我在AnythingSlider中有一个AnythingSlider,我可以为两个滑块设置当前幻灯片的样式吗
I have an AnythingSlider within an AnythingSlider can I style the current slide for both sliders?
以下是示例:http://ashleybest.co.uk/mottie_is_the_best/index.html
我想做的是将幻灯片"一"上的链接("aaa"、"Bbbb"等)设置为与当前幻灯片上控制主滑块的外部链接相同的样式。幻灯片"一"上的链接控制右侧的第二个滑块。
这怎么可能?
以下是css的外观:
.link-1.current, .link-1:hover { text-decoration:underline; color:#BAA5EC; }
.link-2.current, .link-2:hover { text-decoration:underline; color:#BAA5EC; }
.link-3.current, .link-3:hover { text-decoration:underline; color:#BAA5EC; }
.link-4.current, .link-4:hover { text-decoration:underline; color:#BAA5EC; }
.link-a.current, .link-a:hover { text-decoration:underline; color:#BAA5EC; }
.link-b.current, .link-b:hover { text-decoration:underline; color:#BAA5EC; }
.link-c.current, .link-c:hover { text-decoration:underline; color:#BAA5EC; }
.link-d.current, .link-d:hover { text-decoration:underline; color:#BAA5EC; }
通过解决方案的演示
HTML
<table>
<tbody>
<tr>
<td id="sliderbg" valign="bottom">
<div class="nav1">
<a class="nav link-1" href="#1"><span>One</span></a>
<a class="nav link-2" href="#2"><span>Two</span></a>
<a class="nav link-3" href="#3"><span>Three</span></a>
<a class="nav link-4" href="#4"><span>Four</span></a>
</div>
<ul class="slider1">
<li>
<div class="nav2">
One:
<a class="nav link-a" href="#2">Aaaa</a> |
<a class="nav link-b" href="#3">Bbbb</a> |
<a class="nav link-c" href="#4">Cccc</a> |
<a class="nav link-d" href="#5">Dddd</a>
</div>
</li>
<li>Two</li>
<li>Three</li>
<li>Four</li>
</ul>
</td>
<td id="sliderbg" valign="bottom">
<ul class="slider2">
<li>Select an item on the left to view here</li>
<li>A</li>
<li>B</li>
<li>C</li>
<li>D</li>
</ul>
</td>
</tr>
</tbody>
</table>
CSS
.slider1, .slider2, .slider1 li, .slider2 li {
width: 300px;
height: 200px;
list-style: none;
}
#sliderbg {
background-color: #444;
color: #ddd;
}
.nav { text-decoration:none; color:#fff; }
.nav.current, .nav:hover { text-decoration:underline; color:#BAA5EC; }
编写脚本
$(function() {
$('.slider1').anythingSlider({
// If true, builds a list of anchor links to link to each panel
buildNavigation: false,
onInitialized: function(e, slider) {
$('.nav1').find('a').eq(slider.currentPage - 1).addClass('current');
},
onSlideInit: function(e, slider) {
$('.nav1').find('a').removeClass('current').eq(slider.targetPage - 1).addClass('current');
},
});
// set up external links
$('.nav1 a').click(function() {
var slide = $(this).attr('href').substring(1);
$('.slider1').anythingSlider(slide);
return false;
});
$('.slider2').anythingSlider({
// If true, builds a list of anchor links to link to each panel
buildNavigation: false,
onInitialized: function(e, slider) {
$('.nav2').find('a').eq(slider.currentPage - 1).addClass('current');
},
onSlideInit: function(e, slider) {
$('.nav2').find('a').removeClass('current')
// subtract 2 because we don't have a link to the first slide
.eq(slider.targetPage - 2).addClass('current');
},
});
// set up external links
$('.nav2 a').click(function() {
var slide = $(this).attr('href').substring(1);
$('.slider2').anythingSlider(slide);
return false;
});
});
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