获取Javascript日期函数的总和

Get Sum of Javascript Date function

本文关键字：函数 Javascript 日期 获取      更新时间：2023-09-26

我有从两次中获取时差的代码

        var starthours = document.getElementById("time3").value;
        var endhours = document.getElementById("time4").value;
        start = starthours.split(".");
        end = endhours.split(".");
        var startDate = new Date(0, 0, 0, start[0], start[1], 0);
        var endDate = new Date(0, 0, 0, end[0], end[1], 0);
        var diff = endDate.getTime() - startDate.getTime();
        var hours = Math.floor(diff / 1000 / 60 / 60);
        diff -= hours * 1000 * 60 * 60;
        var minutes = Math.floor(diff / 1000 / 60);
    document.getElementById("hourdiff").value = (hours < 9 ? "0" : "") + hours + "." + (minutes < 9 ? "0" : "") + minutes;

但现在我必须为这个结果添加另一个时间字段，我使用这个代码获得这个值

var timetv = document.getElementById("timetv").value;
And I want to add this to above time difference how to do that, Please help me.. 
Start time = 10.30
End time = 12.30
Time TV = 01.15
Resualt = (End Time - Start time) + Time TV

答案应该是=3.15

试试这个，

var starthours = document.getElementById("time3").value;
var endhours = document.getElementById("time4").value;
var timetv = document.getElementById("timetv").value;
start = starthours.split(".");
end = endhours.split(".");
tvtime = timetv.split(".");
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);    
hours = hours + parseInt(tvtime[0]);
minutes = minutes + parseInt(tvtime[1]);

当您已经将日期从表单中解析为Date对象时，这个函数用于获取值。

http://jsfiddle.net/gLReS/

var time1 = new Date('2013/08/12 10:30');
var time2 = new Date('2013/08/12 12:30');
var time3 = new Date('2013/08/12 1:15');
var result = (time2.getTime() - time1.getTime()) + time3.getTime();
var resultTime = new Date(result);
alert(resultTime);

然而，另一件事是获取这些对象，而这个对象取决于您的日期格式。

我不明白，你的问题是什么。 
var d = new Date(
    new Date(0, 0, 0, 12, 30) -
    new Date(0, 0, 0, 10, 30) +
    (+new Date(0, 0, 0, 1, 15)) // transform Date into timestamp
);
[d.getHours(), d.getMinutes()]; // [3, 15]

此外，我通常会更换

(hours < 9 ? "0" : "") + hours

带有

("0" + hours).slice(-2)
相关文章：