如何找到一个小时的结束和推动一个对象

How to find end of hour and push an object

本文关键字：结束 一个对象 小时 一个 何找      更新时间：2023-09-26

下面是一个示例数组。我想每小时检查一下，如果我在最后一分钟有一个目标，如果没有，我想推一个。例如，在下面的数组中，我们看到在02:55和03:50有一个对象，但在00:50和01:50没有对象。那么，在这些时间里，我该如何推送一个对象呢? 

[{day: "2016-10-27T00:45:00.000Z", time: "00:45", val: 100}
{day: "2016-10-27T02:00:00.000Z", time: "02:00", val: 100}
{day: "2016-10-27T02:30:00.000Z", time: "02:30", val: 100}
{day: "2016-10-27T02:55:00.000Z", time: "02:55", val: 100}
{day: "2016-10-27T03:00:00.000Z", time: "03:00", val: 100}
{day: "2016-10-27T03:00:00.000Z", time: "03:00", val: 100}
{day: "2016-10-27T03:00:00.000Z", time: "03:00", val: 100}
{day: "2016-10-27T03:00:00.000Z", time: "03:00", val: 100}
{day: "2016-10-27T03:15:00.000Z", time: "03:15", val: 100}
{day: "2016-10-27T03:30:00.000Z", time: "03:30", val: 100}
{day: "2016-10-27T03:30:00.000Z", time: "03:30", val: 100}
{day: "2016-10-27T03:40:00.000Z", time: "03:40", val: 100}
{day: "2016-10-27T03:50:00.000Z", time: "03:50", val: 100}
{day: "2016-10-27T04:00:00.000Z", time: "04:00", val: 100}]

有人能帮我一下吗

为数组添加新对象:

arr.push({day: "2016-10-27T01:00:00.000Z", time: "01:00", val: 80})

将新对象添加到数组中并按日期对其进行排序

arr.push({day: "2016-10-27T01:00:00.000Z", time: "01:00", val: 80});
arr.sort((a,b) => Date.parse(a.day)-Date.parse(b.day));

你可以使用forEach循环:

var foundIt = false;
myArray.forEach(function(element) {
  if (element.time == whatEverIWant) { // missing time
    foundIt = true;
  }
}
if (!foundIt) {
  myArray.push({ /* insert the missing object here */ });
}
// optionally, sort the array by time
myArray.sort(function(a,b) { return a.time.localeCompare(b.time); }

如果你想对多个值执行此操作，只需对每个值在另一个for循环中运行代码。

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