Ajax从json对象(）中检索值

Ajax retrieve value from json object ()

本文关键字：检索 json 对象 Ajax      更新时间：2023-09-26

这是我的第一次ajax体验。我已经使用ajax成功地从服务器获得了GET响应。但是我面临着从JSON中检索值的问题。

我的ajax调用：

url: "ur",
type: "GET",
cache: false,    
dataType:"json",  
contentType: "application/json",
success: function(res) {                        
    console.log(res);
}

来自服务器的JSON响应：

{
  "message": [
    {
      "files": "SS", 
      "messageBody": "gOOD", 
      "messageID": 1, 
      "messageTitle": "THTH", 
      "photos": "DD", 
      "userID": 2, 
      "videos": "FF"
    }, 
    {
      "files": "", 
      "messageBody": "bla bala blaa", 
      "messageID": 2, 
      "messageTitle": "another", 
      "photos": "", 
      "userID": 3, 
      "videos": ""
    }, 
    {
      "files": "The Cock files", 
      "messageBody": "New message 11 Body", 
      "messageID": 3, 
      "messageTitle": "New message 11 Title", 
      "photos": "The Cock photos", 
      "userID": 3, 
      "videos": "The Cock videos"
    }
  ]
}

我可以在控制台中打印JSON对象。但问题是从JSON中检索内容。我已经尝试了多种方法从JSON对象中检索值。任何帮助都是可观的。

[注意：我是Ajax的新手。请不要标记为重复。]

var res= {
  "message": [
    {
      "files": "SS", 
      "messageBody": "gOOD", 
      "messageID": 1, 
      "messageTitle": "THTH", 
      "photos": "DD", 
      "userID": 2, 
      "videos": "FF"
    }, 
    {
      "files": "", 
      "messageBody": "bla bala blaa", 
      "messageID": 2, 
      "messageTitle": "another", 
      "photos": "", 
      "userID": 3, 
      "videos": ""
    }, 
    {
      "files": "The Cock files", 
      "messageBody": "New message 11 Body", 
      "messageID": 3, 
      "messageTitle": "New message 11 Title", 
      "photos": "The Cock photos", 
      "userID": 3, 
      "videos": "The Cock videos"
    }
  ]
}

$.each(res.message, function(index,value){
console.log(value.files)
console.log(value.messageBody)
console.log(value.messageID)
$('body').append(value.files +"<br>" + value.messageBody +"<br>" + value.messageID +"<hr>");
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

试试这个方法。

这样做：

var x = {
  "message": [
    {
      "files": "SS", 
      "messageBody": "gOOD", 
      "messageID": 1, 
      "messageTitle": "THTH", 
      "photos": "DD", 
      "userID": 2, 
      "videos": "FF"
    }, 
    {
      "files": "", 
      "messageBody": "bla bala blaa", 
      "messageID": 2, 
      "messageTitle": "another", 
      "photos": "", 
      "userID": 3, 
      "videos": ""
    }, 
    {
      "files": "The Cock files", 
      "messageBody": "New message 11 Body", 
      "messageID": 3, 
      "messageTitle": "New message 11 Title", 
      "photos": "The Cock photos", 
      "userID": 3, 
      "videos": "The Cock videos"
    }
  ]
};

然后你访问你的数据，在这种情况下，就像这样：

var z = x.message[0].files; // value of z is "SS"

附加阅读：https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON

更新：在javascript中，您可以通过检查其长度来获取数组中的元素数，如本例所示：x.message.length；

因此，如果你想列出所有数据，你可以这样做：

for(var i = 0; i < x.message.length; i++) {
    var tempUl = document.createElement('ul');
    tempDiv.id = "object"+i;
    // now you can do something like this
    var tempLi = document.createElement('li');
    tempLi.innerHTML = x.message[i].files;   // or x.message[i]['files'];
    tempUl.appendChild(tempLi);
    // ... and so one ... 
    // or you can do it like this
    for(var j = 0; j < Object.keys(x.message[i]).length; j++) {
        var tempLi = document.createElement('li');
        var tempVal = Object.keys(x.message[i])[j];
        tempLi.className = tempVal;    // if you need to sort it or access them by any other way... also you can use classList.add();
        tempLi.innerHTML = x.message[i][tempVal];
        tempUl.appendChild(tempLi);
    }
}

或者类似的东西。这应该会生成未排序的列表。对不起，我试得太累了。

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