JavaScript 复数英语字符串
JavaScript pluralize an english string
在PHP中，我使用Kuwamoto的类来复数我的字符串中的名词。除了一些插件之外，我没有在javascript中找到像这个脚本一样好的东西。因此，拥有一个基于 Kuwamoto 类的 javascript 函数会很棒。
http://kuwamoto.org/2007/12/17/improved-pluralizing-in-php-actionscript-and-ror/
簡化版 （ES6）：
const pluralize = (count, noun, suffix = 's') =>
`${count} ${noun}${count !== 1 ? suffix : ''}`;
打字稿：
const pluralize = (count: number, noun: string, suffix = 's') =>
`${count} ${noun}${count !== 1 ? suffix : ''}`;
用法：
pluralize(0, 'turtle'); // 0 turtles
pluralize(1, 'turtle'); // 1 turtle
pluralize(2, 'turtle'); // 2 turtles
pluralize(3, 'fox', 'es'); // 3 foxes
这显然不支持所有英语边缘情况，但它适用于大多数目的
使用复数
有一个很棒的小库叫做Pluralize，它被打包在npm和bower中。
这是它看起来的样子：
import Pluralize from 'pluralize';
Pluralize( 'Towel', 42 ); // "Towels"
Pluralize( 'Towel', 42, true ); // "42 Towels"
你可以在这里得到它：
https://github.com/blakeembrey/pluralize
因此，我通过分享我在 JavaScript 中翻译的 Kuwamoto 的 PHP 类来回答我自己的问题。
String.prototype.plural = function(revert){
var plural = {
'(quiz)$' : "$1zes",
'^(ox)$' : "$1en",
'([m|l])ouse$' : "$1ice",
'(matr|vert|ind)ix|ex$' : "$1ices",
'(x|ch|ss|sh)$' : "$1es",
'([^aeiouy]|qu)y$' : "$1ies",
'(hive)$' : "$1s",
'(?:([^f])fe|([lr])f)$' : "$1$2ves",
'(shea|lea|loa|thie)f$' : "$1ves",
'sis$' : "ses",
'([ti])um$' : "$1a",
'(tomat|potat|ech|her|vet)o$': "$1oes",
'(bu)s$' : "$1ses",
'(alias)$' : "$1es",
'(octop)us$' : "$1i",
'(ax|test)is$' : "$1es",
'(us)$' : "$1es",
'([^s]+)$' : "$1s"
};
var singular = {
'(quiz)zes$' : "$1",
'(matr)ices$' : "$1ix",
'(vert|ind)ices$' : "$1ex",
'^(ox)en$' : "$1",
'(alias)es$' : "$1",
'(octop|vir)i$' : "$1us",
'(cris|ax|test)es$' : "$1is",
'(shoe)s$' : "$1",
'(o)es$' : "$1",
'(bus)es$' : "$1",
'([m|l])ice$' : "$1ouse",
'(x|ch|ss|sh)es$' : "$1",
'(m)ovies$' : "$1ovie",
'(s)eries$' : "$1eries",
'([^aeiouy]|qu)ies$' : "$1y",
'([lr])ves$' : "$1f",
'(tive)s$' : "$1",
'(hive)s$' : "$1",
'(li|wi|kni)ves$' : "$1fe",
'(shea|loa|lea|thie)ves$': "$1f",
'(^analy)ses$' : "$1sis",
'((a)naly|(b)a|(d)iagno|(p)arenthe|(p)rogno|(s)ynop|(t)he)ses$': "$1$2sis",
'([ti])a$' : "$1um",
'(n)ews$' : "$1ews",
'(h|bl)ouses$' : "$1ouse",
'(corpse)s$' : "$1",
'(us)es$' : "$1",
's$' : ""
};
var irregular = {
'move' : 'moves',
'foot' : 'feet',
'goose' : 'geese',
'sex' : 'sexes',
'child' : 'children',
'man' : 'men',
'tooth' : 'teeth',
'person' : 'people'
};
var uncountable = [
'sheep',
'fish',
'deer',
'moose',
'series',
'species',
'money',
'rice',
'information',
'equipment'
];
// save some time in the case that singular and plural are the same
if(uncountable.indexOf(this.toLowerCase()) >= 0)
return this;
