在jquery中，json对象How中的每个循环(使循环从对象中找到一个值，并与另一个对象值进行比较，以避免重复打印）

In jquery each Loop from json object How (make loop find a value from object and compare to another object value to not repeat a print)?

本文关键字：循环 对象 一个对象 打印 比较 How json jquery 一个      更新时间：2023-09-26

大家好，我正在开发一个音乐播放器，我正在使用Json来存储我的ID3或AKA"MP3元数据"。我面临的问题是，我正在提取一个对象并训练gf，看看我是否可以比较值，如果两个对象都有相同的值，不要重复打印。如果我只想让艺术家在

  • 中重复一次而不是2到无穷大。

    这是JSON文件示例；

    [
{   
    "Artist": "",
    "Album": "",
    "Year":"",
    "Genre": "", 
    "Song": "",
    "Location": "",
    "Track": "",
    "Img": "",
    "Composer":""
},
    {   
    "Artist": "The Rolling Stones",
    "Album": "Hot Rocks (1964-1971)",
    "Year":"2002",
    "Genre": "Rock", 
    "Song": "Heart of Stone",
    "Location": "scr/music/TheRollingStones/HeartofStone.mp3",
    "Track": "2",
    "Img": "scr/music/TheRollingStones/img/HotRocks.jpg",
    "Record":"Sony Music"
},
    {   
    "Artist": "The Rolling Stones",
    "Album": "Hot Rocks (1964-1971)",
    "Year":"2002",
    "Genre": "Rock", 
    "Song": "Sympathy For The Devil",
    "Location": "scr/music/TheRollingStones/SympathyForTheDevil.mp3",
    "Track": "15",
    "Img": "scr/music/TheRollingStones/img/HotRocks.jpg",
    "Record":"Sony Music"
},
        {   
    "Artist": "Led Zeppelin",
    "Album": "The Complete Led Zeppelin",
    "Year":"2007",
    "Genre": "Rock", 
    "Song": "Good Times Bad Times",
    "Location": "scr/music/LedZeppelin/GoodTimesBadTimes.mp3",
    "Track": "1",
    "Img": "scr/music/LedZeppelin/img/The Complete Led Zeppelin.jpg",
    "Record":"Atlantic Records"
}
]

    Javascript文档

        $.getJSON('scr/json/musicdata.json', function(data){
        var output = '<ol>';
             data.sort(function(a, b){
             return [a.Artist] < [b.Artist] ?  0 : 1;
         });//End of Sort by Artist 
         $.each(data, function(key,val) {
         if(val.Artist != ""){
         if(PreArtis != val.Artist){
        output += '<li><a class="songname" href="#" data-src="'+ val.Location +'">' + val.Artist + '</a></li>';
            var PreSong = val.Artist ;
         }//End of PreSong != Song
        }//End of val.Artist     
        });//End of Each 
         output += '</ol>';
        $("#wrapper").append(output);
        });//End of getJSON

    Html

    感谢您对的帮助

    • 尝试

    var songs = {};
$.each(data, function(key,val) {
    if(val.Artist != ""){
        var key = val.Artist + '@' + val.Album;
        if(!songs[key]){
            output += '<li><a class="songname" href="#" data-src="'+ val.Location +'">' + val.Artist + '</a></li>';
            songs[key] = true ;
        }//End of PreSong != Song
    }//End of val.Artist     
});//End of Each 
output += '</ol>';
$("#wrapper").append(output);

    演示：Fiddle

    您可以更改key以查找唯一的组合。例如：如果你想要一个独特的组合艺术家，专辑和歌曲，那么使用var key = val.Artist + '@' + val.Album + val.Song；

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