多维数组

试试这个

 var x = [12, 155, 177];
 var y = [120, 175, 255];
 var z = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160, 161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172, 173, 174, 175, 176, 177, 178, 179, 180, 181, 182, 183, 184, 185, 186, 187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199, 200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210, 211, 212, 213, 214, 215, 216, 217, 218, 219, 220, 221, 222, 223, 224, 225, 226, 227, 228, 229, 230, 231, 232, 233, 234, 235, 236, 237, 238, 239, 240, 241, 242, 243, 244, 245, 246, 247, 248, 249, 250, 251, 252, 253, 254, 255, 256, 257, 258, 259, 260, 261, 262, 263, 264, 265, 266, 267, 268, 269, 270, 271, 272, 273, 274, 275, 276, 277, 278, 279, 280, 281, 282, 283, 284, 285, 286, 287, 288, 289, 290, 291, 292, 293, 294, 295, 296, 297, 298, 299, 300];
  var value = [];

  for (var i = 0; i < x.length; i++) {
      var temp = []
      for (var index = x[i]; index < y[i]; index++) {
          temp.push(z[index]);
      }
      value.push(temp);
  }
  console.log(value);

我不太完全遵循您想要做的事情，但这里有一些应该有帮助的信息。

JavaScript 没有多维数组。（事实上，JavaScript 数组根本不是真正的数组。但是你可以有一个数组，其中有数组作为元素值。所以：

var i, j, a, sub;
// Create the main array
a = [];
// This loop creates the outermost level
for (i = 0; i < 10; ++i) {
    // Here we create the array to store in a[i]:
    sub = [];
    // This loop builds it up
    for (j = 0; j < 20; ++j) {
        sub[j] = "I'm the element at a[" + i + "][" + j + "]"; // Just a sample value
    }
    // Remember this sub-array
    a[i] = sub;
}
console.log("a[1][12] = " + a[1][12]); // "I'm the element at a[1][12]"

关于上述内容的主要说明：

1. 您必须在循环中创建每个从属数组

2. 您不必预先分配或类似的东西，您只需分配给元素即可扩展数组。（push也有效。它有点慢，但这通常并不重要。

这样的事情应该可以工作。我还使用 for 循环来生成 z 数组，而不是手动写出它。

var x = [12, 155, 177], y = [120, 175, 255], z = [], value = [];
// generate z, 1 to 300
for(var i = 1; i<=300; i++) {
    z.push(i);
}
for(var i = 0, len = x.length; i < len; i++) {
    var arr = [];
    for(var j = 0; j < y[i]; j++) {
        arr.push(z[j]);
    }
    value.push(arr);
}