// check for irregular forms
for(word in irregular){
if(revert){
var pattern = new RegExp(irregular[word]+'$', 'i');
var replace = word;
} else{ var pattern = new RegExp(word+'$', 'i');
var replace = irregular[word];
}
if(pattern.test(this))
return this.replace(pattern, replace);
}
if(revert) var array = singular;
else var array = plural;
// check for matches using regular expressions
for(reg in array){
var pattern = new RegExp(reg, 'i');
if(pattern.test(this))
return this.replace(pattern, array[reg]);
}
return this;
}
易于使用：
alert("page".plural()); // return plural form => pages
alert("mouse".plural()); // return plural form => mice
alert("women".plural(true)); // return singular form => woman
演示
基于
@pmrotule答案，带有一些打字稿魔术和对不可数数组的一些补充。我在这里添加复数和单数函数。
复数版本：
/**
* Returns the plural of an English word.
*
* @export
* @param {string} word
* @param {number} [amount]
* @returns {string}
*/
export function plural(word: string, amount?: number): string {
if (amount !== undefined && amount === 1) {
return word
}
const plural: { [key: string]: string } = {
'(quiz)$' : "$1zes",
'^(ox)$' : "$1en",
'([m|l])ouse$' : "$1ice",
'(matr|vert|ind)ix|ex$' : "$1ices",
'(x|ch|ss|sh)$' : "$1es",
'([^aeiouy]|qu)y$' : "$1ies",
'(hive)$' : "$1s",
'(?:([^f])fe|([lr])f)$' : "$1$2ves",
'(shea|lea|loa|thie)f$' : "$1ves",
'sis$' : "ses",
'([ti])um$' : "$1a",
'(tomat|potat|ech|her|vet)o$': "$1oes",
'(bu)s$' : "$1ses",
'(alias)$' : "$1es",
'(octop)us$' : "$1i",
'(ax|test)is$' : "$1es",
'(us)$' : "$1es",
'([^s]+)$' : "$1s"
}
const irregular: { [key: string]: string } = {
'move' : 'moves',
'foot' : 'feet',
'goose' : 'geese',
'sex' : 'sexes',
'child' : 'children',
'man' : 'men',
'tooth' : 'teeth',
'person' : 'people'
}
const uncountable: string[] = [
'sheep',
'fish',
'deer',
'moose',
'series',
'species',
'money',
'rice',
'information',
'equipment',
'bison',
'cod',
'offspring',
'pike',
'salmon',
'shrimp',
'swine',
'trout',
'aircraft',
'hovercraft',
'spacecraft',
'sugar',
'tuna',
'you',
'wood'
]
// save some time in the case that singular and plural are the same
if (uncountable.indexOf(word.toLowerCase()) >= 0) {
return word
}
// check for irregular forms
for (const w in irregular) {
const pattern = new RegExp(`${w}$`, 'i')
const replace = irregular[w]
if (pattern.test(word)) {
return word.replace(pattern, replace)
}
}
// check for matches using regular expressions
for (const reg in plural) {
const pattern = new RegExp(reg, 'i')
if (pattern.test(word)) {
return word.replace(pattern, plural[reg])
}
}
return word
}
和单数版本：
/**
* Returns the singular of an English word.
