字符串中的空格是允许的，但不是在第一个或最后一个位置

以下是我对这个话题的看法:

if (subject.match(/^(?='S+)(?=[a-zA-ZàáâäãåèéêëìíîïòóôöõøùúûüÿýñçčšžÀÁÂÄÃÅÈÉÊËÌÍÎÏÒÓÔÖÕØÙÚÛÜŸÝÑßÇŒÆČŠŽ∂ð ,.'-]*$).*(?='S).$/)) {
    // Successful match
}

它的意思是，至少从非空格开始。这里是条件1和条件5

然后确保整个内容仅由允许的字符组成。这是你所有的其他条件。

然后确保至少有一个非空格字符，匹配它，然后匹配结尾。

更多细节:

"
^                                                                                      # Assert position at the beginning of the string
(?=                                                                                    # Assert that the regex below can be matched, starting at this position (positive lookahead)
   'S                                                                                     # Match a single character that is a “non-whitespace character”
      +                                                                                      # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
(?=                                                                                    # Assert that the regex below can be matched, starting at this position (positive lookahead)
   [a-zA-ZàáâäãåèéêëìíîïòóôöõøùúûüÿýñçčšžÀÁÂÄÃÅÈÉÊËÌÍÎÏÒÓÔÖÕØÙÚÛÜŸÝÑßÇŒÆČŠŽ∂ð ,.'-]       # Match a single character present in the list below
                                                                                             # A character in the range between “a” and “z”
                                                                                             # A character in the range between “A” and “Z”
                                                                                             # One of the characters “àáâäãåèéêëìíîïòóôöõøùúûüÿýñçcšžÀÁÂÄÃÅÈÉÊËÌÍÎÏÒÓÔÖÕØÙÚÛÜŸÝÑßÇŒÆCŠŽ?ð ,.”
                                                                                             # The character “'”
                                                                                             # The character “-”
      *                                                                                      # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   $                                                                                      # Assert position at the end of the string (or before the line break at the end of the string, if any)
)
.                                                                                      # Match any single character that is not a line break character
   *                                                                                      # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
(?=                                                                                    # Assert that the regex below can be matched, starting at this position (positive lookahead)
   'S                                                                                     # Match a single character that is a “non-whitespace character”
)
.                                                                                      # Match any single character that is not a line break character
$                                                                                      # Assert position at the end of the string (or before the line break at the end of the string, if any)
"

您需要使用RegExp ^和$代码，它们分别指定开始和结束。

请参阅有关此操作的更多文档

希望这对你有帮助!

试试这个

^(?! )[a-zA-ZàáâäãåèéêëìíîïòóôöõøùúûüÿýñçčšžÀÁÂÄÃÅÈÉÊËÌÍÎÏÒÓÔÖÕØÙÚÛÜŸÝÑßÇŒÆČŠŽ∂ð ,.'-]*[a-zA-ZàáâäãåèéêëìíîïòóôöõøùúûüÿýñçčšžÀÁÂÄÃÅÈÉÊËÌÍÎÏÒÓÔÖÕØÙÚÛÜŸÝÑßÇŒÆČŠŽ∂ð,.'-]$

在Regexr上查看

^将模式锚定到字符串

$将模式锚定到字符串

(?! )是一个负向前看，它确保它不以空格

然后是您的字符类与*量词，意味着0或更多次。最后还是你的类，但是没有空格，这是为了确保它不会以空格结束。

很遗憾Javascript正则表达式不支持Unicode，并且不允许所有类型的字母使用'p{L}。