioned":false,"InteriorColor":null,"InteriorType":null,"HasSunRoof":false,"Length":0,"Width":0,"Height":0,"WheelStyle":0,"HasSpareKey":false,"SalesNote":null,"IsSale":false,"IsNewArrival":false,"IsReserved":false,"IsThailandStocks":false,"IsLeftHandDrive":false,"DateInspected":"'/Date(-62135596800000)'/","ExteriorVideo":null,"InteriorVideo":null,"IsSingaporeStocks":false,"IsUKStocks":false,"IsOriginalLHD":false,"CustomerPort":null,"Airbag":0,"IsNonSmoker":false,"Tonnage":0,"InteriorGrade":null,"DateConfirm":"'/Date(-62135596800000)'/"}]';
var obj = JSON.parse(carData);

是的，你用javascript写了正确的json解析语句。更多的，我张贴了一个javascript json解析的例子。

var text = '{ "employees" : [' +
'{ "firstName":"John" , "lastName":"Doe" },' +
'{ "firstName":"Anna" , "lastName":"Smith" },' +
'{ "firstName":"Peter" , "lastName":"Jones" } ]}';
var obj = JSON.parse(text);

是正确的方式，但是如果你使用旧的浏览器(不支持JSON)。解析函数)你应该使用eval()

eval ("(" + carData + ")")

这将创建一个只有1个元素的JSON数组。如果你只有一个元素，为什么不去掉开头的‘[’和结尾的‘]’呢?无论如何，JSON.parse(carData)将成功解析您的JSON。obj[0]会有JSON的详细信息

是的，这是正确的方法。JSON.parse()将您的JSON字符串转换为JavaScript对象。

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