*
* @export
* @param {string} word
* @param {number} [amount]
* @returns {string}
*/
export function singular(word: string, amount?: number): string {
if (amount !== undefined && amount !== 1) {
return word
}
const singular: { [key: string]: string } = {
'(quiz)zes$' : "$1",
'(matr)ices$' : "$1ix",
'(vert|ind)ices$' : "$1ex",
'^(ox)en$' : "$1",
'(alias)es$' : "$1",
'(octop|vir)i$' : "$1us",
'(cris|ax|test)es$' : "$1is",
'(shoe)s$' : "$1",
'(o)es$' : "$1",
'(bus)es$' : "$1",
'([m|l])ice$' : "$1ouse",
'(x|ch|ss|sh)es$' : "$1",
'(m)ovies$' : "$1ovie",
'(s)eries$' : "$1eries",
'([^aeiouy]|qu)ies$' : "$1y",
'([lr])ves$' : "$1f",
'(tive)s$' : "$1",
'(hive)s$' : "$1",
'(li|wi|kni)ves$' : "$1fe",
'(shea|loa|lea|thie)ves$': "$1f",
'(^analy)ses$' : "$1sis",
'((a)naly|(b)a|(d)iagno|(p)arenthe|(p)rogno|(s)ynop|(t)he)ses$': "$1$2sis",
'([ti])a$' : "$1um",
'(n)ews$' : "$1ews",
'(h|bl)ouses$' : "$1ouse",
'(corpse)s$' : "$1",
'(us)es$' : "$1",
's$' : ""
}
const irregular: { [key: string]: string } = {
'move' : 'moves',
'foot' : 'feet',
'goose' : 'geese',
'sex' : 'sexes',
'child' : 'children',
'man' : 'men',
'tooth' : 'teeth',
'person' : 'people'
}
const uncountable: string[] = [
'sheep',
'fish',
'deer',
'moose',
'series',
'species',
'money',
'rice',
'information',
'equipment',
'bison',
'cod',
'offspring',
'pike',
'salmon',
'shrimp',
'swine',
'trout',
'aircraft',
'hovercraft',
'spacecraft',
'sugar',
'tuna',
'you',
'wood'
]
// save some time in the case that singular and plural are the same
if (uncountable.indexOf(word.toLowerCase()) >= 0) {
return word
}
// check for irregular forms
for (const w in irregular) {
const pattern = new RegExp(`${irregular[w]}$`, 'i')
const replace = w
if (pattern.test(word)) {
return word.replace(pattern, replace)
}
}
// check for matches using regular expressions
for (const reg in singular) {
const pattern = new RegExp(reg, 'i')
if (pattern.test(word)) {
return word.replace(pattern, singular[reg])
}
}
return word
}
ECMA 的新 intl API 规范将提供复数规则功能，https://github.com/tc39/proposal-intl-plural-rules
这是今天可以使用的填充 https://github.com/eemeli/IntlPluralRules
摘
自我博客：https://sergiotapia.me/pluralizing-strings-in-javascript-es6-b5d4d651d403
您可以为此使用复数库。
NPM:
npm install pluralize --save
Yarn:
yarn add pluralize
无论您想在哪里使用库，都可以轻松要求它。
var pluralize = require('pluralize')
我喜欢将其添加到窗口对象中，这样我就可以在需要的地方调用 pluralize（）。在我的应用程序中.js根文件：
window.pluralize = require('pluralize')
然后你可以在任何地方使用它，React组件，或者只是普通的Javascript：
<span className="pull-left">
{`${item.score} ${pluralize('point', item.score)}`}
</span>
console.log(pluralize('point', item.score))
我使用这个简单的内联语句
const number = 2;
const string = `${number} trutle${number === 1 ? "" : "s"}`; //this one
console.log(string)我创建了一个非常简单的库，可用于JavaScript中的单词复数。它透明地将 CLDR 数据库用于多个区域设置，因此它几乎支持您想要使用的任何语言。它的API非常简约，集成非常简单。它被称为无数。
我还写了一篇小的介绍文章："如何使用JavaScript复数不同语言中的任何单词？"。
随意在您的项目中使用它。我也很高兴您对此的反馈。
要提供一个简单易读的选项 （ES6）：
export function pluralizeAndStringify(value, word, suffix = 's'){
if (value == 1){
