排序结果在JSON变量按整数

我认为最干净的方法是将每个数据集的结果推入外部作用域变量，然后从中排序和呈现。示例如下:

var combined = [],
    completed = 0;
$(document).ready(function () {
    $("#search").keyup(function () {
        combined = [];
        completed = 0;
        $.getJSON("http://suggestqueries.google.com/complete/search?q=" + $("#search").val() + "&client=chrome&callback=?", function (data) {
            for (var key in data[1]) {
                if (data[4]["google:suggesttype"][key] == "NAVIGATION") {
                    combined.push({
                        href : data[1][key],
                        text : data[2][key],
                        score : parseInt(data[4]["google:suggestrelevance"][key],10)
                    });
                } else {
                    combined.push({
                        text : data[1][key],
                        score : parseInt(data[4]["google:suggestrelevance"][key],10)
                    });
                }
            }
            if ( ++completed == 2 ) complete();
        });
        $.getJSON("https://www.googleapis.com/freebase/v1/search?query=" + $("#search").val() + "&limit=3&encode=html&callback=?", function (data) {
            for (var key in data.result) {
                combined.push({
                    text : data.result[key].name,
                    score : parseInt(data.result[key].score,10) * 14
                });
            }
            if ( ++completed == 2 ) complete();
        });
    });
});

function complete(){
    console.log(combined);
    combined.sort(function(a,b){ return b.score - a.score; });
    var buffer = [];
    combined.forEach(function(result){
        buffer.push("<li>"+result.text+" <i>("+result.score+")</i></li>")
    })
    $("#suggest").html(buffer.join(""));
}

编辑

此解决方案没有考虑到用户可能以比API更快的速度输入的事实，API调用可能没有按顺序返回，并且没有做任何事情来限制对每个API的调用数量。要使此行为更一致(和更有效):

• 更改按键处理程序，使每次按键取消任何先前的超时，然后设置一个新的超时在一个合理的延迟(300ms似乎是一个合理的地方开始)，然后触发API调用
• 将每个API调用包装在一个立即执行的函数中，这样你就可以在每个API调用时引用全局计数器的值。每次按键都增加计数器，并且不处理来自计数器不匹配的API调用的响应

这是完整的代码，您必须将所有结果附加到一个容器中，并在.ajaxComplete事件中排序

$(document).ready(function () {
    $("#search").keyup(function () {
        $("#suggest").empty();
        $.getJSON("http://suggestqueries.google.com/complete/search?q=" + $("#search").val() + "&client=chrome&callback=?", function (data) {
            var suggestion = "";
            for (var key in data[1]) {
                if (data[4]["google:suggesttype"][key] == "NAVIGATION") {
                    suggestion += "<li><a href='" + data[1][key] + "'>" + data[2][key] + "</a> <i>(" + data[4]["google:suggestrelevance"][key] + ")</i></li>";
                } else {
                    suggestion += "<li>" + data[1][key] + " <i>(" + data[4]["google:suggestrelevance"][key] + ")</i></li>";
                }
            }
            $("#suggest").append(suggestion);
        });
        $.getJSON("https://www.googleapis.com/freebase/v1/search?query=" + $("#search").val() + "&limit=3&encode=html&callback=?", function (data) {
            var suggestion2 = "";
            for (var key in data.result) {
                suggestion2 += "<li>" + data.result[key].name + " <i>(" + data.result[key].score * 4 + ")</i></li>";
            }
            $("#suggest").append(suggestion2);
        });
        $(document).ajaxComplete(function (event, xhr, settings) {
            $("#suggest").html($("#suggest li").sort(function (a, b) {
                return (parseInt($(a).find("i").html(), 10) > parseInt($(b).find("i").html(), 10));
            }));
        });
    });
});

试一下

将前一行添加到for循环

data[4]["google:suggestrelevance"].sort();

看到演示

尝试使用单个变量

看到演示

将它们放在一起并进行排序。

代码如下:
使用promise来知道两个ajax请求都完成了。

$(document).ready(function(){
    $("#search").keyup(function(){
        var mergedData = [];
    var promise1 = $.getJSON("http://suggestqueries.google.com/complete/search?q="+$("#search").val()+"&client=chrome&callback=?",function(data){
        var suggestion="";
        console.log(data);
        var arr  = [];
        for(var i in data[1]){
        arr[i] = {value : data[1][i], rel : data[4]['google:suggestrelevance'][i]};
        }
        $.extend(mergedData,arr);
        arr.sort(function(a, b){
            return (b['rel']-a['rel']);
        });

    });
    var promise2 = $.getJSON("https://www.googleapis.com/freebase/v1/search?query="+$("#search").val()+"&limit=3&encode=html&callback=?",function(data){
        console.log('data of second request', data);
        var suggestion2="";
        var arr = [];
        for(var key in data.result){
            arr[key] = {value : data.result[key].name, rel : data.result[key].score};
        }
        $.extend(mergedData,arr);
        $("#suggest2").html(suggestion2);
    });

        $.when(promise1, promise2).then(function(){
             mergedData.sort(function(a, b){
            return (b['rel']-a['rel']);
        });
            var suggestion = '';
            for(var key in mergedData){
                suggestion+='<li>' + mergedData[key].value + ' ' + mergedData[key].rel + '</li>';
            }    
            $("#suggest").html(suggestion);
        });
    });

});

更新工作jsfiddle: http://jsfiddle.net/rEPf3/13/