谷歌地图API地理编码多个位置

Google Maps API Geocoding Multiple Locations

本文关键字:位置 编码 API 谷歌地图      更新时间:2023-09-26

我已经设置了一些js代码来对某些位置和地点进行地理编码,而不是在地图上。我可以轻松地完成一个位置,但我无法让它在两个位置工作。我的工作代码如下,但仅适用于一个位置。

var geocoder = new google.maps.Geocoder();
    var address = "Melbourne";
    geocoder.geocode( { 'address': address}, function(results, status) {
        var latitude = results[0].geometry.location.lat();
        var longitude = results[0].geometry.location.lng();

        initialize(latitude,longitude);
        }); 

    function initialize(latitude,longitude) {
        var latlng1 = new google.maps.LatLng(latitude,longitude);
        var myOptions = {
          zoom: 2,
          panControl: false,
            zoomControl: false,
            mapTypeControl: false,
            streetViewControl: false,
          center: latlng1,
          mapTypeId: google.maps.MapTypeId.ROADMAP,
          mapTypeControl: false,
          scrollwheel: false,
        };
        var map = new google.maps.Map(document.getElementById("google-container"),myOptions);
        var marker = new google.maps.Marker({
          position: latlng1, 
          map: map, 
        }); 
      }

我试图在下面添加第二个,但我显然错过了一些东西。正如你可能猜到的,我是javascript的新手。

    var geocoder = new google.maps.Geocoder();
var address = "Seoul";
var address2 = "Melbourne";
geocoder.geocode( { 'address': address}, function(results, status) {
    var latitude = results[0].geometry.location.lat();
    var longitude = results[0].geometry.location.lng();
    var latitude2 = r

    initialize(latitude,longitude);
    }); 
    geocoder.geocode( { 'address': address2}, function(results, status) {
    var latitude2 = results[0].geometry.location.lat();
    var longitude2 = results[0].geometry.location.lng();
    var latitude2 = r

    initialize(latitude2,longitude2);
    }); 

function initialize(latitude,longitude) {
    var latlng1 = new google.maps.LatLng(latitude,longitude);
    var latlng2 = new google.maps.LatLng(latitude2,longitude2);
    var myOptions = {
      zoom: 2,
      panControl: false,
        zoomControl: false,
        mapTypeControl: false,
        streetViewControl: false,
      center: latlng1,
      mapTypeId: google.maps.MapTypeId.ROADMAP,
      mapTypeControl: false,
      scrollwheel: false,
    };
    var map = new google.maps.Map(document.getElementById("google-container"),myOptions);
    var marker = new google.maps.Marker({
      position: latlng1, 
      map: map, 
    }); 
      var marker2 = new google.maps.Marker({
      position: latlng2, 
      map: map, 
    }); 
  }

任何想法都将非常受欢迎!

此解决方案适用于两个位置,可能最多 10 个位置,之后您将开始遇到地理编码器上的查询和速率限制

  1. 分离出初始化函数,只需初始化地图即可
  2. 为每个位置创建一个唯一的地理编码器实例(您可以通过在回调中重复使用相同的地理编码器实例来重复使用该实例,不值得两点)。

工作小提琴

工作代码片段:

function initialize() {
    var myOptions = {
        zoom: 2,
        panControl: false,
        zoomControl: false,
        mapTypeControl: false,
        streetViewControl: false,
        center: {
            lat: 0,
            lng: 0
        },
        mapTypeId: google.maps.MapTypeId.ROADMAP,
        mapTypeControl: false,
        scrollwheel: false,
    };
    var bounds = new google.maps.LatLngBounds();
    var map = new google.maps.Map(document.getElementById("google-container"), myOptions);
    var geocoder = new google.maps.Geocoder();
    var address = "Seoul";
    geocoder.geocode({
        'address': address
    }, function (results, status) {
        if (status == google.maps.GeocoderStatus.OK) {
            var marker = new google.maps.Marker({
                position: results[0].geometry.location,
                map: map,
            });
            bounds.extend(results[0].geometry.location);
            map.fitBounds(bounds);
        } else {
            alert("Geocode of " + address + " failed," + status);
        }
    });
    var geocoder2 = new google.maps.Geocoder();
    var address2 = "Melbourne";
    geocoder2.geocode({
        'address': address2
    }, function (results, status) {
        if (status == google.maps.GeocoderStatus.OK) {
            var marker = new google.maps.Marker({
                position: results[0].geometry.location,
                map: map,
            });
            bounds.extend(results[0].geometry.location);
            map.fitBounds(bounds);
        } else {
            alert("Geocode of " + address2 + " failed," + status);
        }
    });
}
google.maps.event.addDomListener(window, 'load', initialize);
html, body, #google-container {
    height: 100%;
    width: 100%;
    margin: 0px;
    padding: 0px
}
<script src="https://maps.googleapis.com/maps/api/js?key=AIzaSyCkUOdZ5y7hMm0yrcCQoCvLwzdM6M8s5qk"></script>
<div id="google-container" style="border: 2px solid #3872ac;"></div>

here is some code optimization allows to process multiple addresses
      <div id="map-canvas"
   style='position: relative; height: 100%; width: 100%; margin-left: 0px; border: #B8B6B8 solid 1px;; background-color: #ffffff;'>
  </div> 
<script type="text/javascript">
    var geocoder;
    var map;
    function initialize() {
        geocoder = new google.maps.Geocoder();
        var latlng = new google.maps.LatLng(-34.397, 150.644);
        var mapOptions = {
            zoom : 17,
            center : latlng,
            mapTypeId : google.maps.MapTypeId.ROADMAP
        };
        map = new google.maps.Map(document.getElementById("map-canvas"), mapOptions);
    }
    function codeAddress(addressList) {
        try {
            var icount = addressList.length;
            for (var i = 0; i < icount; i++) {
                getGeoCoder(addressList[i]);
            }
        } catch (error) {
            alert(error);
        }
    }
    function getGeoCoder(address) {
        geocoder.geocode({
            'address' : address
        }, function(results, status) {
            if (status == google.maps.GeocoderStatus.OK) {
                map.setCenter(results[0].geometry.location);
                var marker = new google.maps.Marker({
                    map : map,
                    position : results[0].geometry.location
                });
            } else {
                geterrorMgs(address); // address not found handler
            }
        });
    }
    //client's call
//addresses list to be processed
    var addressList = [ '1420 orchardview dr Pittsburgh,  PA,  USA', '1440 orchardview dr Pittsburgh,  PA,  USA', '1410 orchardview dr Pittsburgh,  PA,  USA' ];
        initialize();  
        codeAddress(addressList);
</script>