Angularjs合并两个忽略null和缺失值的对象

Angularjs merge two objects ignoring null and missing values

本文关键字：null 对象 合并 两个 Angularjs      更新时间：2023-10-17

例如，从这两个对象：

var object1 = {
    "color": "yellow",
    "size" : null,
    "age" : 7,
    "weight" : null
}
var object2 = {
    "color": "blue",
    "size" : 51,
    "age" : null
}

我想要这个（对象2覆盖对象1，除了空属性或他没有的属性）：

{
    "color": "blue",
    "size" : 51,
    "age" : 7,
    "weight" : null
}

angular.extend（对象1，对象2）有效，但将age属性重写为空

您可以在调用扩展之前删除对象2中的null属性。

var myApp = angular.module('myApp',[]);
var object1 = {
    "color": "yellow",
    "size" : null,
    "age" : 7,
    "weight" : null
}
var inside = {
    "name": "me",
    "age" : 9,
    "nothing": null
}
var object2 = {
    "color": "blue",
    "size" : 51,
    "age" : null,
    "inside" : inside
}
function removeNullIn(prop, obj)
{
  var pr = obj[prop];
  if(pr === null || pr === undefined) delete obj[prop]; 
  else if(typeof pr === 'object') for (var i in pr) removeNullIn(i, pr);
}
function removeNull(obj)
{
    for (var i in obj) {
        removeNullIn(i, obj);
    }
}
removeNull(object2);
var mergedObject = angular.extend(object1, object2);
console.log(mergedObject);
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.9/angular.min.js"></script>

您可以将此函数用作自定义扩展机制，而不是本地angular.extend.

/**
 * Extends dst with props from src
 * @see 
 *  customExtend({a: 1, test : 1}, {b: 1, test : 2});
 *  //this will return {a: 1, b: 1, test: 2}
 * @returns {Object}
 */
var customExtend = function (/* [emptyObject], dst, src */) {
    var $$args = Array.prototype.slice.call(arguments, 0);
    if ($$args.length === 3) {
        $$args.shift();
    }
    for (var i in $$args[1]) {
        if ($$args[1][i] !== null || angular.isUndefined($$args[1][i])) {
            $$args[0][i] = $$args[1][i];
        }
    }
    return $$args[0];
};

angular.customExtend = customExtend;
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