如何将结果集转换为 JSON 对象

how to convert ResultSet to JSON object

本文关键字：JSON 对象 转换 结果      更新时间：2023-09-26

我们尝试使用以下代码将ResultSet转换为JSON对象：

var getAllCalelements = {};           // Object
    getAllCalelements['totalamount'] = [];          
    getAllCalelements['totalamount'].push(result.rows.item(i).totalamount);
    getAllCalelements['discount'] = [];          
    getAllCalelements['discount'].push(result.rows.item(i).invoicediscount);
    getAllCalelements['NetAmount'] = [];          
    getAllCalelements['NetAmount'].push(result.rows.item(i).namount);
    getAllCalelements['vat'] = [];          
    getAllCalelements['vat'].push(result.rows.item(i).vat);
    getAllCalelements['GrossAmount'] = [];          
    getAllCalelements['GrossAmount'].push(result.rows.item(i).gamount);
    getAllCalelements['bookOrder'] = [];          
    getAllCalelements['bookOrder'].push(result.rows.item(i).bookorder);
var json = JSON.stringify(getAllCalelements, undefined, 2);

但是，我们得到了这样的JSON。 

{
  "totalamount": [19760.22],
  "discount": [ 7],
  "NetAmount": [ 18377],
  "vat": [ 8],
  "GrossAmount": [ 8],
  "bookOrder": [ "ABCANG00110"]
}

而且，我们需要这样的 JSON 输出 

[
    {
        "totalamount": 19760.22,
        "discount": 7,
        "NetAmount": 18377,
        "vat": 8,
        "GrossAmount": 8,
        "bookOrder": "ABCANG00555"
    }
]

我已经尝试过，但我没有得到上面提到的欲望输出，我得到了 JSON 输出。但是我们需要上述格式的 JSON。所有人都请指导我获得上面提到的我的愿望输出，谢谢。

var obj = [];
for (var i = 0; i < result.rows.length; i++){
    var getAllCalelements = {};           // Object
    getAllCalelements['totalamount'] = result.rows.item(i).totalamount ;
    getAllCalelements['discount'] = result.rows.item(i).invoicediscount;
    getAllCalelements['NetAmount'] = result.rows.item(i).namount;
    getAllCalelements['vat'] = result.rows.item(i).vat;
    getAllCalelements['GrossAmount'] = result.rows.item(i).gamount;
    getAllCalelements['bookOrder'] = result.rows.item(i).bookorder;
    obj.push(getAllCalelements);
}
var json = JSON.stringify(obj, undefined, 2);

尝试以下代码： 

var obj = {};
obj = [];
for(var i=0;i<result.rows.item.length;i++)
{
    var getAllCalelements = {};           // Object
    getAllCalelements['totalamount'] = result.rows.item(i).totalamount ;
    getAllCalelements['discount'] = result.rows.item(i).invoicediscount;
    getAllCalelements['NetAmount'] = result.rows.item(i).namount;
    getAllCalelements['vat'] = result.rows.item(i).vat;
    getAllCalelements['GrossAmount'] = result.rows.item(i).gamount;
    getAllCalelements['bookOrder'] = result.rows.item(i).bookorder;
    obj.push(getAllCalelements);
}
var json = JSON.stringify(obj, undefined, 2);

输出： 

[
  {
    "totalamount": "19760.22",
    "discount": "7",
    "NetAmount": "18377",
    "vat": "8",
    "GrossAmount": "8",
    "bookOrder": "ABCANG00110"
  }
]

如果要通过obj.push(getAllCalelements)将第二个对象添加到obj，则会得到以下输出 

[
  {
    "totalamount": "19760.22",
    "discount": "7",
    "NetAmount": "18377",
    "vat": "8",
    "GrossAmount": "8",
    "bookOrder": "ABCANG00110"
  },
  {
    "totalamount": "19760.22",
    "discount": "7",
    "NetAmount": "18377",
    "vat": "8",
    "GrossAmount": "8",
    "bookOrder": "ABCANG00110"
  }
]

@aschattney 即兴创作您的答案并使其动态化 Object.keys() 还将其包装在一个函数中，以便您传递resultSet即在这种情况下，sqlResultSet 并返回有效的 JSON。

  function returnJsonFromSqlResultSet(sqlResultSet) {
    var objArr = [];
    if (sqlResultSet.rows.length > 0) {
      var objKeys = Object.keys(sqlResultSet.rows.item(0)); //sample the keys from first element
      for (var i = 0; i < sqlResultSet.rows.length; i++) {
        var jsonObj = {}; // Object
        for (var j = 0; j < objKeys.length; j++) {
          jsonObj[objKeys[j]] = sqlResultSet.rows.item(i)[objKeys[j]];
        }
        objArr.push(jsonObj);
      }
      var json = JSON.stringify(objArr, undefined, 2);
      return json;
    }
}

谢谢！

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