解析 - JavaScript 指针查询，从指针返回解析对象的问题

我有一个带有多个指针的类，我想在响应中返回它们的完整对象（如SQL中的连接）。 下面的示例这样做，但它返回 JSON 而不是 Parse 对象。 如何从指针返回包含每个 Parse 对象的对象数组，而无需对每个指针进行额外的查询？

    query.find().then(function(results){
        /* Go Through Each Comment*/
        var commentsArray = new Array();
        for(i in results){
            /* Set obj to current comment*/
            var obj = results[i];
            /* Get Post's Name */
            var postName = obj.get("post").get("postName");
            /* Get Post's Message */
            var postMsg = obj.get("post").get("postMsg");
            /* Get Post Author's Name */
            var authorName = obj.get("post").get("postAuthor").get("name");
            /* Get Comment's Message */
            var commentMsg = obj.get("msg");
            /* Get Comment's Author*/
            var commentAuthor = obj.get("user").get("name");
            /* Let's Put the Comment Information in an Array as an Object*/
            commentsArray.push({
                post:{
                    name: postName,
                    msg: postMsg
                },
                author: authorName,
                comment: {
                    author: commentAuthor,
                    msg: commentMsg
                }
            });
        }
    })

已编辑（我在客户端上使用 Swift 构建）：

var query = new Parse.Query("Profile");
query.equalTo("objectId", objectId);
query.find().then(function(profile) {
  response.success(profile)  // Returns profile parse object
}, function(error) {
  response.error(error);
});

//RETURNS
"<Profile: 0x153f96570, objectId: HKdukNBlmA, localId: (null)> {'n}"

Parse.Cloud.define("getProfiles", function(request, response) {
  var query = new Parse.Query("Profile");
  query.include("friendId");
  query.find().then(function(profiles) {
    var res = [];
    profiles.forEach(function(profile) {
      var obj = {
        firstName: profile.get("firstName"),
        lastName: profile.get("lastName"),
        age: profile.get("age"),
        gender: profile.get("gender")
      };
      obj.friend = {
        firstName: profile.get("friendId").get("firstName"),
        lastName: profile.get("friendId").get("lastName"),
      };
      res.push(obj);
    });
    response.success(res);
  }, function(error) {
    response.error("Error: " + error.code + " " + error.message);
  });
});

// RETURNS
[{
  firstName: "bob",
  lastName: "smith",
  age: 19,
  gender: male
  friend: {
    firstName: "tim",
    lastName: "wang",
  }
},
{
  firstName: "chris",
  lastName: "scalia",
  age: 24,
  gender: male
  friend: {
    firstName: "ben",
    lastName: "calder",
  }
}]

我更喜欢前者。