检查数组中的部分匹配

Check for Partial Match in an Array

本文关键字：数组 检查      更新时间：2024-05-13

我有一个JavaScript数组，其中包含一些在请求创建用户帐户时无法使用的单词。

我正在尝试循环查看所请求的帐户，并根据单词过滤器进行检查。如果它们包含任何单词，则该值将移动到一个"无效帐户"数组中。

// Create our arrays
var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];
// I need to check if any of the new accounts have matches to those in the blacklist. 
// admin1@google.com would need to be pushed into the invalidAccounts array because it 
// contains the word admin. Although interweb contains the word web, it does not contain 
// the full word, webform, so should be ignored.
// Loop over the blacklist array
for(var x = 0; x < blacklist.length; x++){
  if(blacklist[x].indexOf(newAccounts) > -1){
    alert(blacklist[x] + " is in the blacklist array");
    // Push the newAccounts value into the invalidAccounts array since it contains
    // a blacklist word.
  } else {
    alert('no matches');
  }
}

我需要在上面的代码中更改什么才能使其与上面提到的部分字符串匹配？

上述代码的Fiddle：https://jsfiddle.net/1qwze81o/

您可能不需要使用所有这些，但它应该会有所帮助：

var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];
// transform each email address to an object of the form:
// { email: string, valid: boolean }
var accountObjects = newAccounts.map(function (a) {
    return { email: a, valid: true };
});
// loop over each account
accountObjects.forEach(function (account) {
    // loop over the blacklisted terms
    blacklist.forEach(function (blacklisted) {
        // check to see if your account email address contains a black listed term
        // and set the valid property accordingly
        account.valid = account.email.search(blacklisted) === -1;
    });
});
// filter accountObjects, validAccounts will now contain an array of valid objects
var validAccounts = accountObjects.filter(function (a) {
    return a.valid;
});
// back to the original type of a string array
var validEmailAddresses = validAccounts.map(function (a) {
    return a.email;
});

使用javascript数组本机函数的解决方案：

var invalidAccounts = newAccounts.filter(function(account){ // we need to filter accounts
  return blacklist.some(function(word){ // and return those that have any of the words in the text
      return account.indexOf(word) != -1
  })
});

更多信息：Array.filter和排列某些

我们需要两个循环来实现这一点：如下所示：

   // Loop over the blacklist array
  for(var j = 0; x < newAccounts.length; j++){
    for(var x = 0; x < blacklist.length; x++){
    if(newAccounts[j].indexOf(blacklist[x]) > -1){
        alert(blacklist[x] + " is in the blacklist array");
        // Push the newAccounts value into the invalidAccounts array since it contains a blacklist word.
      }else{
        alert('no matches');
      }
    }
    }

我修复了一些问题。。。

for (var x = 0; x < newAccounts.length; x++) // loop through new accounts
{
    // for every account check if there is any match in blacklist array
    for (var y = 0; y < blacklist.length; y++) 
    {
      // if there is match do something 
      if (newAccounts[x].indexOf(blacklist[y]) > -1)
      {
          alert(newAccounts[x] + " is in the blacklist array");
          break;
      }
  }
}

这是小提琴：https://jsfiddle.net/swaprks/n1rkfuzh/

JAVASCRIPT:

// Create our arrays
var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];
for(var x = 0; x < newAccounts.length; x++){
    for(var y = 0; y < blacklist.length; y++){

          if( newAccounts[x].indexOf(blacklist[y]) > -1){
            alert(blacklist[x] + " is in the blacklist array");
            // Push the newAccounts value into the invalidAccounts array since it contains
            // a blacklist word.
            invalidAccounts.push(newAccounts[x]);
          }else{
            alert('no matches');
          }
    }
}
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