从弹出窗口中使用php和javascript传递多个MySQL结果集

Passing multiple MySQL result set using php and javascript from a popup window

本文关键字：MySQL 结果 javascript 窗口 php      更新时间：2023-09-26

我正试图通过javascript将多个MySQL结果集数据从弹出页面传递到主页。

以下是我迄今为止所做的：

在我的popup.php页面中：

$sql = mysql_query("SELECT * from item
                    where category like '$category%'
                    and type like '$type%'");
$num = mysql_num_rows($sql);

<table align="center" border="1" cellpadding="10" cellspacing="5">
    <tr bgcolor = 'yellow'>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Select</font></th>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Item Desc</font></th>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Item Specification</font></th>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Item Rate</font></th>
    </tr>
<?php
    $i = 0;
    while ($i < $num) {
    $f1=mysql_result($sql,$i,"item");
    $f2=mysql_result($sql,$i,"specification");
    $f3=mysql_result($sql,$i,"rate");
?>
<tr>
<td><input type="checkbox" name="item" id="item" /></td>
<td align="center"><font face="Arial, Helvetica, sans-serif" color = 'red'><b><?php echo $f1; ?></font></b></td>
<td align="center"><font face="Arial, Helvetica, sans-serif" color = 'red'><b><?php echo $f2; ?></font></b></td>
<td align="center"><font face="Arial, Helvetica, sans-serif" color = 'red'><b><?php echo $f3; ?></font></b></td></tr>
<?php
  $i++;}
?>
<?php
echo('<input type="button" value="Select" id="button" onClick="passVariable('''.str_replace("'", "'''", $f1).''', '''.str_replace("'", "'''", $f2).''');">');

这里是passVariable函数：

function passVariable(name1, name2){
  //This code should be able to pass the entire selection list after user clicks on the check-button to the main.php.
}

在我的main.php中，我应该只得到用户选择结果集。

我想我需要使用arrays，但需要一些帮助。

我应该如何继续？

<?php if(isset($_POST[add])){ ?>
<?php foreach($_POST[item] as $t){ 
        $sql = mysql_query("SELECT * from item
                    where item=$t");
        //write code here to draw table based upon selected items
<} ?>
<?php }?>
<form name="form1" action="test.php" method="POST">
<table align="center" border="1" cellpadding="10" cellspacing="5">
<tr bgcolor = 'yellow'>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Select</font></th>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Item Desc</font></th>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Item Specification</font></th>
    <th align="center"><font face="Arial, Helvetica, sans-serif">Item Rate</font></th>
    </tr>
<?php
$sql = mysql_query("SELECT * from item
                    where category like '$category%'
                    and type like '$type%'");
$num = mysql_num_rows($sql);
$i = 0;
    while ($i < $num) {
    $f1=mysql_result($sql,$i,"item");
    $f2=mysql_result($sql,$i,"specification");
    $f3=mysql_result($sql,$i,"rate");
?>
<tr>
<td><input type="checkbox" name="item[]" id="item" value="<?php echo $f1; ?>"/></td>
<td align="center"><font face="Arial, Helvetica, sans-serif" color = 'red'><b><?php echo $f1; ?></font></b></td>
<td align="center"><font face="Arial, Helvetica, sans-serif" color = 'red'><b><?php echo $f2; ?></font></b></td>
<td align="center"><font face="Arial, Helvetica, sans-serif" color = 'red'><b><?php echo $f3; ?></font></b></td></tr>
<?php  $i++; 
}
?>
</table>
<input type="submit" name="add" value="Submit">
</form>
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