坐标之间的音差地理位置距离

Phonegap geolocation distance between coordinates

本文关键字：地理位置 距离 之间 坐标      更新时间：2023-09-26

我试图在javascript中计算两个坐标之间的距离。
更具体地说，一组静态坐标与我从地理位置科尔多瓦插件中获取的当前位置之间的距离。

这是我的代码：

document.addEventListener('deviceready', onDeviceReady, false);
function onDeviceReady() {
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};
var onSuccess = function(position) {
    document.getElementById("content").innerHTML = 'Success, attempting calculation...';
    var lla = position.coords.latitude;
    var llo = position.coords.longitude;
    document.getElementById("content").innerHTML =
'GPS Position: ' + calcTheDistance(lla, llo).d + 'Metres';

};
var onError = function(error) {
    document.getElementById("content").innerHTML =
    'code: ' + error.code + ''n' +
    'message: ' + error.message + ''n';
};
function refrGps() {
    document.getElementById("content").innerHTML = 'Loading...';
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};
function calcTheDistance(lati1, long1) {
    var r = 6371000; //Meters
    var joschLat = 50.1109221;
    var joschLon = 8.6821267;
    var la1 = lati1;
    var la2 = joschLat;
    var lat1 = lati1.toRadians();
    var lat2 = joschLat.toRadians();
    var lo1 = long1;
    var lo2 = joschLon;
    var la2minla1 = (la2-la1).toRadians();
    var lo2minlo1 = (lo2-lo1).toRadians();
    var cal = Math.sin(la2minla1 / 2) * Math.sin(la2minla1 / 2) +
            Math.cos(lat1) * Math.cos(lat2) *
            Math.sin(lo2minlo1/2) * Math.sin(lo2minlo1/2);
    var c = 2* Math.atan2(Math.sqrt(cal), Math.sqrt(1-cal));
    d = r * c;
};

我试图重写它几次，但没有运气。

对于计算，我提到了这个：http://www.movable-type.co.uk/scripts/latlong.html

您引用的页面包含已在 Javascript 中实现的函数库。如果在应用中包含这些内容，计算将变得微不足道：

document.addEventListener('deviceready', onDeviceReady, false);
function onDeviceReady() {
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};
var onSuccess = function(position) {
    document.getElementById("content").innerHTML = 'Success, attempting calculation...';
    var sourceLl = new LatLon(position.coords.latitude, position.coords.longitude);
    document.getElementById("content").innerHTML =
'GPS Position: ' + calcTheDistance(sourceLl) + 'Metres';
};
var onError = function(error) {
    document.getElementById("content").innerHTML =
    'code: ' + error.code + ''n' +
    'message: ' + error.message + ''n';
};
function refrGps() {
    document.getElementById("content").innerHTML = 'Loading...';
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};
function calcTheDistance(sourceLl) {
    var joschLat = 50.1109221;
    var joschLon = 8.6821267;
    var joschLl = new LatLon(joschLat, joschLon);
    return joschLl.distanceTo(sourceLl);
};

所以我在看完@DaveAlden的答案后就想通了，顺便谢谢！

toRadians（）; 不是一个标准的 Javascript 函数，所以在我添加它并稍微重写了我的代码之后，它工作得很好。

这是工作代码 document.addEventListener（'deviceready'， onDeviceReady， false）;

function onDeviceReady() {

navigator.geolocation.getCurrentPosition(onSuccess, onError);
};
var onSuccess = function(position) {
    document.getElementById("content").innerHTML = 'Success, attempting calculation...';
    var lla = position.coords.latitude;
    var llo = position.coords.longitude;
    var dst = 'Distance: ' + calcTheDistance(lla, llo) + ' Metres';
    document.getElementById("content").innerHTML = dst;

};
var onError = function(error) {
    document.getElementById("content").innerHTML =
    'code: ' + error.code + ''n' +
    'message: ' + error.message + ''n';
};
function refrGps() {
    document.getElementById("content").innerHTML = 'Loading...';
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};
    function toRadians(num) {
        return num * Math.PI / 180; 
};
function calcTheDistance(lati1, long1) {
    var r = 6371000; //metres
    var joschLat = 50.1109221;
    var joschLon = 8.6821267;
    var la1 = lati1;
    var la2 = joschLat;
    var lat1 = toRadians(lati1);
    var lat2 = toRadians(joschLat);
    var lo1 = long1;
    var lo2 = joschLon;
    var la2minla1 = toRadians(la2-la1);
    var lo2minlo1 = toRadians(lo2-lo1);
    var cal = Math.sin(la2minla1 / 2) * Math.sin(la2minla1 / 2) +
            Math.cos(lat1) * Math.cos(lat2) *
            Math.sin(lo2minlo1/2) * Math.sin(lo2minlo1/2);
    var c = 2* Math.atan2(Math.sqrt(cal), Math.sqrt(1-cal));
    var d = r * c;
    return Math.round(d);
};
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