javascript计算日期范围的价格

我有一个关于javascript时间范围的问题

我有两个输入框，客户可以给出开始日期和结束日期

下面有3个季节的日期范围，我需要计算用户输入的日期范围的成本价格低于季节的映射

总共是3个季节，下面是日期范围：

淡季

5月1日至6月30日9月1日至12月14日

成本：每天5美元

---

旺季

1月11日至4月30日7月1日至8月31日

成本：每天10美元

---

旺季

-12月15日至1月10日成本：每天2美元

我写了一个代码来获取日期输入

$('#calculate').click(function(){
//get the first date
da=$('#daydropdowna').val();
ma=$('#monthdropdowna').val();
ya=$('#yeardropdowna').val();

//get the secnd date
dd=$('#daydropdownd').val();
md=$('#monthdropdownd').val();
yd=$('#yeardropdownd').val();

var oneDay = 24*60*60*1000; 
var ourstart= new Date(ya,ma,da);
var oursend= new Date(yd,md,dd);

/*
11th January to 30th April 
1st July to 31st August 
*/
var hsstart= new Date(ya,00,11);
var hsend= new Date(ya,03,11);
var hsstart1= new Date(ya,06,01);
var hsend1= new Date(ya,07,31);

/*
1st May to 30th June 
1st September to 14th December 
*/
var lsstart=new Date(ya,04,01);
var lsend=new Date(ya,05,30);
var lsstart1=Date(ya,08,01);
var lsend1=new Date(ya,11,14);

/*
-15th December - 10th January 
*/
var psstart=new Date(ya,11,15);
var psend=new Date(ya+1,00,10);

var myDate = ourstart;
var myDate1 = oursend;


var startDate = hsstart
var endDate = hsend

//the date range within one high season
if ((startDate < myDate) && (myDate < endDate) && (startDate < myDate1) && (myDate1 < endDate)) {
        alert('seasn 1 h');
       var diffDays = Math.round(Math.abs((myDate1 .getTime() - myDate .getTime())/(oneDay)));
alert (diffDays);
}

//the date range within secnd high season
var startDate = hsstart1
var endDate = hsend1
if ((startDate < myDate) && (myDate < endDate) && (startDate < myDate1) && (myDate1 < endDate)) {
        alert('seasn 2 h');
       var diffDays = Math.round(Math.abs((myDate1 .getTime() - myDate .getTime())/(oneDay)));
alert (diffDays);
}

//the date range within first low season
var startDate = lsstart
var endDate = lsend
if ((startDate < myDate) && (myDate < endDate) && (startDate < myDate1) && (myDate1 < endDate)) {
        alert('season 1 l');
       var diffDays = Math.round(Math.abs((myDate1 .getTime() - myDate .getTime())/(oneDay)));
alert (diffDays);
}

//the date range within second low season
var startDate = lsstart1
var endDate = lsend1

if ((startDate < myDate) && (myDate < endDate) && (startDate < myDate1) && (myDate1 < endDate)) {
        alert('season 2 l');
       var diffDays = Math.round(Math.abs((myDate1 .getTime() - myDate .getTime())/(oneDay)));
alert (diffDays);
}
//peak
var startDate = psstart
var endDate = psend
if ((startDate < myDate) && (myDate < endDate) && (startDate < myDate1) && (myDate1 < endDate)) {
        alert('season p');
       var diffDays = Math.round(Math.abs((myDate1 .getTime() - myDate .getTime())/(oneDay)));
alert (diffDays);
}

//if not wihin a specific range cacuate for all





});

所以我需要根据用户输入来计算总价，Ex用户输入2012-05-05-2013-01-05这需要计算3个季节日期的价格，这涵盖了日期范围。请帮我解决这个问题，谢谢。。。

tempDate = inputStartDate
for each season
    if seasonStart <= tempDate
        if inputEndDate <= seasonEnd
            price = price + (inputEndDate - tempDate) * seasonCost
            break
        else
            price = price + (seasonEnd - tempDate) * seasonCost
            tempDate = seasonEnd + 1 day

var peakSeason = {startDate: w/e, endDate: w/e, numDays: w/e, costRatePerDay: w/e}
var lowSeason1 = {startDate: w/e, endDate: w/e, numDays: w/e, costRatePerDay: w/e}
var lowSeason2 = {startDate: w/e, endDate: w/e, numDays: w/e, costRatePerDay: w/e}
// .... etc
var allSeasons = [peakSeason, lowSeason1, ...] // put these in order and it can help iterating date ranges between
var numberDaysStartFromEndOfRange = function(startDate) {
    // iterate through the allSeasons map and find what range this is in 
    // return {numDays: whateverYouCalculate, dateRange: name your date ranges uniquely}
}
var numberDaysEndFromStartOfRange = function(startDate) {
    // iterate through the allSeasons map and find what range this is in
    // return {numDays: whateverYouCalculate, dateRange: name your date ranges uniquely}
}