我如何才能确保;至“;日期总是晚于“;从“;日期

How can I ensure that a "to" date is always later than the "from" date?

本文关键字：日期确保更新时间：2023-09-26

在"开始"字段中，用户选择一个日期，在"结束"字段中日期不应小于"开始"域日期。

我怎样才能做到这一点？

<script type="text/javascript">
    $(document).ready(function() {
        $('.ui-datepicker-prev ui-corner-all').hide();
        $("#datepicker").datepicker({
            changeMonth: true,
            changeYear: true,
            yearRange: "-0:c+10",
            dateFormat: "dd - M - yy",
            onClose: function(selectedDate) {
                $('#datepicker1').datepicker("setDate", selectedDate);
            }
        });
        $('#datepicker').datepicker("setDate", new Date());
        $("#datepicker1").datepicker({
            changeMonth:false,
            yearRange: "-0:+0",
            dateFormat: "dd - M - yy"
        });
    });
</script>

以下是我的代码（到目前为止）：http://jsfiddle.net/Mounika_Garrepalli/8z2UH/

您可以通过将日期传递给函数来比较日期

var dt1_temp = date1.split("-");
var ctdt1 = new Date(dt1_temp[2],dt1_temp[1],dt1_temp[0]); // Y/m/d format
var dt2_temp = date2.split("-");
var ctdt2 = new Date(dt2_temp[2],dt2_temp[1],dt2_temp[0]);

现在我们可以比较的日期

if(ctdt1>ctdt2) {
alert("To date should not be equal or before the from date");
}

这是FIDDLE

        $(document).ready(function () {
        $('.ui-datepicker-prev ui-corner-all').hide();
        $("#datepicker").datepicker({
            changeMonth: true,
            changeYear: true,
            yearRange: "-0:c+10",
            dateFormat: "dd - M - yy",
            onClose: function (selectedDate) {
                $('#datepicker1').datepicker("setDate", selectedDate);
            }
        });
        $('#datepicker').datepicker("setDate", new Date());
        $("#datepicker1").datepicker({
            yearRange: "-0:+0",
            dateFormat: "dd - M - yy"
        });
        $('#datepicker').change(function () {
            checkDate($(this), $('#datepicker1'));
        });
        $('#datepicker1').change(function () {
            checkDate($('#datepicker'), $(this));
        });
    });
    function checkDate(date1, date2) {
        if (date1.val() > date2.val()) {
            alert('Error');
            date2.val(date1.val());
        }
    }

您可以使用minDate选项：

$("#datepicker1").datepicker({
    yearRange: "-0:+0",
    //Set the initial minDate
    minDate: $("#datepicker").datepicker("getDate"),
    dateFormat: "dd - M - yy"
});

然后反应：

$("#datepicker").on("change", function() {
    $("#datepicker1").datepicker("option", "minDate", $(this).datepicker("getDate"));
});

http://jsfiddle.net/8z2UH/5/

一旦尝试此

        $(document).ready(function() {
        $('.ui-datepicker-prev ui-corner-all').hide();
        $("#datepicker").datepicker({
            changeMonth: true,
            changeYear: true,
            yearRange: "-0:c+10",
            dateFormat: "dd - M - yy",
            onClose: function(selectedDate) {
                $('#datepicker1').datepicker("setDate", selectedDate);
            }
        });
        $('#datepicker').datepicker("setDate", new Date());
        $("#datepicker").change(function() {
             datepicker1_mindate = $(this).datepicker('getDate');
             datepicker1_mindate = new Date(datepicker1_mindate.getTime());
             $("#datepicker1").datepicker("option", "minDate", datepicker1_mindate);
         });
        $("#datepicker1").datepicker({
            yearRange: "-0:+0",
            dateFormat: "dd - M - yy",                
        });
    });

试试这个：

$(document).ready(function() {
    $('.ui-datepicker-prev ui-corner-all').hide();
    $("#datepicker").datepicker({
        changeMonth: true,
        changeYear: true,
        yearRange: "-0:c+10",
        dateFormat: "dd - M - yy",
        onSelect: function(selectedDate) {
            $("#datepicker1").datepicker("option", "minDate", selectedDate);
            $('#datepicker1').datepicker("setDate", selectedDate);
        }
    });
    $('#datepicker').datepicker("setDate", new Date());
    $("#datepicker1").datepicker({
        yearRange: "-0:+0",
        dateFormat: "dd - M - yy"
    });
});