JSON and AJAX response
JSON and AJAX response
嗨,我有一个JSON:响应
[{"id":"1","message":"sdvsvdsdv","nickname":""},{"id":"2","message":"1234556","nickname":""},{"id":"3","message":"4555555","nickname":""}]
javascript函数:
function ajax_request(){
var request = new XMLHttpRequest();
var url = "http://localhost/chat/controller.php?showmessage";
request.open("post", url, true);
request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
request.onreadystatechange = function(){
if(request.readyState == 4 && request.status == 200){
var return_data = request.responseText; // THE WHOLE JSON
document.getElementById("chat").innerHTML = return_data;
}
}
request.send();}
如何只获取元素"message"而不获取整个JSON?。
使用JSON.parse("<JSON-STRING>")
取出对象。从对象中,您可以提取您的消息。
类似于:
var jsonObj = JSON.parse(request.responseText);
for (var i=0; i<jsonObj.length; i++){
alert(jsonObj[i].message); //alerts each "message" ..
}
这与实际问题有所不同,但我确实建议您使用jQuery库。这会让你付出一半的努力。有一个简单的$.ajax(..)
来处理AJAX请求,$.parseJSON(..)
来解析JSON字符串——所有这些都是以跨浏览器的方式进行的。
var returnObject = JSON.parse(request.responseText);
for (var i in returnObject) {
document.getElementById("chat").innerHTML += '<br/>' + returnObject[i].message;
}
像这样:
resp = '[{"id":"1","message":"sdvsvdsdv","nickname":""},{"id":"2","message":"1234556","nickname":""},{"id":"3","message":"4555555","nickname":""}]'
console.log(JSON.parse(resp)[0]['message'])
使用JSON.parse()
方法将JSON字符串转换为JS对象
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