Javascript:在数组中查找对象的索引，不知道索引，只知道对象

Javascript: Finding an object's index in an array, not knowing the index, only the object

本文关键字：索引 对象 不知道 查找 Javascript 数组      更新时间：2023-09-26

我有一个对象数组，我想删除其中一个对象。

[
  {"field":"ingredients","gte":"egg","lte":"egg"},
  {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"},
  {"field":"ingredients","gte":"hvetemel","lte":"hvetemel"}
]

我不知道我要删除的对象的索引，但我知道整个对象。即:

{"field":"ingredients","gte":"bakepulver","lte":"bakepulver"}

我需要通过它的全部内容(所有属性)找到对象的索引，而不仅仅是通过field, gte或lte。我如何找到对象的索引在数组与纯JavaScript?

您可以遍历数据，然后检查键和每个键的长度，如果它具有相同的内容。

var data = [{ "field": "ingredients", "gte": "egg", "lte": "egg" }, { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" }, { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }],
    search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
    keys = Object.keys(search),
    index = -1;
data.some(function (a, i) {
    if (Object.keys(a).length === keys.length && keys.every(function (k) { return a[k] === search[k]; })) {
        index = i;
        return true;
    }
});
console.log(index);

ES6 

var data = [{ "field": "ingredients", "gte": "egg", "lte": "egg" }, { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" }, { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }],
    search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
    keys = Object.keys(search),
    index = data.findIndex(a =>
        Object.keys(a).length === keys.length && keys.every(k => a[k] === search[k]));
console.log(index);

您可以使用Object.keys(), Array.prototype.findIndex(), Array.prototype.every()检查每个属性名称，值和.length对象属性名称是否相等。

let data = [
  {"field":"ingredients","gte":"egg","lte":"egg"},
  {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"},
  {"field":"ingredients","gte":"hvetemel","lte":"hvetemel"}
];
let props = {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"};
let keys = Object.keys(props);
let index = data.findIndex(o => keys.every(key => o[key] === props[key]) 
              && Object.keys(o).length === keys.length);
console.log(index);

根据您的进一步评论，您只需要针对这种特定情况的解决方案，其中对象由3个给定属性组成。因此，我建议使用以下ES6解决方案:

var data = [
  { "field": "ingredients", "gte": "egg", "lte": "egg" },
  { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
  { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }];
var search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" };
var index = data.findIndex(
    a => a.field == search.field && a.gte == search.gte && a.lte == search.lte);
console.log(index);

如果你没有完整的ES6支持，那么:

var data = [
  { "field": "ingredients", "gte": "egg", "lte": "egg" },
  { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" },
  { "field": "ingredients", "gte": "hvetemel", "lte": "hvetemel" }];
var search = { "field": "ingredients", "gte": "bakepulver", "lte": "bakepulver" };
var index = -1;
data.some(function (a, i) {
    if (a.field == search.field && a.gte == search.gte && a.lte == search.lte)
        return index = i, true;
});
console.log(index);

您可以使用此代码解决您的问题

var array = [
    {"field":"ingredients","gte":"egg","lte":"egg"},
    {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"},
    {"field":"ingredients","gte":"hvetemel","lte":"hvetemel"}
];
var searchObject =      
    {"field":"ingredients","gte":"bakepulver","lte":"bakepulver"};
var indexOfSearchResult;
for (var i = 0; i < array.length; i++) {
    var checkEqualBool = true;
    for (var key in array[i]) {
        if(array[i][key]!=searchObject[key]){
            checkEqualBool = false;
            break;
        }
    }
    if(checkEqualBool){
        indexOfSearchResult = i;
        break;
    }
}

我使用老方法比较对象，通过字符串化它。试着复习一下这个

var x = [{
  "field": "ingredients",
  "gte": "egg",
  "lte": "egg"
}, {
  "field": "ingredients",
  "gte": "bakepulver",
  "lte": "bakepulver"
}, {
  "field": "ingredients",
  "gte": "hvetemel",
  "lte": "hvetemel"
}];
var control = {
  "field": "ingredients",
  "gte": "bakepulver",
  "lte": "bakepulver"
};
function getIndex(arr, key) {
  var got = false,
    result = -1;
  arr.every(function(e, i) {
    if (JSON.stringify(e) === JSON.stringify(key)) {
      console.log('match found');
      result = i;
      return false;
    }
    return true;
  })
  return result;
}
console.log(getIndex(x, control));

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