PHP - Facebook API 请求许可
PHP - Facebook API ask for permission
我正在尝试将玩家登录到Facebook。我正在使用Javascript SDK登录用户,我直接从facebook页面复制了脚本:
登录页面
<!DOCTYPE html>
<html>
<head>
<title>Facebook Login JavaScript Example</title>
<meta charset="UTF-8">
</head>
<body>
<script>
// This is called with the results from from FB.getLoginStatus().
function statusChangeCallback(response) {
console.log('statusChangeCallback');
console.log(response);
// The response object is returned with a status field that lets the
// app know the current login status of the person.
// Full docs on the response object can be found in the documentation
// for FB.getLoginStatus().
if (response.status === 'connected') {
// Logged into your app and Facebook.
testAPI();
} else if (response.status === 'not_authorized') {
// The person is logged into Facebook, but not your app.
document.getElementById('status').innerHTML = 'Please log ' +
'into this app.';
} else {
// The person is not logged into Facebook, so we're not sure if
// they are logged into this app or not.
document.getElementById('status').innerHTML = 'Please log ' +
'into Facebook.';
}
}
// This function is called when someone finishes with the Login
// Button. See the onlogin handler attached to it in the sample
// code below.
function checkLoginState() {
FB.getLoginStatus(function(response) {
statusChangeCallback(response);
});
}
window.fbAsyncInit = function() {
FB.init({
appId : '260828287441151',
cookie : true, // enable cookies to allow the server to access
// the session
xfbml : true, // parse social plugins on this page
version : 'v2.1' // use version 2.1
});
// Now that we've initialized the JavaScript SDK, we call
// FB.getLoginStatus(). This function gets the state of the
// person visiting this page and can return one of three states to
// the callback you provide. They can be:
//
// 1. Logged into your app ('connected')
// 2. Logged into Facebook, but not your app ('not_authorized')
// 3. Not logged into Facebook and can't tell if they are logged into
// your app or not.
//
// These three cases are handled in the callback function.
FB.getLoginStatus(function(response) {
statusChangeCallback(response);
});
};
// Load the SDK asynchronously
(function(d, s, id) {
var js, fjs = d.getElementsByTagName(s)[0];
if (d.getElementById(id)) return;
js = d.createElement(s); js.id = id;
js.src = "//connect.facebook.net/en_US/sdk.js";
fjs.parentNode.insertBefore(js, fjs);
}(document, 'script', 'facebook-jssdk'));
// Here we run a very simple test of the Graph API after login is
// successful. See statusChangeCallback() for when this call is made.
function testAPI() {
console.log('Welcome! Fetching your information.... ');
FB.api('/me', function(response) {
console.log('Successful login for: ' + response.name);
document.getElementById('status').innerHTML =
'Thanks for logging in, ' + response.name + '!';
});
}
</script>
<!--
Below we include the Login Button social plugin. This button uses
the JavaScript SDK to present a graphical Login button that triggers
the FB.login() function when clicked.
-->
<fb:login-button scope="public_profile,email" onlogin="checkLoginState();">
</fb:login-button>
<div id="status">
</div>
<a href="postface.php">Try to post</a>
</body>
</html>
我想要的是,当我按下该链接时,我会转到另一个页面,该页面应该与Facebook进行一些服务器端编程。
波斯特斯.php
<?php
require_once('vendor/autoload.php');
use Facebook'FacebookJavaScriptLoginHelper;
use Facebook'FacebookSession;
FacebookSession::setDefaultApplication('YOUR_APP_ID', 'YOUR_APP_SECRET');
$helper = new FacebookJavaScriptLoginHelper();
try {
$session = $helper->getSession();
} catch(FacebookRequestException $ex) {
// When Facebook returns an error
echo "Error 1: " . $ex;
} catch('Exception $ex) {
// When validation fails or other local issues
echo "Error 2: " . $ex;
}
if ($session) {
// Logged in
echo "The user is logged in!!";
} else
echo "not working";
?>
但是,上述方法不起作用。$session变量只是空?我不明白这一点,因为Facebook说你应该使用那个确切的脚本(我也从他们那里复制(来验证登录,如果你使用javascript,我做到了?
有什么指示我做错了什么吗?javascript页面上的登录部分工作正常,它说我已登录。是另一页上的服务器端部分无法验证用户。
提前致谢
这里的问题是,使用JavaScript SDK登录会将access_token
保存到cookie中,而Facebook PHP SDK正在查看不知道cookie的session
。
您需要从$_COOKIE
中提取access_token
,然后在第二页上使用它来创建会话。
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