主干虹吸嵌套属性

尝试按以下方式命名输入

<input type="text" id="test1" name="steps[][description]" value="one step">
<input type="text" id="test2" name="steps[][description]" value="two step">

请注意使其成为实际对象数组的额外[]。

将索引也添加到每个类似的输入中。

<input type="text" id="test1" name="steps[1][description]" value="one step">
<input type="text" id="test2" name="steps[2][description]" value="two step">

在表单提交时，您可以像这样调用序列化对象函数：

var data = $('#form' + formId).serializeObject();
this.model.save(data, {
    success : function(model) {
    },
    error : function(model) {
    }
});

您可以使用下面的序列化对象函数来解析上述语法。这与此堆栈溢出问题中解决的问题相同

$.fn.serializeObject = function() {
        var json, patterns, push_counters, _this = this;
        json = {};
        push_counters = {};
        patterns = {
            validate : /^[a-zA-Z][a-zA-Z0-9_]*(?:'[(?:'d*|[a-zA-Z0-9_]+)'])*$/,
            key : /[a-zA-Z0-9_]+|(?='['])/g,
            push : /^$/,
            fixed : /^'d+$/,
            named : /^[a-zA-Z0-9_]+$/
        };
        this.build = function(base, key, value) {
            base[key] = value;
            return base;
        };
        this.push_counter = function(key) {
            if(push_counters[key] ===
            void 0) {
                push_counters[key] = 0;
            }
            return push_counters[key]++;
        };
        $.each($(this).serializeArray(), function(i, elem) {
            var k, keys, merge, re, reverse_key;
            if(!patterns.validate.test(elem.name)) {
                return;
            }
            keys = elem.name.match(patterns.key);
            merge = elem.value;
            reverse_key = elem.name;
            while(( k = keys.pop()) !==
            void 0) {
                if(patterns.push.test(k)) {
                    re = new RegExp("''[" + k + "'']$");
                    reverse_key = reverse_key.replace(re, '');
                    merge = _this.build([], _this.push_counter(reverse_key), merge);
                } else if(patterns.fixed.test(k)) {
                    merge = _this.build([], k, merge);
                } else if(patterns.named.test(k)) {
                    merge = _this.build({}, k, merge);
                }
            }
            return json = $.extend(true, json, merge);
        });
        return json;
    };
})(jQuery);