在数组之间交换元素

Swap elements between arrays

本文关键字:元素 交换 之间 数组      更新时间:2023-09-26

我正试图从一个数组中删除项,然后添加到另一个数组。在某个阶段,我会将它们添加回原始数组。当我运行数组10次时,第10次没有返回完整数组=0的预期结果,移除数组=100;有人知道为什么会这样吗?

 var fullArr = [];//contains all items
 var remArr = [];//contains removed items
 var userAnswer = true;//this would be user input
 populateArray();
 runTenTimes();
 //getting the answer right 10 times should result in fullArr.length = 0; remArr.length = 100;
 function runTenTimes(){
     for(var i=0;i<10;i++){
     //console.log(i);
     checkUserAnswer();   
     }
 }
 function populateArray(){
     for(var i=0;i<100;i++){
         fullArr.push(i);
     }
 }
function checkUserAnswer(){
     if(userAnswer){//only if true
         for(i=0;i<10;i++){//10 because I remove 10 at a time
           removeShape(fullArr,fullArr[i],remArr);
         }
     }else{
          // add elements from remove arr
          // back into full array   
     }
     console.log("full array : " + fullArr.length);
     console.log("remove array : " + remArr.length);
     console.log("------------------")
 }
 function removeShape(arr,item,rem){
      for(var i = 0;i<arr.length; i++) {
           if(arr[i] === item) {
             rem.push(arr[i]);
             arr.splice(i, 1);
           }
      }   
 } 

http://jsfiddle.net/non_tech_guy/vy671jv4/

请使用此代码

var fullArr = [];//contains all items
 var remArr = [];//contains removed items
 var userAnswer = true;//this would be user input
 populateArray();
 runTenTimes();
 //getting the answer right 10 times should result in fullArr.length = 0; remArr.length = 100;
 function runTenTimes(){
     for(var i=0;i<10;i++){
     //console.log(i);
     checkUserAnswer();   
     }
 }
 function populateArray(){
     for(var i=0;i<100;i++){
         fullArr.push(i);
     }
 }
function checkUserAnswer(){
     if(userAnswer){//only if true
         var arrCopy = fullArr.slice(0);
         for(i=0;i<10;i++){//10 because I remove 10 at a time
           removeShape(fullArr,arrCopy[i],remArr);
         }
     }else{
          // add elements from remove arr
          // back into full array   
     }
     console.log("full array : " + fullArr.length);
     console.log("remove array : " + remArr.length);
     console.log("------------------")
 }
 function removeShape(arr,item,rem){
      for(var i = 0;i<arr.length; i++) {
           if(arr[i] === item) {
             rem.push(arr[i]);
             arr.splice(i, 1);
           }
      }   
 } 

更改为forEach仍然会产生错误,直到我更改了arr.shift()而不是arr.splice(I,0)。

function removeShape(arr,item,rem){
      arr.forEach(function(){
        if(arr[i] === item) {
             rem.push(arr.shift());
          }
       })
}