获取谷歌地图上一组标记的东北角和西南角
get NE and SW corners of a set of markers on a google map
我想在谷歌地图上获得一组标记的NE和SW角。在这里,我对每个标记进行迭代。谷歌或javascript是否提供了一个迭代次数较少的函数?
function fnSetBounds(){
var lowLat = 90;
var highLat = -90;
var lowLng = 180;
var highLng = -180;
for (var i = 0; i < myMarkers.length; i++) {
var myLat = myMarkers[i].position['k'];
var myLng = myMarkers[i].position['B'];
// catch low LAT
if (lowLat > myLat){
lowLat = myLat;
}
// catch high LAT
if (highLat < myLat) {
highLat = myLat;
}
// catch low LNG
if (lowLng > myLng){
lowLng = myLng;
}
// catch high lng
if (highLng < myLng) {
highLng = myLng;
}
}
var southWestCorner = new google.maps.LatLng(highLat, lowLng);
var northEastCorner = new google.maps.LatLng(lowLat, highLng);
var bounds = new google.maps.LatLngBounds();
bounds.extend(southWestCorner);
map.fitBounds(bounds);
bounds.extend(northEastCorner);
map.fitBounds(bounds);
}
我会这样做,将所有位置添加到一个空边界:
function fnSetBounds(){
var bounds = new google.maps.LatLngBounds();
for (var i = 0; i < myMarkers.length; i++) {
bounds.extend(myMarkers[i].getPosition());
}
map.fitBounds(bounds);
}