如何获取JSON对象(javascript)中的所有密钥

How to get all key in JSON object (javascript)

本文关键字:密钥 javascript JSON 何获取 获取 对象      更新时间:2023-09-26
{"document":
  {"people":[
    {"name":["Harry Potter"],"age":["18"],"gender":["Male"]},
    {"name":["hermione granger"],"age":["18"],"gender":["Female"]},
  ]}
}

从这个 JSON 示例中,我想为每个人获取诸如 nameagegender 等键。

怎么做?

我使用内置在JavaScript对象中的Object.keys,它将从给定对象MDN引用返回一个键数组

var obj = {name: "Jeeva", age: "22", gender: "Male"}
console.log(Object.keys(obj))

试试这个

var s = {name: "raul", age: "22", gender: "Male"}
   var keys = [];
   for(var k in s) keys.push(k);

在这里,键数组将返回您的键["name", "age", "gender"]

var input = {"document":
  {"people":[
    {"name":["Harry Potter"],"age":["18"],"gender":["Male"]},
    {"name":["hermione granger"],"age":["18"],"gender":["Female"]},
  ]}
}
var keys = [];
for(var i = 0;i<input.document.people.length;i++)
{
    Object.keys(input.document.people[i]).forEach(function(key){
        if(keys.indexOf(key) == -1)
        {
            keys.push(key);
        }
    });
}
console.log(keys);

ES6 的

一天在这里;
const json_getAllKeys = data => (
  data.reduce((keys, obj) => (
    keys.concat(Object.keys(obj).filter(key => (
      keys.indexOf(key) === -1))
    )
  ), [])
)

是的,它可以写很长的一行;

const json_getAllKeys = data => data.reduce((keys, obj) => keys.concat(Object.keys(obj).filter(key => keys.indexOf(key) === -1)), [])

编辑:如果输入是对象数组类型,则返回所有一阶键

var jsonData = { Name: "Ricardo Vasquez", age: "46", Email: "Rickysoft@gmail.com" };
for (x in jsonData) {   
  console.log(x +" => "+ jsonData[x]);  
  alert(x +" => "+  jsonData[x]);  
  }

此函数应返回 JSON 对象中所有键(即键名(的数组,包括嵌套的键/值对

function get_all_json_keys(json_object, ret_array = []) {
    for (json_key in json_object) {
        if (typeof(json_object[json_key]) === 'object' && !Array.isArray(json_object[json_key])) {
            ret_array.push(json_key);
            get_all_json_keys(json_object[json_key], ret_array);
        } else if (Array.isArray(json_object[json_key])) {
            ret_array.push(json_key);
            first_element = json_object[json_key][0];
            if (typeof(first_element) === 'object') {
                get_all_json_keys(first_element, ret_array);
            }
        } else {
            ret_array.push(json_key);
        }
    }
    return ret_array
}

在 OP 的原始对象上使用此函数

const op_object =
{
    "document":{
       "people":[
          {
             "name":[
                "Harry Potter"
             ],
             "age":[
                "18"
             ],
             "gender":[
                "Male"
             ]
          },
          {
             "name":[
                "hermione granger"
             ],
             "age":[
                "18"
             ],
             "gender":[
                "Female"
             ]
          }
       ]
    }
 }
var all_keys = [];
function get_all_json_keys(json_object, ret_array = []) {
    for (json_key in json_object) {
        if (typeof(json_object[json_key]) === 'object' && !Array.isArray(json_object[json_key])) {
            ret_array.push(json_key);
            get_all_json_keys(json_object[json_key], ret_array);
        } else if (Array.isArray(json_object[json_key])) {
            ret_array.push(json_key);
            first_element = json_object[json_key][0];
            if (typeof(first_element) === 'object') {
                get_all_json_keys(first_element, ret_array);
            }
        } else {
            ret_array.push(json_key);
        }
    }
    return ret_array
}
get_all_json_keys(op_object, all_keys);
console.log(all_keys);

应该屈服

[ 'document', 'people', 'name', 'age', 'gender' ]

注意:这将返回所有键名称的唯一列表。

我们必须"解析"我们的jsonObject

 console.log('{"key0":"value0", "key1":"value1"}'); 
    var jsonObject = JSON.parse('{"key0":"value0", "key1":"value1"}')
    Object.keys(jsonObject).forEach(key => { 
        console.log(jsonObject[key]); //values 
        console.log(key); //keys 
    })