return value + ' ' + word;
}
else {
return value + ' ' + word + suffix;
}
}
如果你给出类似pluralizeAndStringify(5, 'dog')的东西，你会得到"5只狗"作为你的输出。
如果单词以 y 结尾，请使用 -ies 或 -s（取决于倒数第二个字母），如果单词以 -s、-ss、-sh、-ch、-x 或 -z 结尾，请使用 -es，如果世界是不规则复数形式，请使用查找表，否则使用 -s。
var pluralize = (function () {
const vowels = "aeiou";
const irregulars = { "addendum": "addenda", "aircraft": "aircraft", "alumna": "alumnae", "alumnus": "alumni", "analysis": "analyses", "antenna": "antennae", "antithesis": "antitheses", "apex": "apices", "appendix": "appendices", "axis": "axes", "bacillus": "bacilli", "bacterium": "bacteria", "basis": "bases", "beau": "beaux", "bison": "bison", "bureau": "bureaux", "cactus": "cacti", "château": "châteaux", "child": "children", "codex": "codices", "concerto": "concerti", "corpus": "corpora", "crisis": "crises", "criterion": "criteria", "curriculum": "curricula", "datum": "data", "deer": "deer", "diagnosis": "diagnoses", "die": "dice", "dwarf": "dwarves", "ellipsis": "ellipses", "erratum": "errata", "faux pas": "faux pas", "fez": "fezzes", "fish": "fish", "focus": "foci", "foot": "feet", "formula": "formulae", "fungus": "fungi", "genus": "genera", "goose": "geese", "graffito": "graffiti", "grouse": "grouse", "half": "halves", "hoof": "hooves", "hypothesis": "hypotheses", "index": "indices", "larva": "larvae", "libretto": "libretti", "loaf": "loaves", "locus": "loci", "louse": "lice", "man": "men", "matrix": "matrices", "medium": "media", "memorandum": "memoranda", "minutia": "minutiae", "moose": "moose", "mouse": "mice", "nebula": "nebulae", "nucleus": "nuclei", "oasis": "oases", "offspring": "offspring", "opus": "opera", "ovum": "ova", "ox": "oxen", "parenthesis": "parentheses", "phenomenon": "phenomena", "phylum": "phyla", "quiz": "quizzes", "radius": "radii", "referendum": "referenda", "salmon": "salmon", "scarf": "scarves", "self": "selves", "series": "series", "sheep": "sheep", "shrimp": "shrimp", "species": "species", "stimulus": "stimuli", "stratum": "strata", "swine": "swine", "syllabus": "syllabi", "symposium": "symposia", "synopsis": "synopses", "tableau": "tableaux", "thesis": "theses", "thief": "thieves", "tooth": "teeth", "trout": "trout", "tuna": "tuna", "vertebra": "vertebrae", "vertex": "vertices", "vita": "vitae", "vortex": "vortices", "wharf": "wharves", "wife": "wives", "wolf": "wolves", "woman": "women", "guy": "guys", "buy": "buys", "person": "people" };
function pluralize(word) {
word = word.toLowerCase();
if (irregulars[word]) {
return irregulars[word];
}
if (word.length >= 2 && vowels.includes(word[word.length - 2])) {
return word + "s";
}
if (word.endsWith("s") || word.endsWith("sh") || word.endsWith("ch") || word.endsWith("x") || word.endsWith("z")) {
return word + "es";
}
if (word.endsWith("y")) {
return word.slice(0, -1) + "ies";
}
return word + "s";
}
return pluralize;
})();
////////////////////////////////////////
console.log(pluralize("dog"));
console.log(pluralize("cat"));
console.log(pluralize("fox"));
