Jquery按钮触发器css

jquery button trigger css

本文关键字：css 触发器 按钮 Jquery      更新时间：2023-09-26

我想做一个按钮，它有jquery功能，可以触发CSS翻转卡片。我不知道触发器，切换或addClass使用。帮忙，谢谢!我想让它自动从num 1翻转到num 10。对于循环，它将如何实现?

html 

<div class="panel" id="card2">
    <div class="front card">
        <img src="0.png">
    </div>
    <div class="back card">
        <img src="2.png">
    </div>
</div>
css 

.panel {
    width: 200px;
    height: 300px;
    margin: auto;
    position: relative;
}
.card {
    width: 100%;
    height: 100%;
    -o-transition: all .5s;
    -ms-transition: all .5s;
    -moz-transition: all .5s;
    -webkit-transition: all .5s;
    transition: all .2s;
    -webkit-backface-visibility: hidden;
    -ms-backface-visibility: hidden;
    -moz-backface-visibility: hidden;
    backface-visibility: hidden;
    position: absolute;
    top: 0px;
    left: 0px;
}
.front {
    z-index: 2;
}
.back {
    z-index: 1;
    -webkit-transform: rotateY(-180deg);
    -ms-transform: rotateY(-180deg);
    -moz-transform: rotateY(-180deg);  
    transform: rotateY(-180deg);  
}
.panel:hover .front, .togglefront {
    z-index: 1;
    -webkit-transform: rotateY(180deg);
    -ms-transform: rotateY(180deg);
    -moz-transform: rotateY(180deg);
    transform: rotateY(180deg);
}
.panel:hover .back ,.toggleback{
    z-index: 2;   
    -webkit-transform: rotateY(0deg);
    -ms-transform: rotateY(0deg);
    -moz-transform: rotateY(0deg);
    transform: rotateY(0deg);
}

您可以使用jQuery UI的.switchClass()函数来删除和添加指定的类。下面是一个例子:

$("#flip").click(function() {
  $(".card").each(function(index) {
    if ($(this).hasClass("front")) {
      $(this).switchClass("front", "back");
      return;
    }
    if ($(this).hasClass("back")) {
      $(this).switchClass("back", "front");
      return;
    }
  });
});
.panel {
  width: 200px;
  height: 300px;
  margin: auto;
  position: relative;
}
.card {
  width: 100%;
  height: 100%;
  -o-transition: all .5s;
  -ms-transition: all .5s;
  -moz-transition: all .5s;
  -webkit-transition: all .5s;
  transition: all .2s;
  -webkit-backface-visibility: hidden;
  -ms-backface-visibility: hidden;
  -moz-backface-visibility: hidden;
  backface-visibility: hidden;
  position: absolute;
  left: 0px;
}
.front {
  z-index: 2;
}
.back {
  z-index: 1;
  -webkit-transform: rotateY(-180deg);
  -ms-transform: rotateY(-180deg);
  -moz-transform: rotateY(-180deg);
  transform: rotateY(-180deg);
}
.panel:hover .front,
.togglefront {
  z-index: 1;
  -webkit-transform: rotateY(180deg);
  -ms-transform: rotateY(180deg);
  -moz-transform: rotateY(180deg);
  transform: rotateY(180deg);
}
.panel:hover .back,
.toggleback {
  z-index: 2;
  -webkit-transform: rotateY(0deg);
  -ms-transform: rotateY(0deg);
  -moz-transform: rotateY(0deg);
  transform: rotateY(0deg);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/jquery-ui.min.js"></script>
<button type="button" id="flip">Flip!</button>
<div class="front card">
  <img src="https://i.stack.imgur.com/lSjRc.jpg">
</div>
<div class="back card">
  <img src="https://i.stack.imgur.com/j5qcg.jpg">
</div>

或者只使用.removeClass()和.addClass()函数。下面是一个不使用jQuery UI的例子:

$("#flip").click(function () {
    $(".card").each(function (index) {
        if ($(this).hasClass("front")) {
            $(this).removeClass("front");
            $(this).addClass("back");
            return;
        }
        if ($(this).hasClass("back")) {
            $(this).removeClass("back");
            $(this).addClass("front");
            return;
        }
    });
});

JQUERY 

$('.btn').click(function() {
       $('.front').addClass('front-flip');
       $('.back').addClass('back-flip');
    });

您需要创建一个<button>元素，并使用上面的代码为该按钮分配一个事件处理程序。基本上，你将创建两个新类front-flip和back-flip，它们模仿你目前在悬停时分配的相同CSS来翻转卡片/图像。

例子小提琴

我不确定这是正确的方法，但这是工作，你可以改进它:

HTML: 

<div class="panel panel_1" id="card2">
    <div class="front card">
        <img src="http://fr.fordesigner.com/imguploads/Image/cjbc/zcool/png20080526/1211813364.png">
    </div>
    <div class="back card">
        <img src="http://fr.fordesigner.com/imguploads/Image/cjbc/zcool/png20080526/1211808744.png">
    </div>
</div>
<button id='flip_card'>Flip card</button>
CSS: 

.panel {
    width: 200px;
    height: 300px;
    margin: auto;
    position: relative;
}
.card {
    width: 100%;
    height: 100%;
    -o-transition: all .5s;
    -ms-transition: all .5s;
    -moz-transition: all .5s;
    -webkit-transition: all .5s;
    transition: all .2s;
    -webkit-backface-visibility: hidden;
    -ms-backface-visibility: hidden;
    -moz-backface-visibility: hidden;
    backface-visibility: hidden;
    position: absolute;
    top: 0px;
    left: 0px;
}
.front {
    z-index: 2;
}
.back {
    z-index: 1;
    -webkit-transform: rotateY(-180deg);
    -ms-transform: rotateY(-180deg);
    -moz-transform: rotateY(-180deg);  
    transform: rotateY(-180deg);  
}

JS: 

//Flip card function
$('#flip_card').click(function(){
    var card_id = 'card2';
    if($('#'+card_id+' .front').css('z-index')==1)
        flip_front(card_id);
    else
        flip_back(card_id);
});
//Flip back of card 
flip_back = function(card_id){
    $('#'+card_id+' .front').css({
      "z-index": 1, "-webkit-transform": "rotateY(180deg)", "-ms-transform": "rotateY(180deg)", "-moz-transform": "rotateY(180deg)", "transform": "rotateY(180deg)"
    });
    $('#'+card_id+' .back').css({
       "z-index": 2, "-webkit-transform": "rotateY(0deg)", "-ms-transform": "rotateY(0deg)", "-moz-transform": "rotateY(0deg)", "transform": "rotateY(0deg)"
    });
}
//Flip front of card 
flip_front = function(card_id){
    $('#'+card_id+' .back').css({
      "z-index": 1, "-webkit-transform": "rotateY(180deg)", "-ms-transform": "rotateY(180deg)", "-moz-transform": "rotateY(180deg)", "transform": "rotateY(180deg)"
    });
    $('#'+card_id+' .front').css({
       "z-index": 2, "-webkit-transform": "rotateY(0deg)", "-ms-transform": "rotateY(0deg)", "-moz-transform": "rotateY(0deg)", "transform": "rotateY(0deg)"
    });
}

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