JavaScript未更新表单操作

JavaScript not updating form action

本文关键字：操作 表单 更新 JavaScript      更新时间：2023-09-26

我没有附加CSS，因为这对这个问题无关紧要，但由于某种原因，我的表单不会提交。我知道你必须指定一个操作才能提交，我在javascript中这样做，但每当我点击添加到购物车按钮时，它就会重新加载这个页面的产品。已经尝试过将addtoCart.php放入操作中，但这会导致其他错误，不会像我需要的那样带来产品id。那么，javascript没有更新我的表单操作有什么原因吗？

<body class="oneColFixCtrHdr">
<div id="container">
<form name="myform" id="myform" action="" method="post"/>
  <input type="hidden" name="PHPSESSID" value="<?php echo session_id; ?>">
  <input type="hidden" name="cartNumber" value="<?php echo $cartNumber ?>">
  <input type="hidden" name="productID" id="productID" value="">    
  <div id="header">
   <table width="760">
   <tr>
   <td width="188" rowspan="2">
    <a href="default.php"> <img  src="images/CongaMoe.jpg" width="150" height="153" alt="Conga Moe Logo" border="0"/></a>
    </td>
    <td width="361"><img src="images/homeTitle.jpg" width="343" height="152"></td>
    <td width="188">
     <a href="default.php"> <img  src="images/CongaMoe.jpg" width="150" height="153" alt="Conga Moe Logo" border="0"></a>
    </td>
    </tr>
    <tr>
    <td colspan="2" align="right">

    <a href="drums.php"><img src="images/btnCongaDrums.jpg" width="100" height="32" border="0"></a>&nbsp;&nbsp;&nbsp;<a href="products.php"><img src="images/btnBuyAConga.jpg" width="100" height="32" border="0"></a>&nbsp;&nbsp;&nbsp;<a href="viewcart.php"><img src="images/btnLookInCart.jpg" width="100" height="32" border="0"></a>&nbsp;&nbsp;&nbsp;<a href="checkout.php"><img src="images/btnPayAndGo.jpg" width="100" height="32" border="0"></a> 
    </td><td width="3"></td>
  </table>
  </div>
  <!-- end #header -->
<div id="mainContent">
<script type="text/javascript">
  function addToCart(product, formObj) {
      document.getElementById("productID").value = product;
      document.getElementById("myform").action = "addtoCart.php";
      formObj.submit;
  }
  </script>
<table>
<?php
require_once('appVars.php');
$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME)
   or die('Could not connect to MySQL server as CIS55Student, cis55 database.');
 $strQuote = chr(34);
  $query = "SELECT * FROM products_nalanirowe";
   $rs = mysqli_query($dbc, $query);
   $num_rows = mysqli_num_rows($rs);
   for ($i = 0; $i < $num_rows; $i++) {
      $row = mysqli_fetch_array($rs);
      $productID = $row['productID'];
      $productName = $row['productName'];
      $productPrice = $row['productPrice'];
      echo "<tr class='productText'>";
      echo "<td valign='top'><input type='image' name='submit' src='images/btnAddToCart.jpg' width='100' height='32' border='0' onclick'javascript:addToCart(". $strQuote . "$productID" . $strQuote . ",this.form)' ></td>"; 
      echo "<td valign='top'>". $row['productID'] . "</td>";
      echo "<td valign='top'>". $row['productName'] . "</td>";
      echo "<td valign='top'". $row['productDesc'] . "</td>";
      echo "<td valign='top'>". $row['productPrice'] . "</td>";
      echo "<td valign='top'><img src='" . IMAGEPATH . $row['productImgName'] . "' border='0'></td>";
      echo "</tr>"; 
   }

  mysqli_close($dbc);
?>
</table>
<!-- end #mainContent --></div>
  <div id="footer">
    <p><strong>&copy;Conga Moes 2010</strong></p>
  <!-- end #footer --></div>
  </form>
<!-- end #container --></div>

</body>

onclick'javascript:addToCart(". $strQuote . "$productID" . $strQuote . ",this.form)'，您没有正确分配处理程序，该formObj.submit;应该是formObj.submit();

另一个错误是

onclick'javascript:addToCart(". $strQuote . "$productID" . $strQuote . ",this.form)' ,

应读取

onclick='javascript:addToCart(". $strQuote . "$productID" . $strQuote . ",this.form)' ,
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