我如何限制广告商的次数'的广告在某一天用Javascript显示

以下是场景：

在我们的网站上，我们有3个广告商。广告商让我们为他们的产品收集电子邮件。

每个广告商每天收集的电子邮件数量上限为500封。一旦我们在一天内收到500封电子邮件，我们就需要停止显示广告商提供的内容。

为了构建广告商堆栈，我们有一个Javascript数组，用于确定为给定用户显示哪些广告商。我们把每个广告商都推到阵列中。如果我们没有广告商，我们会将用户重定向到另一个页面。

基本上，我需要做的是构建一个计数为"500"的迭代，如果我们在给定的一天内收到500封电子邮件，我们就不会向广告商显示。

// what offers will be show
var offer_order = [];
// what needs to be written is an iteration that counts up to '500', 
// then if its in a given day, do not show the respective offer
// add the advertisers to the order being shown 
// if ( cap <= '500' ) {
offer_order.push('advertiser-1');
// }
// if ( cap <= '300' ) {
offer_order.push('advertiser-2');
// }
// this offer has no cap, so it will always be shown
offer_order.push('advertiser-3');
// I removed all of the functionality that sets the starting offer
// and controls showing the next offer, so don't worry about this not working
// send lead data on submit
$('.submit').on('click', function() {
    $.ajax({    
        url: 'http://domain.com/send-data.php',
        data: $('#user_data').serialize(),
        type: 'POST',
    }).done(function(responseData) {
        // in our response data, we either get back 'success' or 'fail'             
        // we need to build our iteration here
        // if the beginning offer is equal to whats next, then were done, so lets move to the next page
        if ( next == $(starting_offer).data("start") ) {
            window.location.href = "<?php echo $next_page; ?>";
        }
    }).fail(function() {
        // if the beginning offer is equal to whats next, then were done, so lets move to the next page
        if ( next == $(starting_offer).data("start") ) {
            window.location.href = "<?php echo $next_page; ?>";
        }
    });