在json数据中获取嵌套映射

Getting a nested map within json data

本文关键字：嵌套 映射 获取 json 数据      更新时间：2023-09-26

我有这样的JSON数据:

var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}'

它实际上作为JSON返回给我。举个例子，我只是像这样把它展示出来。我可以用data["credit"]来得到元素credit但那只能得到:

{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}

如何深入到一个镜头?data["credit"]["credit"]语法不正确。结果是undefined。我知道我很接近了，但不记得剩下的了。目标是从JSON数据中获取149.96。

目前您可以使用alert(data.credit.credit)。

        var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}';
        eval("data=" + data);
        alert(data.credit.credit);

您也可以使用data = JSON.parse(data);将字符串转换为Json，但这有浏览器兼容性问题。

这些浏览器支持

  • Firefox (Mozilla) 3.5
  • Internet Explorer 8
    • Chrome
  • Opera 10
  • 列表项
  • Safari 4

旧版本不支持。

使用.运算符获取对象的对象

alert(data.credit.credit) //gives 149.96
 alert(data.credit.amount) //gives 149.96
alert(data.credit.card) //gives NT2C8FFC

您正在使data成为字符串而不是对象。把

var data = '{"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}'


var data = {"credit":{"@code":"NT2C8FFC","card":"NT2C8FFC","credit":"149.96","amount":"149.96","disabled":"0","expired":"2011-02-15 10:21:18","user":"xxxx","issued":"2010-02-15 10:21:18","orderid":[],"fromorder":[],"email":"xxxx","phone":[],"state":[],"address":[],"city":[],"zip":[],"country":[],"customerid":"xxx","order":"xxx","order_date":"2010-01-23 00:00:00","reason":"Product Not Working as Expected","source":"xxx","first":[],"last":[],"notes":[]}}

如果不能更改原始数据，则需要执行

来解析它。
data = JSON.parse(data);

(这将在大多数浏览器中工作)或使用库中的方法，如JQuery的:

data = jQuery.parseJSON(data);
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