向除发件人以外的所有客户端发送响应
Send response to all clients except sender
要向所有客户端发送内容,请使用:
io.sockets.emit('response', data);
要从客户端接收,请使用:
socket.on('cursor', function(data) {
...
});
如何将这两者结合起来,以便在从客户端在服务器上接收消息时,将该消息发送给除发送消息的用户之外的所有用户?
socket.on('cursor', function(data) {
io.sockets.emit('response', data);
});
我是否必须通过发送客户端 ID 和消息然后在客户端检查来破解它,或者有更简单的方法?
这是我的列表(针对 1.0 更新):
// sending to sender-client only
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.emit('message', "this is a test");
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');
// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');
// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');
// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
// list socketid
for (var socketid in io.sockets.sockets) {}
OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});
从@LearnRPG答案中,但使用 1.0:
// send to current request socket client
socket.emit('message', "this is a test");
// sending to all clients, include sender
io.sockets.emit('message', "this is a test"); //still works
//or
io.emit('message', 'this is a test');
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');
// sending to all clients in 'game' room(channel), include sender
// docs says "simply use to or in when broadcasting or emitting"
io.in('game').emit('message', 'cool game');
// sending to individual socketid, socketid is like a room
socket.broadcast.to(socketid).emit('message', 'for your eyes only');
为了回答@Crashalot评论,socketid
来自:
var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })
以下是关于从 0.9.x 到 1.x 的变化的更完整的答案。
// send to current request socket client
socket.emit('message', "this is a test");// Hasn't changed
// sending to all clients, include sender
io.sockets.emit('message', "this is a test"); // Old way, still compatible
io.emit('message', 'this is a test');// New way, works only in 1.x
// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");// Hasn't changed
// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');// Hasn't changed
// sending to all clients in 'game' room(channel), include sender
io.sockets.in('game').emit('message', 'cool game');// Old way, DOES NOT WORK ANYMORE
io.in('game').emit('message', 'cool game');// New way
io.to('game').emit('message', 'cool game');// New way, "in" or "to" are the exact same: "And then simply use to or in (they are the same) when broadcasting or emitting:" from http://socket.io/docs/rooms-and-namespaces/
// sending to individual socketid, socketid is like a room
io.sockets.socket(socketid).emit('message', 'for your eyes only');// Old way, DOES NOT WORK ANYMORE
socket.broadcast.to(socketid).emit('message', 'for your eyes only');// New way
我想编辑@soyuka的帖子,但我的编辑被同行评审拒绝了。
发出备忘单
io.on('connect', onConnect);
function onConnect(socket){
// sending to the client
socket.emit('hello', 'can you hear me?', 1, 2, 'abc');
// sending to all clients except sender
socket.broadcast.emit('broadcast', 'hello friends!');
// sending to all clients in 'game' room except sender
socket.to('game').emit('nice game', "let's play a game");
// sending to all clients in 'game1' and/or in 'game2' room, except sender
socket.to('game1').to('game2').emit('nice game', "let's play a game (too)");
// sending to all clients in 'game' room, including sender
io.in('game').emit('big-announcement', 'the game will start soon');
// sending to all clients in namespace 'myNamespace', including sender
io.of('myNamespace').emit('bigger-announcement', 'the tournament will start soon');
// sending to individual socketid (private message)
socket.to(<socketid>).emit('hey', 'I just met you');
// sending with acknowledgement
socket.emit('question', 'do you think so?', function (answer) {});
// sending without compression
socket.compress(false).emit('uncompressed', "that's rough");
// sending a message that might be dropped if the client is not ready to receive messages
socket.volatile.emit('maybe', 'do you really need it?');
// sending to all clients on this node (when using multiple nodes)
io.local.emit('hi', 'my lovely babies');
};
broadcast.emit 将消息发送到所有其他客户端(发件人除外)
socket.on('cursor', function(data) {
socket.broadcast.emit('msg', data);
});
对于房间内的命名空间,循环访问房间中的客户端列表(类似于 Nav 的答案)是我发现的仅有的两种可行的方法之一。 另一种是使用排除。 例如
socket.on('message',function(data) {
io.of( 'namespace' ).in( data.roomID ).except( socket.id ).emit('message',data);
}
V4.x 中服务器端所有有效的发出事件列表
io.on("connection", (socket) => {
// basic emit
socket.emit(/* ... */);
// to all clients in the current namespace except the sender
socket.broadcast.emit(/* ... */);
// to all clients in room1 except the sender
socket.to("room1").emit(/* ... */);
// to all clients in room1 and/or room2 except the sender
socket.to(["room1", "room2"]).emit(/* ... */);
// to all clients in room1
io.in("room1").emit(/* ... */);
// to all clients in room1 and/or room2 except those in room3
io.to(["room1", "room2"]).except("room3").emit(/* ... */);
// to all clients in namespace "myNamespace"
io.of("myNamespace").emit(/* ... */);
// to all clients in room1 in namespace "myNamespace"
io.of("myNamespace").to("room1").emit(/* ... */);
// to individual socketid (private message)
io.to(socketId).emit(/* ... */);
// to all clients on this node (when using multiple nodes)
io.local.emit(/* ... */);
// to all connected clients
io.emit(/* ... */);
// WARNING: `socket.to(socket.id).emit()` will NOT work, as it will send to everyone in the room
// named `socket.id` but the sender. Please use the classic `socket.emit()` instead.
