如何用javascript获取servlet响应

how to get servlet response in javascript?

本文关键字：servlet 响应 获取 javascript 何用      更新时间：2023-09-26

如何在javascript变量中获取servlet响应消息有没有可能在java脚本中获取响应消息的方法？

Html:
<form method="post" id="importForm">
Name<input type="text" name="name"/>
<input type="submit" onclick="importScenarioFromServer();">
</form>
javascript:
function importScenarioFromServer(){
    var result = document.forms["importForm"].submit();
}
servlet:
int numberOfRecs = db.setDBValue(dMap);
if (numberOfRecs == 1) {
String result = "success";
response.getWriter().print(result);
}

这可以在javascript中使用ajax或使用jquery来实现。我们可以在ajax命中中序列化表单，然后在成功事件回调函数中从servlet获取响应数据。下面是一个例子。。。

function getData()
{
var client;
var data;
var url_action="/temp/getData";
if(window.XMLHttpRequest)
{
    client=new XMLHttpRequest();
}
else
{
    client=new ActiveXObject("Microsoft.XMLHTTP");
}
client.onreadystatechange=function()
{
    if (client.readyState==4 && client.status==200)
    {
         document.getElementById("response").innerHTML=client.responseText; 
    }
};
data="name="+document.getElementById("name").value+"&file="+document.getElementById("filname").value;
client.open("POST",url_action,true);
client.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
client.send(data);
}

Servlet post method
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
    PrintWriter out=response.getWriter();
    log.info("Good");
    out.println("Good to go");
}
相关文章：