PHP中的截屏JavaScript

我可以使用以下脚本成功地抓取该页面上的所有项目：

$html = file_get_contents($list_url);
$doc = new DOMDocument();
libxml_use_internal_errors(TRUE);
    if(!empty($html))
    {
        $doc->loadHTML($html);
        libxml_clear_errors(); // remove errors for yucky html
        $xpath = new DOMXPath($doc);
        /* FIND LINK TO PRODUCT PAGE */
        $products = array();
        $row = $xpath->query($product_location);
        /* Create an array containing products */
        if ($row->length > 0)
        {            
            foreach ($row as $location)
            {
                $product_urls[] = $product_url_root . $location->getAttribute('href');
            }
        }
        else { echo "product location is wrong<br>";}
        $imgs = $xpath->query($photo_location);
        /* Create an array containing the image links */
        if ($imgs->length > 0)
        {            
            foreach ($imgs as $img)
            {
                $photo_url[] = $photo_url_root . $img->getAttribute('src');
            }
        }
        else { echo "photo location is wrong<br>";}
        $was = $xpath->query($was_price_location);
        /* Create an array containing the was price */
        if ($was->length > 0)
        {
            foreach ($was as $price)
            {
                $stripped = preg_replace("/[^0-9,.]/", "", $price->nodeValue);
                $was_price[] = "&pound;".$stripped;
            }
        }
        else { echo "was price location is wrong<br>";}
        $now = $xpath->query($now_price_location);
        /* Create an array containing the sale price */
        if ($now->length > 0)
        {
            foreach ($now as $price)
            {
                $stripped = preg_replace("/[^0-9,.]/", "", $price->nodeValue);
                $stripped = number_format((float)$stripped, 2, '.', '');
                $now_price[] = "&pound;".$stripped;
            }
        }
        else { echo "now price location is wrong<br>";}
        $result = array();
        /* Create an associative array containing all the above values */
        foreach ($product_urls as $i => $product_url)
        {
            $result[] = array(
                'product_url' => $product_url,
                'shop_name' => $shop_name,
                'photo_url' => $photo_url[$i],
                'was_price' => $was_price[$i],
                'now_price' => $now_price[$i]
            );
        }
    }

然而，如果我想获得第二页，或者如果我每页查看100，则会出现问题。file_get_contents($list_url)将始终返回具有24个值的第一页。

我认为页面更改是通过AJAX请求处理的（尽管我在源代码中找不到任何证据）。有没有办法把我在屏幕上看到的东西刮出来？

我在之前的回答中看到过PhantomJS的讨论，但考虑到我使用的是PHP，我不确定它在这里是否合适。