// with acknowledgement
socket.emit("question", (answer) => {
// ...
});
// without compression
socket.compress(false).emit(/* ... */);
// a message that might be dropped if the low-level transport is not writable
socket.volatile.emit(/* ... */);
});
客户端
// basic emit
socket.emit(/* ... */);
// with acknowledgement
socket.emit("question", (answer) => {
// ...
});
// without compression
socket.compress(false).emit(/* ... */);
// a message that might be dropped if the low-level transport is not writable
socket.volatile.emit(/* ... */);
指向源的存档链接 => http://archive.today/2021.06.22-023900/https://socket.io/docs/v4/emit-cheatsheet/index.html
其他情况
io.of('/chat').on('connection', function (socket) {
//sending to all clients in 'room' and you
io.of('/chat').in('room').emit('message', "data");
};
更新了列表以获取更多文档。
socket.emit('message', "this is a test"); //sending to sender-client only
socket.broadcast.emit('message', "this is a test"); //sending to all clients except sender
socket.broadcast.to('game').emit('message', 'nice game'); //sending to all clients in 'game' room(channel) except sender
socket.to('game').emit('message', 'enjoy the game'); //sending to sender client, only if they are in 'game' room(channel)
socket.broadcast.to(socketid).emit('message', 'for your eyes only'); //sending to individual socketid
io.emit('message', "this is a test"); //sending to all clients, include sender
io.in('game').emit('message', 'cool game'); //sending to all clients in 'game' room(channel), include sender
io.of('myNamespace').emit('message', 'gg'); //sending to all clients in namespace 'myNamespace', include sender
socket.emit(); //send to all connected clients
socket.broadcast.emit(); //send to all connected clients except the one that sent the message
socket.on(); //event listener, can be called on client to execute on server
io.sockets.socket(); //for emiting to specific clients
io.sockets.emit(); //send to all connected clients (same as socket.emit)
io.sockets.on() ; //initial connection from a client.
希望这有帮助。
针对 Socket.io v4.0.0+ 进行了更新
若要在 v4 中向除发送方之外的所有客户端发出,请使用:
socket.broadcast.emit(/* ... */);
示例用法
io.on("connection", (socket) => {
socket.on("message", (message) => {
//sends "newMessage" to all sockets except sender
socket.broadcast.emit("newMessage", message)
})
})
使用此编码
io.sockets.on('connection', function (socket) {
socket.on('mousemove', function (data) {
socket.broadcast.emit('moving', data);
});
这个socket.broadcast.emit()将在函数中发出除发射的服务器之外的所有东西
我正在使用命名空间和房间 - 我发现
socket.broadcast.to('room1').emit('event', 'hi');
在何处工作
namespace.broadcast.to('room1').emit('event', 'hi');
冇
(如果其他人遇到这个问题)
相关文章:
- 使用 RESTful API,如果未定义特定的响应 json 级别,我如何在客户端不出错
- 可以't为客户端形成正确的JSON响应
- 从服务器到客户端的响应状态
- node.js+MySQL;JSON结果-回调问题&没有响应客户端
- 将简单的Perl脚本翻译成Python,向客户端发送响应
- Nodejs-websocket:如何在没有服务器响应的情况下连续发送客户端消息
- 在转发到代理目标并将响应发送回客户端之前,编辑POST参数
- 如何在谷歌地图服务的Go客户端中使用方向响应
- 客户端始终响应上一个服务器发送的事件,而不是当前事件
- Socket.io 和 Nodejs:向多个客户端发送响应并且更改未保存(?
- 如何在一个 Http 响应中将多个 mime 类型返回到 Web 客户端
- 如何使用 socket.io 等待客户端响应
- Socket.io 客户端:使用一个处理程序响应所有事件
- 如何在响应 Angular 客户端应用时发送 API 密钥
- 服务器发送事件如何将响应发送到特定客户端
- 节点.js xmpp 客户端收到“BAD_REGISTRATION”错误作为消息响应
- 向除发件人以外的所有客户端发送响应
- 节点ACS 404未找到Java http客户端的响应代码
- 为什么在未读取响应的情况下,节点http客户端仍在运行
- 与node.js我如何设置var从HTTP客户端响应