向声音云响应json添加一个变量

首先，将JSON响应存储在一个变量中：

var obj = response;

现在，您有了一个变量，其中包含一个javascript对象。要将属性添加到您的对象，只需使用：

obj.custom_url = "Your_url";

或

obj["custom_url"] = "your_url";

我不知道完整的对象结构，但假设对象被称为result，并且有一个名为albums的属性，它是一个对象数组。在这种情况下，你会这样做：

$.each(result.albums, function() {
    this.custom_url = 'whatever';
});

或者搭配香草js:

for (var i = 0, i < result.albums.length; i++) {
    result.albums[i].custom_url = 'whatever';
}

u不需要或想要jQuery，只需要JavaScript。

以为例

var data = {items: [
    {id: "1", name: "Snatch", type: "crime"},
    {id: "2", name: "Witches of Eastwick", type: "comedy"},
    {id: "3", name: "X-Men", type: "action"},
    {id: "4", name: "Ordinary People", type: "drama"},
    {id: "5", name: "Billy Elliot", type: "drama"},
    {id: "6", name: "Toy Story", type: "children"}
]};

添加项目：

data.items.push(
    {id: "7", name: "Douglas Adams", type: "comedy"}
);

这就结束了。请参阅以下内容以在中间添加"。

删除项目：

有几种方法。拼接方法是最通用的：

data.items.splice(1, 3); // Removes three items starting with the 2nd,
                         // ("Witches of Eastwick", "X-Men", "Ordinary People")

拼接将修改原始阵列，并返回已删除项目的阵列。

中间添加：

拼接实际上既可以添加也可以删除。拼接方法的特征是：

removed_items = arrayObject.splice(index, num_to_remove[, add1[, add2[, ...]]]);
index - the index at which to start making changes
num_to_remove - starting with that index, remove this many entries
addN - ...and then insert these elements

所以我可以在第三个位置添加一个项目，如下所示：

data.items.splice(2, 0,
    {id: "7", name: "Douglas Adams", type: "comedy"}
);

这意味着：从索引2开始，删除零项，然后插入以下项。结果如下：

var data = {items: [
    {id: "1", name: "Snatch", type: "crime"},
    {id: "2", name: "Witches of Eastwick", type: "comedy"},
    {id: "7", name: "Douglas Adams", type: "comedy"},     // <== The new item
    {id: "3", name: "X-Men", type: "action"},
    {id: "4", name: "Ordinary People", type: "drama"},
    {id: "5", name: "Billy Elliot", type: "drama"},
    {id: "6", name: "Toy Story", type: "children"}
]};

你可以一次删除一些并添加一些：

data.items.splice(1, 3,
    {id: "7", name: "Douglas Adams", type: "comedy"},
    {id: "8", name: "Dick Francis", type: "mystery"}
);

意思是：从索引1开始，删除三个条目，然后添加这两个条目。结果是：

var data = {items: [
    {id: "1", name: "Snatch", type: "crime"},
    {id: "7", name: "Douglas Adams", type: "comedy"},
    {id: "8", name: "Dick Francis", type: "mystery"}
    {id: "5", name: "Billy Elliot", type: "drama"},
    {id: "6", name: "Toy Story", type: "children"}
]};