JSON CSS parser

JSON CSS parser

本文关键字:parser CSS JSON      更新时间:2023-09-26

我的递归函数坏了,我不知道为什么。我正试图用barebone javascript编写json到css的解析器,似乎无法将我的头围绕为什么我的函数不起作用。有人能帮我一下吗?

在css中,你会得到你正在寻址的特定元素的子元素,比如

#nav li{
  some style here
}

试图在javascript中操作相同的东西,但它不起作用。到目前为止,我的代码对于简单的选择器工作得很好。

var json = {
    "body" : {
        "background": "#303030",
        "color": "#FFFFFF",
        "font-family": "Arial, Helvetica, sans-serif"
    },
    "#nav": {
        "li": {
            "display": "inline-block",
            "list-styles": "none",
            "margin-right": "10px",
            "padding": "10px, 10px"
        }
    }
}
// How to use:
// json is an obj
// body is a selector
// background is a property belong to a selector
// #303030 is a value for the property

//apply css changes to document without writing any css
//by default the first values are
//               selector = background
//               parent   = document
//               object   = json
function styleApply(selector, parent, object){
    var element, onSelector, signal;
    //checks the first character of the selector and grabs element from page depending on what type of element it is
    switch(selector[0]){
        case ".":
            element= parent.getElementsByClassName(selector.substring(1));
            newParent = element[0]; //checks to see what is in the first index of the obtained element
            break;
        case "#":
            element= parent.getElementById(selector.substring(1));
            newParent = element;
            break;
        default:
            element= parent.getElementsByTagName(selector);
            newParent = element[0];
            break;
    }
    //only works if there is actually an element in the page corresponding with the selector
    if(newParent != null){ 
        //loops through all elements with the same selector or in the case of id just does one loop
        for(var i=0; i<element.length; i++){ 
            //loops through all properties in the selector
            for (var property in object[selector]){
                //grabs the associated value with the selector could be string or object
                var value= object[selector][property];
                //if it is a string it is a style, if it is an object, it is targeting the elements inside the current selector only
                if(typeof(value) === "string"){
                    element[i].style.setProperty(property, value);
                }else{
/*I am breaking my code right here*/
                    //reusing the same function, this time selector is equal to property for the case of nav, it is the element 'li'
                    //newParent is the element who is a parent of the current element (e.g 'nav' is parent of 'li')
                    //value is the new object that is replacing json, 
                    styleApply(property, newParent, value); //since value is an object it did not pass the string test and now the new object is value
/*Problem ends here */

                }
            }
        }
    } 
}
my code for looping over all the values in json
for (var selector in json){
    styleApply(selector, document, json);
}

我只是碰巧看到json写一个干净的css比直接连接字符串和数字在一起。我没有将样式直接应用于每个元素,而是将它们放入<style>元素中,这使得在页面的整个生命周期中更容易更改。它还能够定位伪元素,如:前面,我使用的。

总之,函数是这样的:

// convert json to css
function jsonToCss(obj) {
    var x, finalStr=''
    for (x in obj) {
        var y, decStr=''
        for (y in obj[x]) {
            decStr+= y + ':' + obj[x][y] + ';'
        }
        finalStr+= x + '{' + decStr + '}'
    }
    return finalStr
}

由于该函数只递归两个级别(一个用于选择器,另一个用于声明),您的json需要修改如下:

var json = {
    "body" : {
        "background": "#303030",
        "color": "#FFFFFF",
        "font-family": "Arial, Helvetica, sans-serif"
    },
    "#nav li": {
        "display": "inline-block",
        "list-styles": "none",
        "margin-right": "10px",
        "padding": "10px, 10px"
    }
}

将其输入到函数中,您将得到以下字符串:

body{background:#303030;color:#FFFFFF;font-family:Arial, Helvetica, sans-serif;}#nav li{display:inline-block;list-styles:none;margin-right:10px;padding:10px, 10px;}

,然后可以将其放入样式元素中。我还没有验证这个函数产生的字符串,看看它是否格式良好,但它在我这边工作得很好。

这是一段很短的代码,是关于把json解析成css的,我想试试

——selectors指的是你在json中编写的CSS选择器

——parent开始引用文档,就像javascript中的document对象模型一样

——object是传入

的json对象。

如果我误用了术语,请再次纠正我

function styleApply(selector, parent, object){
    var element, onSelector, signal;
    
    switch(selector[0]){
        case ".":
            element= parent.getElementsByClassName(selector.substring(1));
            break;
        case "#":
            element= [parent.getElementById(selector.substring(1))];
            break;
        default:
            element= parent.getElementsByTagName(selector);
            break;
    }
    
    if(element[0] != null){
        for(var i=0; i<element.length; i++){ 
            for (var property in object[selector]){
            
                var value= object[selector][property];
                if(typeof(value) === "string"){
                    element[i].style.setProperty(property, value);
                }else{
                    styleApply(property, element[i], object[selector]);
                }
            }
        }
    } 
}