使用Javascript显示共享点库项

我有3个库，我想显示库项的名称。如果我只想显示一个库的项目，一切都可以，但如果我要查找两个或多个库的项，它仍然只显示一个图书馆的项目。我的代码出了什么问题？

    <p id="AInfo">library A Items</p>
    <p id="BInfo">library B Items</p>
    <p id="CInfo">library C Items</p>
    <script type="text/javascript">
        jQuery(document).ready(function(){ExecuteOrDelayUntilScriptLoaded(fill, "sp.js"); });
        var siteUrl = '/Example/test/';
        liblist = new Array("A", "B", "C"); //list of the libraries
        var i=0;
        var lib;
        function fill(){
            while (i<3){
                lib = liblist[i];
                alert(lib);
                retrieveListItemsInclude();
                i++;
            }
        }

        function retrieveListItemsInclude() {

            var clientContext = new SP.ClientContext(siteUrl);
            var oList = clientContext.get_web().get_lists().getByTitle(lib);
            var camlQuery = new SP.CamlQuery();
            camlQuery.set_viewXml('<View><RowLimit>100</RowLimit></View>');
            this.collListItem = oList.getItems(camlQuery);
            clientContext.load(collListItem, 'Include(Id, DisplayName, HasUniqueRoleAssignments)');
            clientContext.executeQueryAsync(Function.createDelegate(this, this.onQuerySucceeded), Function.createDelegate(this, this.onQueryFailed));
        }

            function onQuerySucceeded(sender, args) {
                var listItemInfo = '';
                var listItemEnumerator = collListItem.getEnumerator();            
                while (listItemEnumerator.moveNext()) {
                    var oListItem = listItemEnumerator.get_current();
                    listItemInfo += oListItem.get_displayName()+ '<br>';
                }
                var x = listItemInfo.toString();
                document.getElementById(lib+"Info").innerHTML = x;
        }

        function onQueryFailed(sender, args) {
            var x = 'Request failed. ' + args.get_message() + ''n' + args.get_stackTrace();
            document.getElementById(lib+"Info").innerHTML = x;  
        }
    </script>