简单 HTML 表单创建循环中的永恒循环

Eternal loop in a simple HTML-form-creating loop

本文关键字:循环 永恒 创建 HTML 表单 简单      更新时间:2023-09-26

我正在尝试制作这个从 JSON 数据中创建 3 个多项选择题的简单代码,出于我无法理解的原因,发生的事情是一个永恒的循环,其中最后一个问题一次又一次地写入页面,直到它崩溃......帮助和建议将不胜感激。

var questions = {
"qestion":["what is bla?", "what is bla bla?", "what is bla bla bla?"],
"answerswer":[["aaa","bbb","ccc","ddd"], ["eee","fff","ggg","hhh"], ["zzz","xxx","yyy","www"]],
"correctAns":[1,2,3]};
String.prototype.format = function() {
    var formatted = this;
    for (i=0; i< arguments.length; i++) {
        var regexp = new RegExp('''{'+i+'''}', 'gi');
        formatted = formatted.replace(regexp, arguments[i]);
        }
    return formatted;
};
function writeQuestions() {
    for (i=0 ;i<=2; i++) {
            answerRdy = [];
            qestionRdy = questions.qestion[i];
            answerRdy[0] = questions.answer[i][0];
            answerRdy[1] = questions.answer[i][1];
            answerRdy[2] = questions.answer[i][2];
            answerRdy[3] = questions.answer[i][3];
            divID = "question-" + i;
                writeAnswer = [];
                writeAnswer[writeAnswer.length] = ("'n<div id='{0}'>'n<form method='post' onsubmit='return validate(this);'>'n").format(divID);
                writeAnswer[writeAnswer.length] = ("<b>" + qestionRdy + "</b><br />'n");
            for (n=0; n<=3; n++) {
                writeAnswer[writeAnswer.length] = ("<input type='radio' name='answer' value='{0}' /> {1} <br />'n").format(n, answerRdy[n]);
                    }
                writeAnswer[writeAnswer.length] = ("<input type='submit' value='Submit your answer'>'n</form>'n</div><!--{0}-->").format(divID);

            joinQuestion = writeAnswer.join();
                exp = /,/gi;
            fullQuestion = joinQuestion.replace(exp, "");
        $('#container').append(fullQuestion);
    }
}

我更改了循环以声明用于迭代的局部变量,并将终止长度链接到适当的对象,这似乎可以解决问题。 例如:

for (i=0 ;i<=2; i++) {

成为:

for (var i = 0, len = questions.answer.length; i < len; i++) {

请参阅示例→

可能是因为你有两个使用未声明的魔术全局变量"i"的 for 循环

for (i=0...

它最有可能在哪里

for (var i=0...