PHP foreach in JavaScript
PHP foreach in JavaScript
我正在使用以下代码(JavaScript中的PHP)。foreach正在工作,当我检查控制台时,它会回显结果,但映射脚本不起作用。
var t = [];
var x = [];
var y = [];
var h = [];
<?php foreach($obj->data as $mapMarkers) {
echo "t.push('" . json_encode($mapMarkers->AreaName . "');'n";
echo "x.push(" . $mapMarkers->Longitude . ");'n";
echo "y.push(" . $mapMarkers->Latitude . ");'n";
echo "h.push('" . $mapMarkers->FullAddressBR . "');'n";
} ?>
var i = 0;
for ( item in t ) {
var m = new google.maps.Marker({
map: google_map,
animation: google.maps.Animation.DROP,
title: t[i],
position: new google.maps.LatLng(x[i],y[i]),
html: h[i]
});
google.maps.event.addListener(m, 'click', function() {
info_window.setContent(this.html);
info_window.open(google_map, this);
});
i++;
}
试试这个:
<?php foreach($obj->data as $mapMarkers) {?>
t.push(<?echo "'" . json_encode($mapMarkers->AreaName . "'" ?>));
x.push(<?echo "'" . $mapMarkers->Longitude . "'" ?>);
y.push(<?echo "'" . $mapMarkers->Latitude . "'" ?>);
h.push(<?echo "'" . $mapMarkers->FullAddressBR . "'" ?>);
<? } ?>
您应该做的是创建一个php对象(好吧,让我们把它放在一个数组*中);您回显该对象的jsonencode;那么javascript可以直接读取。
原因是您将php与javascript分离。
所以类似的东西
<?php
$my_array = array();
foreach($obj->data as $mapMarkers) {
$my_array.push(array(
't'=>$mapMarkers->AreaName,
'x'=>$mapMarkers->Longitude,
'y'=>$mapMarkers->Latitude,
'h'=>$mapMarkers->FullAddressBR
));
}
echo 'var my_data = ' . json_encode($my_array) .';';
?>
现在你们可以这样使用它:
for (i in my_data) { // notice: this is how you use for/in. The i becomes the index, not the item itself
var m = new google.maps.Marker({
map: google_map,
animation: google.maps.Animation.DROP,
title: my_data[i].t,
position: new google.maps.LatLng(my_data[i].x, my_data[i].y),
html: my_data[i].h
});
(*php不知道数组到底应该是什么。大多数php数组实际上都是对象)
解决了它!我最初的代码运行得很好,我只是把长代码转错了方向。我的坏!
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