extjs4:显示Mysql blob值中的图像

Ext.define('ImageModel', {
        extend: 'Ext.data.Model',
        fields: ['PicID', 'PicUploadedDateTime','PicData']
    });
    var ImgStore = Ext.create('Ext.data.JsonStore', {
        model: 'ImageModel',
        autoLoad: true,
        proxy: {
            type: 'ajax',
            url: 'get-image.php',
            baseParams: {  //here you can define params you want to be sent on each request from this store
                        mainid: 'value1',
                        startdate: 'value2',
                        enddate: 'value3'
                        },
            reader: {
                type: 'json',
                root: 'images'
            }
        }
    });
    var listView = Ext.create('Ext.grid.Panel', {
        region: 'west',
        id : 'imagelist',
        title: 'Select Image',
        width: 200,
        split: true,
        collapsible: true,
        floatable: false,
        title:'Select Image',
        renderTo: Ext.getBody(),
        store: ImgStore,
        multiSelect: true,
        viewConfig: {
            emptyText: 'No images to display'
        },
        columns: [
            {
            text: 'Date Time Uploaded',
            //xtype: 'datecolumn',
            //format: 'Y-m-d H:i:s',
            flex: 65,
            width: 100,
            dataIndex: 'PicUploadedDateTime'
        }]
    });
listView.on('selectionchange', function(view, nodes){
        Ext.getCmp('displayimage') = nodes[0].get("PicData") // display the image on here
        //when listview selected the image,will display the image at here.
    });

我已经创建了一个listview，当在listview上选择change时，将在Ext.getCmp('displayimage')上显示图像。

nodes[0].get("PicData")是所选的图像数据
图像数据都是blob值(都是JPEG十六进制值(，如何从extjs中显示图像？

更新

这是我的显示图像代码

button.on('click', function(){
        if (!win) {
            win = Ext.create('widget.window', {
                title: 'View Image',
                closable: true,
                closeAction: 'hide',
                width: 600,
                minWidth: 350,
                height: 550,
                layout: {
                    type: 'border',
                    padding: 5
                        },
                items:[
                        listView, 
                    {                           
                    region: 'center',
                    //xtype: 'tabpanel',
                    minheight: 350,
                    items: [{
                        //title: 'Bogus Tab',
                        xtype : 'image',
                        id : 'displayimage',
                            }]
                    },
                    {
                    region: 'north',
                    margin : "5 0 5 0",
                    //xtype: 'tabpanel',
                    minheight: 350,
                    items: [dr]
                    }]
            });

在我把代码改成之后

Ext.getCmp('displayimage').src = 'data:image/jpeg;base64,'+nodes[0].get("PicData") // 
Image corrupt or truncated

这是我从firebug中得到的错误消息，但我可以确定我的二进制数据是正确的，因为我曾尝试使用python将其转换为.jpeg文件

这是来自数据库的.jpeg示例blob值(二进制字符串(，
http://pastebin.ca/raw/2314500