console.log(pluralize("dwarf"));
console.log(pluralize("guy"));
console.log(pluralize("play"));显然，这不能支持所有英语边缘情况，但它具有最常见的边缘情况。
function pluralize( /* n, [ n2, n3, ... ] str */ ) {
var n = Array.prototype.slice.call( arguments ) ;
var str = n.pop(), iMax = n.length - 1, i = -1, j ;
str = str.replace( /'$'$|'$('d+)/g,
function( m, p1 ) { return m == '$$' ? '$' : n[+p1-1] }
) ;
return str.replace( /[(](.*?)([+-])('d*)(?:,([^,)]*))?(?:,([^)]*))?[)]/g,
function( match, one, sign, abs, not1, zero ) {
// if abs, use indicated element in the array of numbers
// instead of using the next element in sequence
abs ? ( j = +abs - 1 ) : ( i < iMax && i++, j = i ) ;
if ( zero != undefined && n[j] == 0 ) return zero ;
return ( n[j] != 1 ) == ( sign == '+' ) ? ( not1 || 's' ) : one ;
}
) ;
}
console.log( pluralize( 1, 'the cat(+) live(-) outside' ) ) ;
// the cat lives outside
console.log( pluralize( 2, 'the child(+,ren) (is+,are) inside' ) ) ;
// the children are inside
console.log( pluralize( 0, '$1 dog(+), ($1+,$1,no) dog(+), ($1+,$1,no) dog(+,,)' ) ) ;
// 0 dogs, no dogs, no dog
console.log( pluralize( 100, 1, '$1 penn(y+,ies) make(-1) $$$2' ) ) ;
// 100 pennies make $1
console.log( pluralize( 1, 0.01, '$1 penn(y+,ies) make(-1) $$$2' ) ) ;
// 1 penny makes $0.01
使用 @sarink 的答案，我创建了一个函数，使用键值对数据并复数键来创建字符串。这是代码片段：
// Function to create a string from given key value pairs and pluralize keys
const stringPluralize = function(data){
var suffix = 's';
var str = '';
$.each(data, function(key, val){
if(str != ''){
str += val>0 ? ` and ${val} ${key}${val !== 1 ? suffix : ''}` : '';
}
else{
str = val>0 ? `${val} ${key}${val !== 1 ? suffix : ''}` : '';
}
});
return str;
}
var leftDays = '1';
var leftHours = '12';
var str = stringPluralize({day:leftDays, hour:leftHours});
console.log(str) // Gives 1 day and 12 hours
我也迟到了，但这适用于英语单词或西班牙语：
String.prototype.pluralize = function(count, plural = 's') {
return count === 1 ? this : plural.length > 2 ? plural : this + plural
};
这样，您可以使用任何字符串，如下所示：
"Apple".pluralize(1) // Apple
"Apple".pluralize(2) // Apples
"Company".pluralize(1, "Companies") // Company
"Company".pluralize(5, "Companies") // Companies
"Tooth".pluralize(1, "Teeth") // Tooth
"Tooth".pluralize(2, "Teeth") // Teeth
一些西班牙语：
"arbol".pluralize(1,"es") // arbol
"arbol".pluralize(2,"es") // arboles
"manzana".pluralize(1) // manzana
"manzana".pluralize(2) // manzanas
简明版本：
`${x} minute${x - 1 ? 's' : ''}`
我参加这个派对有点晚了，但这可以用非常少的代码很好地工作：
const pluralize = (count, single, plural) => `${count} ${count !== 1 ? plural || single+'s' : single}`;
提供任一单词：
pluralize(1, 'house');
// Output: 1 house
pluralize(2, 'house');
// Output: 2 houses
或者，2 个字符串表示具有不同结尾的单词：
pluralize(1, 'company', 'companies');
// Output: 1 company
pluralize(2, 'company', 'companies');
// Output: 2 companies
pluralize(100000, "fish", "fish");
// Output: 100000 fish
pluralize(2, "piece of furniture", "pieces of furniture");
// Output: 2 pieces of furniture
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