如何对Javascript Unix时间戳数组进行排序

How to Sort a Javascript Unix Timestamp Array

本文关键字：数组 排序 时间戳 Unix Javascript      更新时间：2023-11-16

我有一个包含Unix时间戳的数组，我想对该数组进行排序——有人知道怎么做吗？或者可能将其转换为简单的日期格式，然后以任何方式对其进行排序？

还请举例说明

我已经尝试过了，但没有成功Jquery-按时间戳排序数组的最快方法

我的代码：

//where rawutimes is unsorted unix time array
console.log(rawutimes);

 // output ["1423857905", "1423611874", "1422953913", "1423499856", "1423502234", "1423502884", "1423503754", "1423510832", "1423511445", "1423514134", "1423358619", "1423583825", "1423713297", "1423713401", "1423735601", "1423772523", "1423768351", "1423817039", "1423166917", "1423446473", "1423446761", "1423835014", "1423858124", "1423857905", "1423855048", "1423852400", "1423852313", "1423852210", findIndex: function, find: function]
thesorted = rawutimes.sort(function(x, y){
    return x.timestamp - y.timestamp;
});
//printing the sorted unix time array       
console.log(thesorted);
//Output : ["1423857905", "1423852210", "1422953913", "1423499856", "1423502234", "1423502884", "1423503754", "1423510832", "1423511445", "1423514134", "1423358619", "1423583825", "1423713297", "1423713401", "1423611874", "1423772523", "1423768351", "1423817039", "1423166917", "1423446473", "1423446761", "1423835014", "1423858124", "1423857905", "1423855048", "1423852400", "1423852313", "1423735601", findIndex: function, find: function]
//Converted to Readable date format to confirm if it's sort or not?
rtimes = [];
for (var i = 0; i < rawutimes.length; i++) {
    rtime = timeConverter(thesorted[i]);
    rtimes.push(rtime);
};
//output 

//["14,Feb 2015 1:5:5", "13,Feb 2015 23:30:10", "3,Feb 2015 13:58:33", "9,Feb 2015 21:37:36", "9,Feb 2015 22:17:14", "9,Feb 2015 22:28:4", "9,Feb 2015 22:42:34", "10,Feb 2015 0:40:32", "10,Feb 2015 0:50:45", "10,Feb 2015 1:35:34", "8,Feb 2015 6:23:39", "10,Feb 2015 20:57:5", "12,Feb 2015 8:54:57", "12,Feb 2015 8:56:41", "11,Feb 2015 4:44:34", "13,Feb 2015 1:22:3", "13,Feb 2015 0:12:31", "13,Feb 2015 13:43:59", "6,Feb 2015 1:8:37", "9,Feb 2015 6:47:53", "9,Feb 2015 6:52:41", "13,Feb 2015 18:43:34", "14,Feb 2015 1:8:44", "14,Feb 2015 1:5:5", "14,Feb 2015 0:17:28", "13,Feb 2015 23:33:20", "13,Feb 2015 23:31:53", "12,Feb 2015 15:6:41"]

//result array not sorted

感谢

您有一个字符串列表，但在排序函数中使用.timestamp。只需移除它：

rawutimes = ["1423857905", "1423611874", "1422953913", "1423499856", "1423502234", "1423502884", "1423503754", "1423510832", "1423511445", "1423514134", "1423358619", "1423583825", "1423713297", "1423713401", "1423735601", "1423772523", "1423768351", "1423817039", "1423166917", "1423446473", "1423446761", "1423835014", "1423858124", "1423857905", "1423855048", "1423852400", "1423852313", "1423852210"]
thesorted = rawutimes.sort(function(x, y){
    return x - y;
});
rtimes = thesorted.map(function(x) {
  return new Date(x * 1000);
});
document.write(rtimes.join("<br>"))

试试这个，完美排序，在Chromium浏览器和Firefox中检查：

<!DOCTYPE html>
<html>
<head>
<script>
var rawutimes = ["1423857905", "1423611874", "1422953913", "1423499856", "1423502234", "1423502884", "1423503754", "1423510832", "1423511445", "1423514134", "1423358619", "1423583825", "1423713297", "1423713401", "1423735601", "1423772523", "1423768351", "1423817039", "1423166917", "1423446473", "1423446761", "1423835014", "1423858124", "1423857905", "1423855048", "1423852400", "1423852313", "1423852210"]
console.log("Raw unix timestamps: " + rawutimes);
var formatted = [];
for (var i = 0; i < rawutimes.length; ++i) {
    var d = new Date(parseInt(rawutimes[i]) * 1000);
    formatted.push(d);
}
thesorted = formatted.sort(function (x, y) {
        return y - x;
        });
console.log("Formatted: " + thesorted);
</script>
</head>
<body>
</body>
</html>
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