未捕获的类型错误:无法设置属性'src'为null的..选择你自己的冒险

Uncaught TypeError: Cannot set property 'src' of null...Choose your own adventure

本文关键字：src 选择 冒险 自己的 你自己 null 属性 类型 错误 设置      更新时间：2023-09-26

我只是在学习javascript，遇到了一些麻烦。我正在制作一款你自己选择的冒险游戏，让你穿过迷宫。有一些图片向你展示正在发生的事情。这些图片会在你做出每一个决定后发生变化。我在向左或向右输入后更改图片时遇到问题。我一直得到Uncaught TypeError:无法在每次尝试加载图片时设置null错误消息的属性"src"。Java表示问题发生在66号线

这是我的代码：

<!doctype html>
<html>
<head>
<meta charset="UTF-8">
<title>Brian.Bosco-Hazey Maze Adventure</title>
<script type="application/javascript">
var flag;
var output;
var name;
var n1 = "what is your name?"
var s1 = "You wake up in a spooky maze. You must find your way out or this place will become your grave. You can go <b>Left</b> or <b>Right</b>?";
var s2 = "You come across a wizard at a fork in the maze. He gives you a magic sword to defend yourself with. You can either go <b>Left</b> or <b>Right</b>?";
var e1 = "You encounter a monster. you attempt to escape, but it pounces on you and tears off your flesh. You have died. GAME OVER. Type restart to try again";
var e2 = "You come across a dead end, looks like you have to go back the way you came. When you turn around you step on a trap on the floor and the whole tunnel collapses on you. You did not survive. Please type restart to try again."
var e3 = "While walking down this long hallway, you come across a giant monster guarding the exit door. You take the sword the wizard gave you and you slay the beast. You go through the door and exit the maze. Congradulations you have beaten the game! Type restart to play again. ";
var done = "What are you doing? You are still dead. Type restart to start again";
var myImage;
var newImage;

function init(){
	output = document.getElementById('output');
	output.innerHTML="";
	flag="n1";
	texter(n1);
	name = "";
	document.body.style.background="white";
}
function texter(newText){
	console.log(newText+" from texter");
	var oldText = document.getElementById('output').innerHTML;
	document.getElementById('output').innerHTML= newText;//+" "+oldText;
}
function Imger(newImage){
	document.getElementById('img1').src = newImage;
	document.getElementById('img2').src = newImage;
}
function game(){
	var input = document.getElementById('input').value;
	console.log("the input is "+input);
	if(input=="restart"){
		init();
	}else{
		if(flag=="n1"){
			name = input;
			flag="s1";
			texter("hello "+name+" "+s1);
			document.getElementById('img1').src = "hooded man.jpg";
			output.style.color="blue";
		}else if(flag=="s1"){
			//ask c1
			if(input=="right"){
				flag="s2";
				texter(s2);
				
					
				document.body.style.background="green";
			}else if(input=="left"){
				texter(e1);
				flag ="e1";
				document.getElementById('img2').src = "last scene.jpg";
			
			}else{
				texter("error");
			}
		}else if(flag=="s2"){
			//ask c2
			if(input=="right"){
				flag="e2";
				texter(e2);
				
				document.body.style.background="red";
			}else if(input=="left"){
				texter(e3);
				flag ="e3";
				document.body.style.background="yellow";
			}else{
				texter("error");
			}
		}else if(flag=="e1"){
			//e1
			texter(done);
		}else if(flag=="e2"){
			//e2
			texter(done);
		}else if(flag=="e3"){
			//e3
			texter(done);
		}
	}
}
</script>
</head>
<body onLoad="init()">
<img src="start.jpg" id="img1" width="500" height="500">
<p id="output">this is the start text</p>
<input type="text" id="input">
<input type="button" value="submit" onClick="game()" ">
</body>
</html>

document.getElementById('img2').src = newImage;

HTML中没有id="img2"，所以document.getElementById('img2') == null。

你可以在img1:下加一个吗

<img src="start.jpg" id="img1" width="500" height="500">
<img src="start.jpg" id="img2" width="500" height="500">

或者你可以删除JS行：

document.getElementById('img2').src = newImage;

还有：

document.getElementById('img2').src = "last scene.jpg";

或者将其更改为：

document.getElementById('img1').src = "last scene.jpg";

我也遇到了同样的问题，我只是这样做了：

function Imger(newImage){
 document.getElementById('img1').src = newImage;
 if(document.getElementById('img2') != NULL){
  document.getElementById('img2').src = newImage;
 }
}

如果不是NULL，则仅使用。

if(image != NULL){
 image.src = 'image url';
}

尽管我不会有太多帮助，因为3年前有人问我这个问题，脚本实际上应该在img之后，img应该在它后面，而且它应该可能工作。我想说，你没有img2的id，但有人已经指出了这一点，如果他的建议不起作用，那就执行我的建议。

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