按分数排序列表并保持分页

sorting lists by score and keeping pagination

本文关键字：分页 列表 排序      更新时间：2023-09-26

我有三个无序列表，其中包含列表项，每个列表项包含从1到10的分数。我有分页，所以页面中有三个相同的ul项。

我需要一个按钮，当点击时，按降序排列列表项(所以从10到1)。

的HTML是:

<ul class="pagination">
    <li class="first active">1</li>
    <li class="second">2</li>
    <li class="third">3</li>
</ul>
<ul class="sort">
    <li class="sortEm">sort by score</li>
</ul>
<div class="block" style="display:block">
    <ul class="reviews_list">
        <li class="one_review">score:
            <div class="score">10</div>
        </li>
        <li class="one_review">score:
            <div class="score">7</div>
        </li>
        <li class="one_review">score:
            <div class="score">9</div>
        </li>
        <li class="one_review">score:
            <div class="score">2</div>
        </li>
        <li class="one_review">score:
            <div class="score">2</div>
        </li>
    </ul>
</div>
<div class="block">
    <ul class="reviews_list">
        <li class="one_review">score:
            <div class="score">1</div>
        </li>
        <li class="one_review">score:
            <div class="score">2</div>
        </li>
        <li class="one_review">score:
            <div class="score">3</div>
        </li>
        <li class="one_review">score:
            <div class="score">7</div>
        </li>
        <li class="one_review">score:
            <div class="score">9</div>
        </li>
    </ul>
</div>
<div class="block">
    <ul class="reviews_list">
        <li class="one_review">score:
            <div class="score">10</div>
        </li>
        <li class="one_review">score:
            <div class="score">2</div>
        </li>
        <li class="one_review">score:
            <div class="score">2</div>
        </li>
        <li class="one_review">score:
            <div class="score">1</div>
        </li>
        <li class="one_review">score:
            <div class="score">5</div>
        </li>
    </ul>
</div>

， js是

$(".pagination li").click(function () {
    $(this).toggleClass("active").siblings().removeClass("active");
    $(".block").hide();
    $(".block").eq($(this).index()).show()
});

$(".sortEm").click(function () {


    function sortEm(a, b) {
        return parseInt($(".score", a).text()) < parseInt($(".score", b).text()) ? 1 : -1;
    }
    $("li.one_review").sort(sortEm).prependTo($(".reviews_list"));

});

的问题是，使用这个函数，当我点击按钮，我失去了分页。这里有一个小提琴:http://jsfiddle.net/3ed03xy9/2/

我如何写javascript，以使它从块移动到块的li项，保持分页和显示它们从10到1?我不是js专家，所以这是我不知道如何做的事情。我走了这么远有人能帮忙吗?非常感谢:)

您可以将插入排序列表的代码更改为

//store sorted list in variable so we can iterate over it and divide it
//this list combine all '.one_review' (li)s in the 3 reviews_list (ul)s
var sortedList = $("li.one_review").sort(sortEm);
// i iteration variable to let us know where we are in sortedList iteration
// we will increase it every iteration throgh sortedList elements
var i = 0;
// j iteration variable to point to Nth of ul.reviews_list (we have 3 ul.reviews_list)
// we will increase it when i=0, i=5 and i=10 
var j = -1;
// the number of items per page (here the sortedList length is 15 and we wanna dived it to 3 pages )
// 15/3 = 5 then round it
var itemsPerPage = Math.round(sortedList.length / 3);
// iterate over each item in sortedList array 
// https://api.jquery.com/each/ 
sortedList.each(function(){
    //if reminder of Nth of element / itemsPerPage equal zero that mean
    //we need to move to next ul.reviews_list empty it.
    if( i % itemsPerPage == 0 ){
        //move to next ul.reviews_list
        // we will enter here 3 times:
        // in first iteration when i=0 then 0%5 = 0 then j will be 0
        // in 6th iteration when i=5 then 5%5 = 0 then j will be 1
        // in 11th iteration when i=10 then 10%5 = 0 then j will be 2
        ++j;
        // empty current ul.reviews_list
        // see : https://api.jquery.com/eq-selector/
        // see : http://api.jquery.com/html/
        $('.reviews_list:eq('+j+')').html("");
    }
    // append current li.one_review(this) to current ul.reviews_list (:eq(j))
    $('.reviews_list:eq('+j+')').append(this);
    ++i;
});
http://jsfiddle.net/3ed03xy9/5/

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